someone who knows how to work with burp suite?

#define TEST() std::cerr << pSomeVar ; int main() Static const char* pSomeVar = “...”; TEST()

Set up burpsuite proxy to the browser , when your browser doing some request it will intercept

Now how can we get rid of macro in that instance ? Assuming we have this kind of usage in 1000000 places and physically we can’t modify the function signature

and your goal is?

Hi all! I have a question regarding to C I didn't declare function. Only wrote definition void Test() after main In main system found my function call to Test() and implicitly declare it for me with such signature I suppose "int Test()" Question is "Why when I try to call this function system doesn't generate ERROR cause of using void in expression" Yes in default declaration there is INT but in definition VOID

Because void mean nothing, so returning void means returning nothing

Nope. If i will change void in declaration it will generate error. We can not use void in expression like + Question is how system understands where to look for returning value IMPLICIT Declaration or Definition

Yes, because void means nothing. It has no value

you dont understand me.

You mean like void + x will give error ?

Too bad that i can not attach screen here. I mean that: If i have implicict declaration of Test() in main funct it will be int Test() But in definition I have void Test() I expect error becasuse void + x should be error. But it look to declaration not definition and in declatation there is INT and no error in result

Owww In function protoype void test() In function declaration int test() like that ?

Owww In function protoype void test() In function declaration int test() like that ?

exactly and after between them i call test() in main

Owww In function protoype void test() In function declaration int test() like that ?

why it looks INT in implicitly generate declaration no in definition where returning value void?

Because you can't print void value, so compiler implicitly change void return value, into int

I dont think so. You can not change void to int or can?. It just refers to INT in declaration somehow. And i want to know how :(

Using -E ?

What compiler are u using ?

dont know what is this for now sorry

dont know what is this for now sorry

I got error on clang main.c:7:20: error: argument type 'void' is incomplete printf("%d\n", test());

Sorry bro can you send my your code screen in direct message?

No thanks, stay on the group

but we can not send pictures here

I treated warning as error btw

yes I though so

I made it wrong myself to understand how it works. Question here is how compiler solves missmatch in returning value between implicitly created declaration and definitions with same identificator

It gives error in both clang and gcc

you dont recreate it properly then. Whatever. Thank you

Maybe you can share the code here or post long code on pastebin. Hope other member will answer your question

Maybe you can share the code here or post long code on pastebin. Hope other member will answer your question

"Enter the number : 5" 12345 23451 34512 45123 51234

are there something like generics in c?

are there something like generics in c?

#include <stdio.h> #include <conio.h> #include <limits.h> #include <float.h> #define _ printf("\n Minimum #define __ printf("\n Maximum void main() { _ short|short int|signed short|signed short int : %d",SHRT_MIN ); __ short|short int|signed short|signed short int : %d",SHRT_MAX ); _ unsigned|short|unsigned short int : %u",O); __ unsigned short|unsigned short int : %u", USHRT_MAX ); _ int|signed int : %d", INT_MIN ); __ int|signed int : %d", INT_MAX ); _ unsigned int : %u", O ); __ unsigned int : %u", UINT_MAX ); _ long|long int|signed long|signed long int : %ld", LONG.MIN ); __ long|long int|signed long|signed long int : %ld", LONG.MAX ); _ unsigned long|unsigned long int : %lu", O ); __ unsigned long|unsigned long int : %lu", ULONG.MAX ); _ float : %e", FLT MIN); __ float : %e", FLT_MAX); _ double : %e", DBLMIN); __ double : %e", DBLMAX); _ long double : %Le", LDBL_MIN); __ long double : %Le", LDBL_MAX); }

long nc; nc=0; while (getchar() != EOF) ++nc; printf("%ld\n", nc);

You sure that %ld is the code for long? long ≠ long int

do you know why it doesn't print the value of nc?

Does the while loop end ? Send EOF signal first

Does the while loop end ? Send EOF signal first

You sure that %ld is the code for long? long ≠ long int

Really ? I though long is equal to long int

I think I read long size might differ across systems

I think I read long size might differ across systems

So which one could I try?