I need help in Armstrong number checker program in C using for loop... I'm asking here because following reasons: 1. Most of the solutions of this program found on Google checks only 3 digit number but I want it to check any digit number. 2. Solution found on Google are done using while loop but I am doing it with for loop. 3. I am almost done doing it, but stuck at the final point. Can anyone help me with this. Then I'll share my code. Thank you..

I resolved this problem @Correctmaninwrongplace you are right I'm trying to print elements of object by mistake..

Share your code and ask specific question.

But how is it of type void?

#include <stdio.h> int main() { //num: to store number entered by the user int num; //count: to count number of digits int count = 0; //i: for looping int i; //for calculating sum int sum = 1, sum2 = 0; //for storing individual digits int d = 1; //tcount, tnum: temporary containers for num and count's original values as it is goimg to be modified in our program int tcount, tnum; //Ask the user to input the number printf("Enter a number: "); scanf("%d", &num); //store the original value of 'num' in temporary varible i.e 'tnum' tnum = num; //Checking the number of digits in the user input for(i = 0; num != 0; i++) { num = num / 10; count = count + 1; } //reassign the original value of num to tnum as it was modified in the above loop num = tnum; tcount = count; //get the number of digits in the input, now raising the power total number to each digits to check whether it is armstrong number or not //eg: if the entered number has 3 digits, raise power 3 to each digits and add them //if it has 4 digits, then raise power 4 to all and sum them printf("Before: count: %d, Sum: %d\n\n", count, sum); for(num; num != 0; num = num / 10){ d = num % 10; for (i = 0; i < count; ++i){ sum = sum * d; printf("Sum in every loop: %d\n", sum); sum2 += sum; //sum = sum + (d * d * d); } } printf("%d \t %d\t%d\n", sum, tnum, sum2); if(tnum == sum) printf("%d is armstrong number", tnum); else printf("%d is not armstrong number", tnum); return 0; } It is not returning expected results.

the inner for can be change by just 1 line of the correct code, you have it there, so uncomment that line and delete the loop

That line only checks for 3 digit code. And I am making it to check any number of digits, so I had commented it for reference only. So, I needed another for loop to raise "count" power to the sum, which is that.

#include <stdio.h> int main() { //num: to store number entered by the user int num; //count: to count number of digits int count = 0; //i: for looping int i; //for calculating sum int sum = 1, sum2 = 0; //for storing individual digits int d = 1; //tcount, tnum: temporary containers for num and count's original values as it is goimg to be modified in our program int tcount, tnum; //Ask the user to input the number printf("Enter a number: "); scanf("%d", &num); //store the original value of 'num' in temporary varible i.e 'tnum' tnum = num; //Checking the number of digits in the user input for(i = 0; num != 0; i++) { num = num / 10; count = count + 1; } //reassign the original value of num to tnum as it was modified in the above loop num = tnum; tcount = count; //get the number of digits in the input, now raising the power total number to each digits to check whether it is armstrong number or not //eg: if the entered number has 3 digits, raise power 3 to each digits and add them //if it has 4 digits, then raise power 4 to all and sum them printf("Before: count: %d, Sum: %d\n\n", count, sum); for(num; num != 0; num = num / 10){ d = num % 10; for (i = 0; i < count; ++i){ sum = sum * d; printf("Sum in every loop: %d\n", sum); sum2 += sum; //sum = sum + (d * d * d); } } printf("%d \t %d\t%d\n", sum, tnum, sum2); if(tnum == sum) printf("%d is armstrong number", tnum); else printf("%d is not armstrong number", tnum); return 0; } It is not returning expected results.

That line only checks for 3 digit code. And I am making it to check any number of digits, so I had commented it for reference only. So, I needed another for loop to raise "count" power to the sum, which is that.

i would use pow

y=1+x+(x^2)/2!+(x^3)/3!+(x^4)/4! How this solve in C++ ? is it possible?

Of course it is possible.

Maybe available any equations converter to C++ programming language online?

Hello every body

I think you're supposed to do it yourself as you have to do it.

Or any channels?

#include <stdio.h> int main() { //num: to store number entered by the user int num; //count: to count number of digits int count = 0; //i: for looping int i; //for calculating sum int sum = 1, sum2 = 0; //for storing individual digits int d = 1; //tcount, tnum: temporary containers for num and count's original values as it is goimg to be modified in our program int tcount, tnum; //Ask the user to input the number printf("Enter a number: "); scanf("%d", &num); //store the original value of 'num' in temporary varible i.e 'tnum' tnum = num; //Checking the number of digits in the user input for(i = 0; num != 0; i++) { num = num / 10; count = count + 1; } //reassign the original value of num to tnum as it was modified in the above loop num = tnum; tcount = count; //get the number of digits in the input, now raising the power total number to each digits to check whether it is armstrong number or not //eg: if the entered number has 3 digits, raise power 3 to each digits and add them //if it has 4 digits, then raise power 4 to all and sum them printf("Before: count: %d, Sum: %d\n\n", count, sum); for(num; num != 0; num = num / 10){ d = num % 10; for (i = 0; i < count; ++i){ sum = sum * d; printf("Sum in every loop: %d\n", sum); sum2 += sum; //sum = sum + (d * d * d); } } printf("%d \t %d\t%d\n", sum, tnum, sum2); if(tnum == sum) printf("%d is armstrong number", tnum); else printf("%d is not armstrong number", tnum); return 0; } It is not returning expected results.

