@programminginc - страница 1505

BinaryByter

I'm not home and i refuse to code on phone

MᏫᎻᎯᎷᎷᎬᎠ

Brand new member

Tushar

i have been trying to write a program on 2-D array to print in a circular path. just like this picture.__________________ int main(void) { int m=5, n=m, w=0; int arr[m][n]; int i, k = 0, l = 0; m--, n--; while(k <= m && l <= n) { // Print the row left to right for(i = l; i <= n; ++i) { w=w+1; printf("%d ", w); } // Print the column top to bottom k++; for(i = k; i <= m; ++i) { w=w+1; printf("%d ", w); } // Print the row right to left n--; if(m >= k) { for(i = n; i >= l; --i) { w=w+1; printf("%d ", w); } m--; } // Print the column bottom to top for(i = m; i >= k; --i) { w=w+1; printf("%d ", w); } l++; } printf("\n"); return 0; } ________________________________________ i tried thiscode. but it instead gives this: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 :http://www.studyalgorithms.com/array/print-a-matrix-in-

for your image the below program is correct...

Tushar

#include<stdio.h> int main() { int a[5][5]={0},i,j,low=0,top=4,n=1; for(i=0;i<3;i++,low++,top--) { for(j=low;j<=top;j++,n++) a[i][j]=n; for(j=low+1;j<=top;j++,n++) a[j][top]=n; for(j=top-1;j>=low;j--,n++) a[top][j]=n; for(j=top-1;j>low;j--,n++) a[j][low]=n; } printf("\t\t\t\tPerfect Square\n"); for(i=0;i<5;i++) { printf("\n\n\t"); for(j=0;j<5;j++) { printf("%6d",a[i][j]); } } return 0; }

Tushar

Check it

uncle

Check it

thanks ver much.. i please can you try an odd dimension.... like (4,5) (3,6) (7,3).............

Tushar

thanks ver much.. i please can you try an odd dimension.... like (4,5) (3,6) (7,3).............

I didn't understand

Tushar

Give me the series...

Sanket

Hey guys !! Can you give me some real life example of oop except the car and person example...

Farhan

Hey guys !! Can you give me some real life example of oop except the car and person example...

Human body and it parts

Sanket

Yeah bro other than this

Sanket

I need something different example as I am going for interview.

Tushar

An architect will have the blueprints for a house. Those blueprints will be plans that explain exactly what properties the house will have and how they are all laid out. However it is just the blueprint, you can't live in it. Builders will look at the blueprints and use those blueprints to make a physical house. They can use the same blueprint to make as many houses as they want....each house will have the same layout and properties. Each house can accommodate it's own families...so one house might have the Smiths live in it, one house might have the Jones live in it. The blueprint is the class...the house is the object. The people living in the house are data stored in the object's properties.

uncle

I didn't understand

like for 5x4 is something like this; 1 2 3 4 14 15 16 5 13 20 17 6 12 19 18 7 11 10 9 8

Tushar

Okay... wait..

Anonymous

An architect will have the blueprints for a house. Those blueprints will be plans that explain exactly what properties the house will have and how they are all laid out. However it is just the blueprint, you can't live in it. Builders will look at the blueprints and use those blueprints to make a physical house. They can use the same blueprint to make as many houses as they want....each house will have the same layout and properties. Each house can accommodate it's own families...so one house might have the Smiths live in it, one house might have the Jones live in it. The blueprint is the class...the house is the object. The people living in the house are data stored in the object's properties.

You explained so well 👌.

Tushar

#include <stdio.h> const int MAX = 100; void spiralFill(int m, int n, int a[][MAX]) { int val = 1; int k = 0, l = 0; while (k < m && l < n) { for (int i = l; i < n; ++i) a[k][i] = val++; k++; for (int i = k; i < m; ++i) a[i][n-1] = val++; n--; if (k < m) { for (int i = n-1; i >= l; --i) a[m-1][i] = val++; m--; } if (l < n) { for (int i = m-1; i >= k; --i) a[i][l] = val++; l++; } } } int main() { int m = 10, n = 5; int a[MAX][MAX]; spiralFill(m, n, a); for (int i=0; i<m; i++) { for (int j=0; j<n; j++) printf("%d\t",a[i][j]); printf("\n"); } return 0; } m --> no. of rows n --> no. of columns

Tushar

like for 5x4 is something like this; 1 2 3 4 14 15 16 5 13 20 17 6 12 19 18 7 11 10 9 8

check it.

uncle

check it.

Tushar

Any more questions..

Dima

What do you need

Dima

no assignments

Anonymous

Hello, I am stuck with my C homework and I just want to understand what should I do. Homework about the converting C++ code into C code there are header files and source files. If any one is willing to help can you write me via gmail (ihurata123@gmail.com) or you can give your mail addresses. I really just want to understand which path should I follow. I can explain better if anyone send me mail. I will be greatful if you help. Thank you and have good day to everyone.

Mihail

Hello, I am stuck with my C homework and I just want to understand what should I do. Homework about the converting C++ code into C code there are header files and source files. If any one is willing to help can you write me via gmail (ihurata123@gmail.com) or you can give your mail addresses. I really just want to understand which path should I follow. I can explain better if anyone send me mail. I will be greatful if you help. Thank you and have good day to everyone.

we could help you here, if you better describe your issue

uncle

Any more questions..

no.. thanks verymcuh. i'm just trying to use functions.. but its not a problem

Mihail

what do you mean by "Homework about the converting C++ code into C"?

Mihail

converting C++ to C isn't possible

uncle

Hello, I am stuck with my C homework and I just want to understand what should I do. Homework about the converting C++ code into C code there are header files and source files. If any one is willing to help can you write me via gmail (ihurata123@gmail.com) or you can give your mail addresses. I really just want to understand which path should I follow. I can explain better if anyone send me mail. I will be greatful if you help. Thank you and have good day to everyone.