https://codingcompetitions.withgoogle.com/codejam/round/0000000000051705/0000000000088231 Heres the question

Can anyone talk about the preciseness of sqrtl() function?

@ollirz

- there is a leading space before case - "c" in case should be capital - wrong logic e.g. 41 returns 20 20

Thats right i think cuz they say they gonna send an integer check

- there is a leading space before case - "c" in case should be capital - wrong logic e.g. 41 returns 20 20

A n B i.e. 20 n 20 not containing 4

Been told to use long int

Check if a number is perfect square. Is this the right way? Or I'm thinking of using Binary search. long long p = sqrtl(K); if(p*p==K){ cout<<"YES"; } else{ cout<<"NO"; }

Umm so now i should change ll to double n check it again?

20.5 20.5 would what we get

you should output any A and B, so that A + B = N and neither A nor B contains a 4. So for 41 you can output 39 and 2 or 20 and 21

Yeah 20.5 doesnt caontain a four

you should output any A and B, so that A + B = N and neither A nor B contains a 4. So for 41 you can output 39 and 2 or 20 and 21

They said at the end of question A n B can be same

They said at the end of question A n B can be same

it's not an integer though

Umm so okay for 41 A n B should be such that there ints

A and B shall always be integral values - just read the task again

Yeah I'll... Thanks for all the help

Good Luck :)

Check if a number is perfect square. Is this the right way? Or I'm thinking of using Binary search. long long p = sqrtl(K); if(p*p==K){ cout<<"YES"; } else{ cout<<"NO"; }

long long

0 ) the func must be void print_reverse(const char *s) 1) s is not necessary a string literal. It may be any ASCIIZ string. 2) t = t - 1; MUST BE --t; or nobody could believe you are a C programmer. 3) last puts better to do with "\n" All the rest is ok

//program to check graph is bipartite or not #include<bits/stdc++.h> using namespace std; class Graph{ int v; list<int> *l; public: Graph(int V){ v=V; l=new list<int>[v]; } void addEdge(int v,int u,bool bidir=true){ l[v].push_back(u); if(bidir) l[u].push_back(v); } bool isBipartite(int src){ queue<int> q; q.push(src); int *color=new int[v]; for(auto i=0;i<v;i++){ color[i]=-1; } color[src]=0; bool ans=true; while(!q.empty()&&ans){ int u=q.front(); q.pop(); for(auto v:l[u]){ if(color[v]=-1){ color[v]=1-color[u]; q.push(v); } else if(color[v]==color[u]){ return false; break; }} } return true; }}; int main(){ Graph g(4); g.addEdge(0,1); g.addEdge(2,0); g.addEdge(1,3);g.addEdge(2,3); // g.addEdge(1,2); if(g.isBipartite(0)){ cout<<"yes"; } else{ cout<<"no"; } return 0; }

It checks if current iterator is further than begin (or equal), that is, we have some chars to print

void print_reverse(char *s){ size_t len = strlen(s); // holds the value of the length of the string literal char *t = s + len - 1; // s is a pointer to the first value in the s string literal //s + len moves it to the null character // 0 1 2 3 4 5 \n // minus 1 moves it to the last character in the string while(t >= s){ //so at this point t starts at the end of the string printf("%c", *t); //then it prints the t //then subtract 1, or pointer math , so moves it // one memory address before the last //until there is no more letters in left t = t - 1 ; } puts(""); }

hi, i have specific question...

@Maestrowscki10

is there any penalty, if enum {} is nested inside a c++ class

Yo must have counter for doing that bro

instead of using of static const

thats what i thought, i wouldnt even use a while loop , i would use a for loop but it works

is there any penalty, if enum {} is nested inside a c++ class

but its the question in the book

The books yo give me? Right

whats a ASCIIZ string

buffer of char containing sequence of symbols of type "char" and ended by '\0' symbol

😂😂 calm let's go OT

No penalty Write your question in ONE message

I have few constants, and normally i delcare them as static const, inside a class in the header file, but there must be initialiser statement in the .cpp file as well, by using enum inside the class to define some constants, i can omit the initialiser part and the cpp file at all... is there difference in the way compiler will use these numbers... code lenght, memory usage? that's i mean for penalty

buffer of char containing sequence of symbols of type "char" and ended by '\0' symbol

If your constants ARE connected to each other by meaning and semantics, you use them as enumerators and you definitely need to use enum, especially enum class If your constants ARE NOT connected in any way, you can declare your constants inline — initilize them in-place — and you don't need to initilize them in cpp file

when comparing strings like char somestring[20] = “hello” and char anotherstring[40] = “long” and you do like an while loop like if(somestring > anotherstring) are we comparing if they have the same character or length or something

you mean that inline static const int Parameter123 = 123; is allowed inside class definition? so i can reference this externally as ClassName::Parameter123, if it is public?

You canNOT compare char[] with those operators

I want to know why we have to put *p='\0' here