Mainly because having a prototype gives a very clear picture to the reader

so he doesnt have to read through all the shitcode in order to see what a class does and how he interacts with it

Good

have you stopped putting your notes into a big printf statement?

have you stopped using printf in C++?

xD

well. it doesnt teach you anything

its just that it's super hard to keep it correct and all

have you stopped using printf in C++?

https://github.com/fmtlib/fmt

https://github.com/fmtlib/fmt

No

http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2017/p0645r0.html There is also a standards proposal for this

http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2017/p0645r0.html There is also a standards proposal for this

http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2018/p0645r2.html new revision

Ah nice

And it seems like it was already reviewed by the comittee

http://www.zverovich.net/2018/06/15/iso-cpp-meeting-rapperswil.html

And it seems like it was already reviewed by the comittee

yep

No

Yes

Everything I do recently depends on this guy

lol

I like that lib

universal formats

lol >= 3k commits for that little lib

https://github.com/fmtlib/fmt

I like it

Which are affordable colleges for masters program/direct PhD in data science/machine learning/data analytics/computer science/open source?

Today I just complete a tutorial which consisted of creating a program to find the area of a circle using functions. Although the instructions already displayed how to create the program, I gained a better understanding of more functions such as if statement, cout, and return value. I also was able to compile it successfully and execute. Feelsgood.

Today I just complete a tutorial which consisted of creating a program to find the area of a circle using functions. Although the instructions already displayed how to create the program, I gained a better understanding of more functions such as if statement, cout, and return value. I also was able to compile it successfully and execute. Feelsgood.

Today I just complete a tutorial which consisted of creating a program to find the area of a circle using functions. Although the instructions already displayed how to create the program, I gained a better understanding of more functions such as if statement, cout, and return value. I also was able to compile it successfully and execute. Feelsgood.

Great now #googleit

#googleit

#googleit

http://www.fuckinggoogleit.com/

Very humorous

Can one explain friend function in c++ ?

Can one explain friend function in c++ ?

Friend functions are allowed to access protected and private members of your class.

Today I just complete a tutorial which consisted of creating a program to find the area of a circle using functions. Although the instructions already displayed how to create the program, I gained a better understanding of more functions such as if statement, cout, and return value. I also was able to compile it successfully and execute. Feelsgood.

Now give us the pastebin link and let us praise you or stone you tomatoes

Friend functions are allowed to access protected and private members of your class.

And friend injection is useful for stateful metaprogramming

On the other hand: dudes, I need help. My algo depends on a variable not being initialized. as soon as I initialize it, the algo won't work and the Neural Network's error will converge to the average

accumulator

I have double and triple and quintuple checked the algorithm

use modern header guards

you declare Questions but you never define it

use #pragma once at the top of your header

/KicKme

/KicKme

No problem.

you have to define it before using it

use #pragma once at the top of your header

I would use standard compliant guards

I would use standard compliant guards

which is #pragma once

your Problem is here class Questions; Questions Askaway; you create an object of a class, that you have not yet defined

you have to define the class in the header itself and define it's functions in a c++ file

which is #pragma once

where? paragraph?

which is #pragma once

#pragma pragma_params Implementation defined behavior is controlled by #pragma directive.

#pragma pragma_params Implementation defined behavior is controlled by #pragma directive.

Oh I see

Oh I see

so the standard compliant ones are the #ifndef a #define a #endif

right?

yes, exactly.

So I should change that in ZENeural

after i've fixed the bug with the undefined variable ;_;

Most compilers will probably recognize #pragma once but that is not defined

Most compilers will probably recognize #pragma once but that is not defined

Okay

so if I want to write a compiler and I want to add some cool dank new features to C++, i'll use pragma

a.hpp class A { public: void foo(); }; a.cpp #include "a.hpp" void A::foo() { // your code } main.cpp #include "a.hpp" int main() { A a; // create your object here a.foo(); // call your function } i woudl suggest a layout similar to the above To use your class it should be in a header file, that can be included. Only after you told your compiler how your class looks like, you can instantiate it. The implementation might go into a seperate source file, that includes that header and implements the functions. your main code includes the header, to make use of the class. It's preferable to construct the object with a minimal lifetime. So create it in the main function and use it there.

so if I want to write a compiler and I want to add some cool dank new features to C++, i'll use pragma

You would not add features to C++, you would add them to your compiler. If you want to add them to C++ yoyu should make a proposal :)

You would not add features to C++, you would add them to your compiler. If you want to add them to C++ yoyu should make a proposal :)

ahh fuck. formalism strikes again :D

ahh fuck. formalism strikes again :D

otherwise coroutines would have been already part of C++

otherwise coroutines would have been already part of C++

I wish

😢

are the C++ casts member of the stl?

reinterpret_cast <type> looks very much like a function in a standard library

but the examples I've seen don't include the stl

and the wikipedia page on operators in C++ lists them as own operators

@ollirz

are the C++ casts member of the stl?

no, they are part of the language itself

no, they are part of the language itself

ouch!

ugly ugly ugly

why?

They look like they are normal template functions

which makes C++ another candidate for the PHP evolution

imho

But I personally don't see a problem there

it doesnt preserve clearness of intent

especially when there's a stl wrapper

I think it acutally does by including the _cast prefix