Why don't you try it? It looks like this will print the average of the 5 numbers.

Please help me, I did not understand this passage ### If the parentheses are removed, we obtain a + b + c + d + e / 5, which evaluates incorrectly as: a + b + c + d +e/5 ##

That's basic math, division goes before addition.

//m=A+B+C+D+E/5 #include <iostream> using namespace std; int main (){ int A, B, C , D , E , sum , m; cout <<"enter the A & B & C & D & E \n"; cin >>A>>B >>C>>D>>E ; sum = A + B + C + D + E ; m=sum/5; cout <<"_____________\n"; cout <<" m = "<< m;} ......, Is that True or false 😐😐

//m=A+B+C+D+E/5 #include <iostream> using namespace std; int main (){ int A, B, C , D , E , sum , m; cout <<"enter the A & B & C & D & E \n"; cin >>A>>B >>C>>D>>E ; sum = A + B + C + D + E ; m=sum/5; cout <<"_____________\n"; cout <<" m = "<< m;} ......, Is that True or false 😐😐

How to start studying c++ for first time?

Hii

Hi

This isn't a group to say ("hi") x3 , read rules

I get an infinite loop, why?

Are you sure that your f is valid? Code looks fines except for excessive use of malloc. Do you know what values of char you're getting? Does it read the file? Did you debug the issue.

I am getting different outputs for the same code on different compilers .

You can use recursion or lots of selections to make a factorial function

I code a logic but it's printing the whole sum of each column

I am super confused if c does increment operations left to right or right to left .

So it would depend computer to computer?

Hello friends, i have a problem to solve, who will help me please 😌

how can I fix this?

#include <stdio.h> int main() { int i = 10, j = 20, k = 0; k = (++i) + (--i) + (j++); printf(" %d\n %d \n %d ", i, j, k); return 0; } /* What will be the output for this ? 10 21 41 Or 10 21 40

I am super confused if c does increment operations left to right or right to left .

First do 2 for loops for 2d array..

No need, I know that the column size is always 4 on the first one and 5 on the second one.

void print_double_array(void **array, int type, int size) { /* Write your code here */ int i; if(type == 0){ for(i = 0; i < size; i++){ printf("%.2f %.2f %.2f %.2f", array[i][0], array[i][1], array[i][2], array[i][3])); } } else if(type == 1){ for(i = 0; i < size; i++){ printf("%d %d %d %d %d", array[i][0], array[i][1], array[i][2], array[i][3], array[i][4]); } } }

You probably need to cast and dereference your pointer e.g. instead of array[i][1] do *((double*)array[i][1]))

But I'm not sure what exactly you store there

void print_double_array(void array, int type, int size) { /* Write your code here */ int i; if(type == 0){ for(i = 0; i < size; i++){ float **x = (float)array; printf("%.2f %.2f %.2f %.2f", x[i][0], x[i][1], x[i][2], x[i][3])); } } else if(type == 1){ for(i = 0; i < size; i++){ int y = (int)array; printf("%d %d %d %d %d", y[i][0], y[i][1], y[i][2], y[i][3], y[i][4]); } } }

Hello, everyone, I have got a question. During data entry via cin, memory called a buffer holds these entries until extracted into variables. Suppose I have got a single variable and given this code bit; int num; cin >> num; while (cin) { cin >> num; } cout << num; And my entries are 1, 2, f At the end of program execution, num = 0. But my expectation is after input stream enters a fail state, num = 2. So what happened????

Hello, everyone, I have got a question. During data entry via cin, memory called a buffer holds these entries until extracted into variables. Suppose I have got a single variable and given this code bit; int num; cin >> num; while (cin) { cin >> num; } cout << num; And my entries are 1, 2, f At the end of program execution, num = 0. But my expectation is after input stream enters a fail state, num = 2. So what happened????

hi guyZZZ, can i post here link to my C++ optimization educational channel ?

What's wrong with discussing C++ optimisations in this channel?

hi guyZZZ, can i post here link to my C++ optimization educational channel ?

I am not against tho, but tg bot will remove the link lol

Hello, everyone, I have got a question. During data entry via cin, memory called a buffer holds these entries until extracted into variables. Suppose I have got a single variable and given this code bit; int num; cin >> num; while (cin) { cin >> num; } cout << num; And my entries are 1, 2, f At the end of program execution, num = 0. But my expectation is after input stream enters a fail state, num = 2. So what happened????

You probably do 3 iterations, before exiting the loop, the last one reads invalid value and operator>> still needs to put something to num (probably it puts a default value but I'm not sure, need to look at the specification).

In my ide, default values of an uninitiated int variable is 0 so I guess that would be it. Thanks.