@programminginc - страница 1259

Mihail

With '\0'

Mihail

Because it's printing 30 random chars I think

Mihail

So just stringf[t] = '\0'; after the for

Gianmarco

so for {....} stringf[t] = '\0';

Mihail

Yes

Gianmarco

It worked!

Mihail

Nice

Mihail

Idk why I didn't think of that earlier tho

Mihail

I'm too used to std::string I guess

BinaryByter

probably because you didn't have the full picture

BinaryByter

its really hard helping people who don't give you context

BinaryByter

(to be fair, gianmarco did do all he could)

Mihail

Well you could've known that was wrong with just the function

BinaryByter

but its hard to read into others peoples code

Mihail

But yeah seeing it in such a way made it more clear

BinaryByter

C Ïê÷ D :tû E Ïê÷

this issues could - under no circumstance - happen due to a missing \0 btw

Mihail

this issues could - under no circumstance - happen due to a missing \0 btw

It did tho

Mihail

Because he just initialized a buffer of 30 bytes(chars)

BinaryByter

No

Mihail

And modified that

BinaryByter

notice how the 3 first bytes ARE set

Mihail

No

Why?

BinaryByter

void crypt(char* string, char* stringf) { int t = strlen(string); for (int i = 0; i < t; i++) { stringf[i] = string[i] + t; } }

in this loop

Mihail

in this loop

No

BinaryByter

his error implies that there are special chars in between C D and E

Mihail

That's the length of string

Mihail

Not stringf

Mihail

They aren't necessarily the same

Mihail

And scanf terminated the input one for him

BinaryByter

Well yes

Mihail

So the for only ran 3 times

BinaryByter

anyway, whatever

Gianmarco

i tried to use the function for print into a file

Mihail

anyway, whatever

Oh now I see what you're talking about

Gianmarco

but i have this printed

Gianmarco

C /Ôm D :tû E /Ôm

Mihail

Idk why that happened

Gianmarco

Oh wrong .exe

Gianmarco

my bad

Gianmarco

it works!!

Mihail

Nice

Mihail

Got confused for a bit

Anonymous

Code

Mihail

Code

No

Mihail

We aren't here to do your homework

Mihail

Or assignment

Mihail

Also that's way beyond simple

BinaryByter

Also that's way beyond simple

^

Gianmarco

Honestly i thought that i could copy ONLY the string that input and it wouldnt autofill

Mihail

You could modify the input one if you want

Mihail

So all the modified variables aren't necessary

Mihail

Unless you need them later on that is

Gianmarco

Thanks for the help

MᏫᎻᎯᎷᎷᎬᎠ

If rvalue can't appears in the left hand of the assignment Then Why this expression is valid: int&& r = 1;

Dima

If rvalue can't appears in the left hand of the assignment Then Why this expression is valid: int&& r = 1;

loool

MᏫᎻᎯᎷᎷᎬᎠ

loool

Don't mock my dumbass xD

BinaryByter

we don't

Dima

int&& = 1;

BinaryByter

its just that those are pretty ridiculous things to ask xD

BinaryByter

If rvalue can't appears in the left hand of the assignment Then Why this expression is valid: int&& r = 1;

why wouldn't this be valid?

BinaryByter

why is int&& r an rvalue?

BinaryByter

Like... I wouldn't call it one

MᏫᎻᎯᎷᎷᎬᎠ

why is int&& r an rvalue?

it isn't ?🤔

MᏫᎻᎯᎷᎷᎬᎠ

Then..

MᏫᎻᎯᎷᎷᎬᎠ

In the move constructor

MᏫᎻᎯᎷᎷᎬᎠ

int&&

MᏫᎻᎯᎷᎷᎬᎠ

What?!!

BinaryByter

what is int** ?

MᏫᎻᎯᎷᎷᎬᎠ

what is int** ?

Pointer to pointer

BinaryByter

yes

BinaryByter

what is int&& ?

MᏫᎻᎯᎷᎷᎬᎠ

You mean reference to reference?

BinaryByter

yes

MᏫᎻᎯᎷᎷᎬᎠ

yes

So as a parameter it's not a reference to reference

MᏫᎻᎯᎷᎷᎬᎠ

+

MᏫᎻᎯᎷᎷᎬᎠ

Why would reference to reference can be initialized to a literal?

BinaryByter

if you make it const

MᏫᎻᎯᎷᎷᎬᎠ

if you make it const

I didn't and it worked

BinaryByter

show me them codes

MᏫᎻᎯᎷᎷᎬᎠ

I didn't and it worked

Even I could change the value