How long does it take to master C++? Hi Im a high school student that is considering being a programmator, since Im only 15 I still have some time to learn C++ until I start university, so my question is how long does it take to develop a skill level of C++ that you can be a programmator as a job. Sorry for bad English. https://redd.it/bpdfwu @r_cpp

I'd say this is Maxi if not (Sorry for the English)

no

Why would they ban you?

Me too but I'm still here?

is it possible to join multiples loop into one without having i+j+z I mean only one var at the end joining loops for (int i = 33; i <= 47; i++) std::cout << (char)i; for (int j = 58; j <= 64; j++) std::cout << (char)j; for (int z = 91; z <= 96; z++) std::cout << (char)z;

What?

just a simple question , why do I always get 45 from return value? int Common::digits() { int digits = 0; for (int i = 0; i <= 9; i++) { digits += i; } return digits; }

just a simple question , why do I always get 45 from return value? int Common::digits() { int digits = 0; for (int i = 0; i <= 9; i++) { digits += i; } return digits; }

I just want to store it in the variable and return it , but how can I ?

I mean I want to loop from 0 to 9 without sum , but I want to store it in the digit var to return it

anyway you question is not clear enough

Return what? You can only return a single value out of a call. You can call some function in the loop if you want to do some action for each value. Or you can make an std::vector to accumulate and return all the values. Or you can use std::function if you want to make a generic "for each" function and parametrize the call with some behavoior

int Common::digits() { int digits = 0; for (int i = 0; i <= 9; i++) { digits += i; } return digits; } I got my function like this , but however if in my main std::cout << reverse.digits(); then my output it should 0123456789 ,but it return the sum

how can I fix to display 0 to 9?

how can I fix to display 0 to 9?

so I should need to return as a string even if I am dealing with numbers

so I should need to return as a string even if I am dealing with numbers

it return me ascii not numbers std::string Common::digits() { std::string digits; for (int i = 0; i <= 9; i++) { digits += i; } return digits; } std::cout << reverse.digits();

Use a stringstream

Create a stringstream, add digits to it with the "<<" operator and then call .str() on the stringstream to get the string

it return me ascii not numbers std::string Common::digits() { std::string digits; for (int i = 0; i <= 9; i++) { digits += i; } return digits; } std::cout << reverse.digits();

hey guys I have an array of int datatype, now I want to increase each element of array by 1 how can I do that? I asked this because I'd like to avoid using loop

We can use recursion

Recursion is a waste of resources in that case

Also now I understand that there is no other way to do that also

Or what, Red?

And also have enough grammar and syntax errors for me not to understand it without parsing it twice

alternatively, use a better parsing aplroach

How to do the problem

Rose is in a coma