i would use pow

#include <stdio.h> int main() { //num: to store number entered by the user int num; //count: to count number of digits int count = 0; //i: for looping int i; //for calculating sum int sum = 0, sum2 = 0; //for storing individual digits int d = 1; //tcount, tnum: temporary containers for num and count's original values as it is goimg to be modified in our program int tcount, tnum; //Ask the user to input the number printf("Enter a number: "); scanf("%d", &num); //store the original value of 'num' in temporary varible i.e 'tnum' tnum = num; //Checking the number of digits in the user input for(i = 0; num != 0; i++) { num = num / 10; count = count + 1; } //reassign the original value of num to tnum as it was modified in the above loop num = tnum; tcount = count; //get the number of digits in the input, now raising the power total number to each digits to check whether it is armstrong number or not //eg: if the entered number has 3 digits, raise power 3 to each digits and add them //if it has 4 digits, then raise power 4 to all and sum them /* printf("Before: count: %d, Sum: %d\n\n", count, sum); for(num; num != 0; num = num / 10){ d = num % 10; for (i = 0; i < count; ++i){ sum = sum * d; printf("Sum in every loop: %d\n", sum); sum2 += sum; //sum = sum + (d * d * d); } } */ for(; num != 0; num /= 10){ // getting digits from the given number int d = num % 10; // now we need to set the power of d with count (d^count) int res = 1; for(int ii=0; ii<count; ++ii){ res *= d; } if(d != 0) sum += res; } printf("%d \t %d\t%d\n", sum, tnum, sum2); if(tnum == sum) printf("%d is armstrong number", tnum); else printf("%d is not armstrong number", tnum); return 0; }

Thank you☺️☺️☺️😍

I would suggest binary exp.

are there an implemented method ? i dont know, if he is learning, is the simplest solution

Hello guy's I have question Suppose we have an unsorted array And we want to sort it by swapping(swap by index values) But the swapping indexes should be random Example:- arr={9,8,3,2} i=some random value(less than 4) j=some random value(less than 4) if(arr[i]>arr[j]) temp=arr[i] arr[i]=arr[j] arr[j]=temp Swap until the array is sorted

Hello guy's I have question Suppose we have an unsorted array And we want to sort it by swapping(swap by index values) But the swapping indexes should be random Example:- arr={9,8,3,2} i=some random value(less than 4) j=some random value(less than 4) if(arr[i]>arr[j]) temp=arr[i] arr[i]=arr[j] arr[j]=temp Swap until the array is sorted

Hello guy's I have question Suppose we have an unsorted array And we want to sort it by swapping(swap by index values) But the swapping indexes should be random Example:- arr={9,8,3,2} i=some random value(less than 4) j=some random value(less than 4) if(arr[i]>arr[j]) temp=arr[i] arr[i]=arr[j] arr[j]=temp Swap until the array is sorted

Hello guys How I can clear char* inside?For example if I want to clear string's inside I write: string s="";

Hello guys How I can clear char* inside?For example if I want to clear string's inside I write: string s="";

Hello guys How I can clear char* inside?For example if I want to clear string's inside I write: string s="";

int main() { string str = "find longests number"; string temp_str = ""; string longest = ""; for (int i = 0; i < str.length(); i++) { if (str[i] != ' ') temp_str += str[i]; else temp_str = ""; if (longest.length()<temp_str.length()) { longest = temp_str; } } cout << longest << endl; system("pause"); return 0; }

int main() { string str = "find longests number"; string temp_str = ""; string longest = ""; for (int i = 0; i < str.length(); i++) { if (str[i] != ' ') temp_str += str[i]; else temp_str = ""; if (longest.length()<temp_str.length()) { longest = temp_str; } } cout << longest << endl; system("pause"); return 0; }

std::string works in different way with char *. In C, string is null terminated. This means: char x[] = "Hello World"; printf("%s", x); // shows "Hello World" *x = '\0'; printf("%s", x); // shows nothing, strlen(x) is also zero.

int main() { string str = "find longests number"; string temp_str = ""; string longest = ""; for (int i = 0; i < str.length(); i++) { if (str[i] != ' ') temp_str += str[i]; else temp_str = ""; if (longest.length()<temp_str.length()) { longest = temp_str; } } cout << longest << endl; system("pause"); return 0; }

int main() { string str = "find longests number"; string temp_str = ""; string longest = ""; for (int i = 0; i < str.length(); i++) { if (str[i] != ' ') temp_str += str[i]; else temp_str = ""; if (longest.length()<temp_str.length()) { longest = temp_str; } } cout << longest << endl; system("pause"); return 0; }

anyone help???

here we go

here we go

here we go

Is it possible to invoke member function for non-class type?

I think is not defined, as compiler said...

I think your screenshot does not represent your question. You should give the corresponding screenshot.

It represents the question perfectly. He wrote bullshit

_method_ was an argument.. I replaced it with order and i fixed it

Forget everything you know about python and never touch it again