Try calling func as fun(&arr1);
Then it makes sense to use double pointers
In this way
using namespace std;
void fun(int **sac)
{
**sac[1][0]=4;
}
int main()
{
int arr1[2][2]={{1,2},{0,5}};
fun(&arr1);
cout<<arr1[1][0];
}
Harsh
Harsh
Anonymous
Dima
Lol
Anonymous
11 11 C:\s\2d using pointer.cpp [Error] cannot convert 'int (*)[2][2]' to 'int**' for argument '1' to 'void fun(int**)'
Андрей
why pass 2d array using pointer to pointer if you can use pointer ???
Андрей
wtf?!?!?!
Harsh
why pass 2d array using pointer to pointer if you can use pointer ???
That's why &arr1 😂
Андрей
you can't pass 2d array, it's not like
int **arr = new int[rows];
for (...) arr[i] = new int[cols];
Anonymous
what's the task ?
task is simple create n*n in main function and do a sum of there dialgonals but the condition is use a function to insert elements in the matrix using pointer size should be passed explicitly
Anonymous
fun(arr,size)
Anonymous
bot dimensions are of same size
Anonymous
suppose i created in int main()
{
int arr[2][2];
Harsh
task is simple create n*n in main function and do a sum of there dialgonals but the condition is use a function to insert elements in the matrix using pointer size should be passed explicitly
Then why you want it **?
Using *arr1[] on &arr1 is best I say
Anonymous
then i need to pass fun(arr,2)
Anonymous
Then why you want it **?
Using *arr1[] on &arr1 is best I say
i dont want the question is that what i am supposed to do
Harsh
then i need to pass fun(arr,2)
In this way
using namespace std;
void fun(int *sac)
{
*sac[1][0]=4;
}
int main()
{
int arr1[2][2]={{1,2},{0,5}};
fun(&arr1);
cout<<arr1[1][0];
}
Anonymous
Anonymous
check plzz
Dima
Dima
Stop begging
Dima
hit or miss
Accel
Anonymous
What errors does it give u?
11 11 C:\s\2d using pointer.cpp [Error] cannot convert 'int (*)[2][2]' to 'int*' for argument '1' to 'void fun(int*)'
Anonymous
Anonymous
Anonymous
oh god..i have forgotten how to access it in case of 2d array
Stanislav
Anonymous
in 2d array *(*sac+1)+j)
Till
Harsh
arr1[1][0] == *(*(arr1+1)+0)
Harsh
Anonymous
Anonymous
Nameful
also, I would recommend installing gcc/g++ locally
Anonymous
send error
annot convert ‘int (*)[2]’ to ‘int**’ for argument ‘1’ to ‘void fun(int**)’
fun(arr1);
^
Anonymous
tried on gcc as well
Anonymous
#include<iostream>
using namespace std;
void fun(int **sac)
{
sac[1][0]=4;
}
int main()
{
int arr1[2][2]={{1,2},{0,5}};
fun(arr1);
cout<<arr1[1][0];
}
Anonymous
Anonymous
showing error
what about when you just print the value at sac[1][0]? does that show error too?
Anonymous
#include<iostream>
using namespace std;
void fun(int sac[][2]){
sac[1][0]=4;
}
int main(){
int arr1[2][2]={{1,2},{0,5}};
fun(arr1);
cout<<arr1[1][0];
}
only this works
I_Interface
int fun(int arr[2][2]) {
return arr[1][0] = 5;
}
int arr[2][2] = { {1,2}, {3,4} };
fun(arr);
std::cout << arr[1][0];
Anonymous
Anonymous
that is the question
Anonymous
Love to be here... After all God and nature are all programmers too
Dima
What
Dima
Anonymous
:)