Anonymous
The challenge seems weird
Anonymous
Selfmodifying Code
+==============+
Language: C, C++
Time: 20 minutes
+==============+
Make a function that changes its own code!
+==============+
Solutions and challenge ideas to @maxi_robot
Anonymous
challenge I got
Anonymous
Language:c, c++
Talula
Selfmodifying Code
+==============+
Language: C, C++
Time: 20 minutes
+==============+
Make a function that changes its own code!
+==============+
Solutions and challenge ideas to @maxi_robot
You can modify the source file and recompile it… but I don’t think that’ll is needed.
Artöm
In a group I found a programming challenge to write a self modifying function..
My guess is
void f() {
// shit
((char*)f)[dunno] = some_num;
}
Artöm
But you need to know assembly
Anonymous
Selfmodifying Code
+==============+
Language: C, C++
Time: 20 minutes
+==============+
Make a function that changes its own code!
+==============+
Solutions and challenge ideas to @maxi_robot
Bad task and challenge
Don't use it ever again
Artöm
And understand exactly how codegen works
Anonymous
My guess is
void f() {
// shit
((char*)f)[dunno] = some_num;
}
I am unable to understand can u explain what have you written actually I am new to programming
Anonymous
Anonymous
And stop doing these challenges
Anonymous
My guess is
void f() {
// shit
((char*)f)[dunno] = some_num;
}
It's total UB that will cause segmentation fault, i think
Anonymous
Artöm
It's total UB that will cause segmentation fault, i think
It defenitely is, no segfault with enough care
Anonymous
Can you people suggest me a group where I will get good programming challenges?
Anonymous
Anonymous
HackerRank
Anonymous
Ok thanks definitely I will work there
Khan
#include <stdio.h>
int main(){
for (int angka = 0;angka < 501; angka++){
printf("Angake Ke %d\n,",angka);
}
}
why the for is error?
Ilya
Dima
What the hell
Khan
'for'loop initial declaration are only allowed in C99 mode
Khan
what that's mean?
yoav
the news only difference between c and cpp is that cpp is OOP?
Ilya
'for'loop initial declaration are only allowed in C99 mode
You use C language compiler, not C++
Dima
'for'loop initial declaration are only allowed in C99 mode
int i;
for (i = 0; i < 100; i++)
Anonymous
the news only difference between c and cpp is that cpp is OOP?
C++ is more type-safe
It has templates and metaprogramming
Ilya
the news only difference between c and cpp is that cpp is OOP?
No, there are many many differences, lots of.
Anonymous
It has a lot of features that C does not have and never will
Ilya
'for'loop initial declaration are only allowed in C99 mode
Use C++ compiler or switch C compiler to later ANSI standard mode (I don't know how)
Khan
i still can't run it
Ilya
what is type safe
In two words , C++ is stricter language than plain C /
Checks more problems at compile time.
.json
Hello
Khan
i can't run it on C compailer but i can run it on C++,if i want to run it on C compailer waht should i do?
Artöm
Artöm
How do you compile?
Khan
i can run it right now
Khan
thanks guys
Anonymous
I have 😁
eren
Hii
Olanrewaju O.
hy
I_Interface
Anonymous
Well hello
Anonymous
Can anyone help me with my code
Anonymous
https://pastebin.com/NbE4hGJ2?fbclid=IwAR1udSuZY6z9Ztr22SgpYCnUPmAXkTVmbBZQhgs6BJUSND31IxRvzGSGXVI
This is codejam qualification round code
Anonymous
Output is the same they're demanding
Anonymous
Waiting for step 5 to be executed
Anonymous
Any $x developer?
Sachin
//program to check graph is bipartite or not
#include<bits/stdc++.h>
using namespace std;
class Graph{
int v;
list<int> *l;
public:
Graph(int V){
v=V;
l=new list<int>[v];
}
void addEdge(int v,int u,bool bidir=true){
l[v].push_back(u);
if(bidir) l[u].push_back(v);
}
bool isBipartite(int src){
queue<int> q;
q.push(src);
int *color=new int[v];
for(auto i=0;i<v;i++){
color[i]=-1;
}
color[src]=0;
bool ans=true;
while(!q.empty()&&ans){
int u=q.front();
q.pop();
for(auto v:l[u]){
if(color[v]=-1){
color[v]=1-color[u];
q.push(v);
}
else if(color[v]==color[u]){
return false;
break;
}}
}
return true;
}};
int main(){
Graph g(4);
g.addEdge(0,1); g.addEdge(2,0);
g.addEdge(1,3);g.addEdge(2,3); // g.addEdge(1,2);
if(g.isBipartite(0)){
cout<<"yes";
}
else{ cout<<"no";
}
return 0;
}
Anonymous
Anonymous
Did I break the rules?
Haahh looks like u had to post a pastebin than posting actual code smh
Anonymous
Check if a number is perfect square.
Is this the right way? Or I'm thinking of using Binary search.
long long p = sqrtl(K);
if(p*p==K){
cout<<"YES";
}
else{
cout<<"NO";
}
Anonymous
Is the above one the safest and the most correct way to do that?
olli
Sites not acceptin my code
So it's probably not what they demand?
What's the question? And what's the output of the judge?
Is it actually that hard to ask a question that can be answered?!
Anonymous
Imma post the que right here
Anonymous
https://codingcompetitions.withgoogle.com/codejam/round/0000000000051705/0000000000088231
Heres the question
Muhammad
Guys How many languages Computer science includes?
Muhammad
ex.C programming
Muhammad
and how about other languages