Download from another source

2013 repo?

Means?

what are you even trying to achieve?

for which IDE?

you can download codeblocks with mingw gcc

That's what I have done But further packages aren't downloading There is a connection problem with it or other...don't know right now

That's what I have done But further packages aren't downloading There is a connection problem with it or other...don't know right now

Use vpn

How?

if that doesnt work, post it here

for the installation of MinGW the packages are must and for that it needs to connect with the sorceforge(it is by defuault) and now again i am facing the same issue....

Yes I have tried

That means the files are missing, search for the files on google directly and download those, frankly I have never used codeblock to know about this problem but just giving you tips I think @K11M1 can give you better solution.

That's what I have done But further packages aren't downloading There is a connection problem with it or other...don't know right now

I had used codeblockz out of the box before without an internet connection, must be some version that comes with the compilers

hello i want channel for MS ACCESS and VBA projects and asks,answers

/report troll and ot

/report troll and ot

Eh, don't be so sensitive on that, it's just a meme

https://stackoverflow.com/questions/29028808/is-there-an-offline-mingw-installer

My issue has resolved 😊 Thank you so much!👍

🖐️

My issue has resolved 😊 Thank you so much!👍

hii

hii

#include <iostream> int main() { int in; std::cin » in; if (in % 3 == 0 && in % 5 == 0) { std::cout « "I wont steal homeworks\n"; } return 0; }

can you write in simple c Language please

#include <iostream> int main() { int in; std::cin » in; if (in % 3 == 0 && in % 5 == 0) { std::cout « "I wont steal homeworks\n"; } return 0; }

OK thanks

Let’s decrease warn limit to 1

#include <iostream> int main() { int in; std::cin » in; if (in % 3 == 0 && in % 5 == 0) { std::cout « "I wont steal homeworks\n"; } return 0; }

There is a mistake

&& must be ||

&& must be ||

3 AND 5.

Let’s decrease warn limit to 1

Think over again

lets decrease it to 0

3 is divideble by 3, and so does 5

3 is divideble by 3, and so does 5

3 is divideble by 3, and so does 5

if with double type - yes, if with integer type - no.