Especially this part: The syntax of the declaration for a variable mimics the syntax of expressions in which the variable might appear.

Just don't understand it.

Especially this part: The syntax of the declaration for a variable mimics the syntax of expressions in which the variable might appear.

U don't need to, forget that line.

U don't need to, forget that line.

You're right, but I'm curious about it

I have

They're just telling u type comes before variable/function name in declaration

You're right, but I'm curious about it

Honestly, if u've been using - Pointers - Variables - Functions ... forget about that line, nothing to be worried about.

Ok, thanks 😒

Ok, thanks 😒

No problem, your charge is $200

Pay or get banned

tbh, you didn't teach me that. BTW, I give you flowers in return 😊🌷🌷

Lol

I have more beautiful flowers for you if answer my questions

@viferga

did you solve it?

I have more beautiful flowers for you if answer my questions

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How can we swap two variables without using a third variable

How can we swap two variables without using a third variable

xor

int x= x+y; int y=x-y; int x=x-y; This worked ..but if any of u have another solution let me see

int x= x+y; int y=x-y; int x=x-y; This worked ..but if any of u have another solution let me see

this may overflow, xor not

It didn't

It didn't

ok

Try it

https://stackoverflow.com/questions/10549155/why-swap-dont-use-xor-operation-in-c

Ok

Thanks for dat

this may overflow, xor not

doesn rlly matter

cuz its all mod 0x1000000...

using a temporary variable will use registers on the cpu, and it will be incredible faster and safer in comparison to the alternatives

But processor are so fast today that it doesn't matter

ok

did you solve it?

Hi, I can't understand it word by word.

How can a variable appear in an expression

How can a variable appear in an expression

int x=5,y; y=x;

It's simply an assignment

this may overflow, xor not

xor not work with double and Is more slow on x64

xor not work with double and Is more slow on x64

it does

Just typecast

I have xor working with pointers too

it does

No, can't with double

Hi, would you please explain this passage to me?

is double *dp; double atof(char*); clearer?

did you solve it?

Yes, now it's solved

tbh, you didn't teach me that. BTW, I give you flowers in return 😊🌷🌷

I don't know about u but we don't eat flowers in here. And tbh, I told u what to and not to worry about

is double *dp; double atof(char*); clearer?

Error

is double *dp; double atof(char*); clearer?

double *dp; double atof(char*);

No, can't with double

cant you typecast to like int_64 or smt

is double *dp; double atof(char*); clearer?

No idea

double *dp; double atof(char*);

oops forgot doulbe

yea

functions are just pointers

No idea

What is a pointer?

#define swap(A,B)({__auto_type __c__=(A);\ (A)=(B);\ (B)=__c__;})

Oh no

hi

What is a pointer?

a finger that points to a place in ram

a finger that points to a place in ram

Does it have to be RAM tho

I don't know about u but we don't eat flowers in here. And tbh, I told u what to and not to worry about

Seems Russian don't believe in folk medicine

What is a pointer?

A variable that contains the address of another variable

Does it have to be RAM tho

hm

Seems Russian don't believe in folk medicine

Rose flowers, is what u eat. Reason why u look like one

A variable that contains the address of another variable

👍

A variable that contains the address of another variable

not necessarily of another variables

A variable that contains the address of another variable

What's a variable

It is really just a address

What's a variable

what is a program

And is pointer a variable

It is really just a address

So why could we assign a value to it

Rose flowers, is what u eat. Reason why u look like one

😂

So why could we assign a value to it

Value or Address?

What's a variable

A group or groups of cells on memory that can hold a value.

Value or Address?

He said a pointer is just an address, and I said, how could we assign a value to an address.

A group or groups of cells on memory that can hold a value.

Or simply a named object. An object is a region of memory with a type.

He said a pointer is just an address, and I said, how could we assign a value to an address.

Sorry, I meant to say Value or Address

True

Sorry, I meant to say Value or Address

Neither, it's a variable with an address to another variable

Neither, it's a variable with an address to another variable

*it's an address to other region of memory

*it's an address to other region of memory

An*

So what's it to do with the original question

Especially this part: The syntax of the declaration for a variable mimics the syntax of expressions in which the variable might appear.

Nothing, just to waste your time.

😶