strcmp returns 0 for equal strings, yes? then if (strcmp(str1, str2)) {...} else {...} should go to the else block if str1 and str2 are equal.

exactly but isn't it more logically if that worked for the if block? the condition is true so don't execute the else?

so the condition is true when it's not equal to 0, instead for a function like strcmp it's true when it's equal to 0

it true when it's not zero, and false if it is zero

if the strings matches (true) it will return 0

alright writing it like this it's better I think

strcmp returns a value that represents the difference between the first characters encountered that are different in the two strings (0 if there is no difference). It has nothing to do with the logic 0 or false.

I agree, I'm not a C programmer, but for me this == 0 is a clear sign that you check for strings equality

strcmp returns a value that represents the difference between the first characters encountered that are different in the two strings (0 if there is no difference). It has nothing to do with the logic 0 or false.

No, it is not required to return difference. Implementation which returns only -1, 0 or 1 is perfectly valid

It does make some sense though. I assume the non-zero values are mostly used for sorting purposes anyway.

#include <stdio.h> #include <stdlib.h> int main (void){ int value, remainderArray[20], i, count =0, digits, reversingValues[20], j; printf("How many Digits will your value contain?: "); scanf("%d", &digits); printf("Input your value: "); scanf("%d", &value); for (i = 0; i<digits; i++){ remainderArray[i] = value % 10; value = value /10; count++; } for (i=digits-1, j=0; i>=0; i--, j++) reversingValues[j] = remainderArray[i]; for (i=0; i<count; i++){ if(reversingValues[i] == 1){ printf("one "); } else if(reversingValues[i] == 2){ printf("Two "); } else if (reversingValues[i] == 3){ printf("Three "); } else if (reversingValues[i] == 4){ printf("Four "); } else if (reversingValues[i] == 5){ printf("Five "); } else if (reversingValues[i] == 6){ printf("Six "); } else if (reversingValues[i] == 7){ printf("Seven "); } else if (reversingValues[i] == 8){ printf("Eight "); }else if (reversingValues[i] == 9){ printf("Nine "); }else if (reversingValues[i] == 0){ printf("Zero "); } // printf("\nvalue= %d \n", reversingValues[i]); } printf("\n\n"); return 0; }

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What's with this?

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It's what you see🤔

I meant do u want the output or ur running into some errors?

Go read it I explained all please.

Errors while printing, the data became inconsistent with my current approach

Hi please can anyone help with this? Write a program that takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English. So, if the user types in 932, the program should display nine three two Remember to display “zero” if the user types in just a 0.

Hi please can anyone help with this? Write a program that takes an integer keyed in from the terminal and extracts and displays each digit of the integer in English. So, if the user types in 932, the program should display nine three two Remember to display “zero” if the user types in just a 0.

This right?

Yes

Here's what I've done so far but it isn't exactly what was needed. Because I couldn't do it well😔😔

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Mine runs well but it isn't exactly what was ask.

Okay i am trying to run it. ..

Just remember it's a c program not cpp. Thanks

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If you can, then thank you

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