OFC he can use C for education for first time, but its too simple language

int *a = (int *) new int[10];

There is no need to explicitly cast

int *a = realloc(NULL, 10*sizeof(int)); a[9] = 228; int *a = realloc(a, 20*sizeof(int)); printf("%d", a[9]);

Hey any linux users?

int *a = (int *) new int[10];

Mine better 😜

Malloc returns void pointer so you have to cast

Its only for C++ code i think

int *a = realloc(NULL, 10*sizeof(int)); a[9] = 228; int *a = realloc(a, 20*sizeof(int)); printf("%d", a[9]);

No in c++ when you use new then you haven't cast it because we already mentioned it's type

He talk about malloc, not a NEW

But in C++ you need cast, lol

For new??

new is not a C-lang

Lol I know

Lol, and what are you doing? You talk about C

Give up that topic.....

Malloc in C++ is unnecessary, you need avoid it

I know I am familiar with the new :)

But topic about C

why this is not appending

ak->a[4] = 67;

Why do you write it???

just exploring something

It is really bad

(struct array ** ak) so that can we use this and ak.a[4]=67;

Just delete this code

Just delete this code

Just delete this code

Explore how std::vector works

bro i want to learn about **pointer

#include<iostream> using namespace std; void fun(int **sac) { } int main() { int arr1[2][2]={{1,2},{0,5}}; fun(**arr1); cout<<arr1[1][1]; }

i want to make this 0 as 4 using pointer

#include<array> template <std::size_t N, std::size_t M> void func(const std::array<int, N, M>& array) { array[1][0] = 4; }

[In reply to Rextester] #include<iostream> void fun(int (&arr)[2][2]) { arr[1][0] = 4; } int main() { int arr1[2][2]={{1,2},{0,5}}; fun(arr1); std::cout << arr1[1][0]; }

using pointer

using pointer

in my code change & to *

bro in place of[][] i want to use **