Anonymous
What about-infinity
klimi
infinity is not a real number
Anonymous
I don’t mean exactly infinity. I mean from -10 to +10
Anonymous
Log(-5)
Joesph
For negative no.s
Anonymous
Okay
Tokin
Btw so far no errors in the girlfriend package?
Anonymous
You mean auto log(-x)
Tom
log(0)=1????? log(1)=0
Joesph
Auto x = no.
Auto y = exp(x);
Tokin
Some santa just hacked my telegram..
Tokin
The telegram name atop has changed
Roxifλsz 🇱🇹
:^)
Tokin
😅
youness
thank you
youness
where is this message please?
Anonymous
Void main()
{
Int k=8,m=7;
K<m?k++:m=m+1;
Printf("%d",k);
}
Can anybody tell y we got complile time error in dis quest..
Mat
Anonymous
Which error?
Actually I didn't execute it..I found dis on some website nd d ans is compile time error dats d reason y i asked it..
Mat
Write in a readable way
Mat
Anonymous
Void main()
{
Int k=8,m=7;
K<m?k++:m=m+1;
Printf("%d",k);
}
Can anybody tell y we got complile time error in dis quest..
I thing you should not add commas between 8 and m=7 it should be semicolon
Anonymous
Void main()
{
Int k=8,m=7;
K<m?k++:m=m+1;
Printf("%d",k);
}
Can anybody tell y we got complile time error in dis quest..
Simultaneous declaration of variable is not allowed if I am right
Mat
I thing you should not add commas between 8 and m=7 it should be semicolon
That part isn't wrong
Mat
I don't even know if it's C or Cpp
Anonymous
(Initial values of a=1,b=2,c=1)
c += (-c) ? a : b;
How d final value of c would be 2 in dis question..??
Tokin
If the expression is true then the value of c will be a otherwise it will be b
Tokin
Now anything other than 0 is 1
Tokin
I mean 1 is considered to be true and 0 is false
Tokin
If the value of expression is anything other than 0, it will be considered it's true
Bhaskar
This is the error
Bhaskar
It should be either m++ or m==m+1
Bhaskar
The error you'll get when compiling is "lvalue required as left operand of assaignment"
ekansh
Happy new year
Marián
printf("%s", "Happy new year!");
Marián
printf_s*
we should be safe 😁
Anonymous
Happy new year peeps
Zues
Happy New Year everyone
Anonymous
Anyone have an idea how to delete a check dat file Written in C++
I_Interface
Anyone have an idea how to delete a check dat file Written in C++
You mean extension of file or code inside ?
I_Interface
Anyone have an idea how to delete a check dat file Written in C++
Delete from where ? Would you ask correctly ?
Anonymous
Delete from where ? Would you ask correctly ?
Do you want me to send you a file and check it out?
I_Interface
Do you want me to send you a file and check it out?
I don't need it. I want to understand about what check do you mean ?
Anonymous
I don't need it. I want to understand about what check do you mean ?
When I change or edit a file name and run a game, I'm stuck on the loading screen When I delete a game update file it works great I checked an update file via hex tool and found checksum, check, and checkpoints in paths and file names I want how to delete a check in an update file
I_Interface
When I change or edit a file name and run a game, I'm stuck on the loading screen When I delete a game update file it works great I checked an update file via hex tool and found checksum, check, and checkpoints in paths and file names I want how to delete a check in an update file
Do you have a source code of the game with check ?
Anonymous
Do you have a source code of the game with check ?
No. only an update file can read string in hex editor or ida pro
Bello
Happy new year 🎅⛄❄🎉🎈🎅⛄❄🎉🎈🎅⛄❄🎉🎈
Anonymous
No. only an update file can read string in hex editor or ida pro
Just Delete CRC codes from an update file or create a file in C and give it paths and offsets And address After you finish merging a file with an update file, C will make Bypass
Anonymous
Anonymous
how can I get it ?
This is a difficult method for you But there is a very easy way You said you could read strings in an update file with hex editor All you have to do is change the name of a file in an update An example of this is you'll find a path pc/game/data/zax.dat Change zax.dat to zax1.dat, then save. Then go to game files to the same path you will find a file, change its name to zax1.dat  The game will work This will disable check
Anonymous
Keep this in mind Perhaps in the coming days, game developers will use a more difficult method, which is They will make some game read files from an update file They will use compress, reduce the size and encode an update file You will not be able to do anything I advise you to return to the normal situation and not to violate their laws
Brainiac
David
Hallo
Anonymous
Anonymous
Happy New year everyone
shreyas
/notes
shreyas
/get cbook
shreyas
/get howtoprogram
shreyas
/get freeprogrammingbooks
Anonymous
How to find max 2 condition in sql
Anonymous
https://youtu.be/hNHjpZsVYTE
Giri
Hello friends
sam
hy
sam
mat
sam
Anonymous
#include<stdio.h>
#define MAN(x, y) ((x)>(y)) ? (x):(y);
int main()
{
    int i=10, j=5, k=0;
    k = MAN(++i, j++);
    printf("%d, %d, %dn", i, j, k);
    return 0;
How d ans of dis question will be 12, 6,12??
}
Ashish
#include<stdio.h>
#define MAN(x, y) ((x)>(y)) ? (x):(y);
int main()
{
    int i=10, j=5, k=0;
    k = MAN(++i, j++);
    printf("%d, %d, %dn", i, j, k);
    return 0;
How d ans of dis question will be 12, 6,12??
}
because of the macro you have defined
before execution, MAN will be replaced with the whole defination
#include<stdio.h>
#define MAN(x, y) (x)>(y)?(x):(y);
int main()
{
int i=10, j=5, k=0;
k = MAN(++i, j++);
// This line will look like
// k = (++i)>(j++)?(++i):(j++);
printf("%d, %d, %dn", i, j, k);
return 0;
}
and when you'll execute this
You'll get 12, 6, 12
Mat
You should tell him why i is incremented by 2 and j by 1
Mat
#include<stdio.h>
#define MAN(x, y) ((x)>(y)) ? (x):(y);
int main()
{
    int i=10, j=5, k=0;
    k = MAN(++i, j++);
    printf("%d, %d, %dn", i, j, k);
    return 0;
How d ans of dis question will be 12, 6,12??
}
Do you know how the ternary operator works?