@programminginc - страница 1230

Anonymous

opengl makes 3D objects but not realistic enough

Anonymous

👍

klimi

opengl makes 3D objects but not realistic enough

Lol

klimi

Then use Ray tracking

klimi

You can go see blender

klimi

And play with it

Anonymous

how can I use blender in my own soft its completely different software not for c++ as I know

klimi

You can't

Anonymous

You can't

thats why I should learn how to make my own

klimi

Ok

klimi

Good luck

Anonymous

well even if admin couldn't help then...

Anonymous

but thanks in any case

klimi

I'm not a programmer

klimi

I'm just an admin

Anonymous

I see

Anonymous

Hi

klimi

Hi

Anonymous

Hi guys i couldn't find any function to clean the screen in console application

Anonymous

Hi guys i couldn't find any function to clean the screen in console application

Clrscr()

Anonymous

conio isn't working bro

Anonymous

getch() is the only function that i am using from conio

MᏫᎻᎯᎷᎷᎬᎠ

Hi guys i couldn't find any function to clean the screen in console application

Use system

MᏫᎻᎯᎷᎷᎬᎠ

system (command-name)

Anonymous

How did you use the conio header file? #include<conio.h> Or #include <conio>

Anonymous

How did you use the conio header file? #include<conio.h> Or #include <conio>

conio.h

Anonymous

You can use system (cls)

Anonymous

Dude just cheak it it is cls in caps i guess

MᏫᎻᎯᎷᎷᎬᎠ

How did you use the conio header file? #include<conio.h> Or #include <conio>

include cstdlib Then use system (command) function to clear the screen, where command is: 1-"cls" if you are using Windows 2-"clear" if you are using linux

Anonymous

include cstdlib Then use system (command) function to clear the screen, where command is: 1-"cls" if you are using Windows 2-"clear" if you are using linux

Thnx.

Anonymous

Hii

MᏫᎻᎯᎷᎷᎬᎠ

Hi

Anonymous

You can use system (cls)

system isn't working too No error message, but no result too

NandhU

need fibonnaci series with limit

Ludovic 'Archivist'

opengl makes 3D objects but not realistic enough

The realism depends on the shaders used

olli

Mutexes use the thread_id for locking so that a thread cannot self-deadlock

>> "cannot deadlock" That's not true for std::mutex, it applies to std::recursive_mutex though A program may deadlock if the thread that owns a mutex object calls lock() on that object http://eel.is/c++draft/thread.mutex.requirements.mutex#thread.mutex.class-4

Ибраги́м

https://www.youtube.com/watch?v=lM-21GySlso

olli

Environment mapping does help a lot for realism especially in static scenes.

Parra

Hi guys i couldn't find any function to clean the screen in console application

this is very platform dependant

BinaryByter

the c++ standard needs to include that just to make the indians shut up

BinaryByter

btw: I wrote a library which allows that, iirc

BinaryByter

COLORINK I think

BinaryByter

wait not it doesnt di that :(

Anonymous

In "Head first C" book they said that * The C language doesn't support strings out of the box* but its supports printf("hello world"); this prints hello world, its a string then how it support?

BinaryByter

ist a const char []

Anonymous

const char?

Parra

In "Head first C" book they said that * The C language doesn't support strings out of the box* but its supports printf("hello world"); this prints hello world, its a string then how it support?

it's an array of char, like if you have an array of int

BinaryByter

const char?

condt char []

Anonymous

it's an array of char, like if you have an array of int

then can i access a string like array char name[] = "john"; printf("%s", name[0]);

Victor

then can i access a string like array char name[] = "john"; printf("%s", name[0]);

%c

Anonymous

%c

thanks, it works. I can access. :-)

Anonymous

what differences between those two name[0]&name[0]

Dima

wat

klimi

/kick @Chlid I'm so angry

Anonymous

code int main() { char name[10]; printf("Enter your name: "); scanf("%s", name); printf("is this one %c \n",name[0]); printf("is this one %c \n",name[1]); printf("is this two %c \n",name[2]); printf("is this three %c \n",name[3]); printf("is this four %c \n",name[4]); printf("is this five %c \n",name[5]); printf("is this six %c \n",name[6]); printf("full char %s \n",name); scanf("%s", name); return 0; }output Enter your name: loren is this one l is this one o is this two r is this three e is this four n is this five is this six Ç full char lorenQ: why there is empty in name[5]: ?

Ludovic 'Archivist'

>> "cannot deadlock" That's not true for std::mutex, it applies to std::recursive_mutex though A program may deadlock if the thread that owns a mutex object calls lock() on that object http://eel.is/c++draft/thread.mutex.requirements.mutex#thread.mutex.class-4

That is theory, in practice mutex on all libraries I have tested lock using their thread_id and noop same thread multilocking

Dmitry

code int main() { char name[10]; printf("Enter your name: "); scanf("%s", name); printf("is this one %c \n",name[0]); printf("is this one %c \n",name[1]); printf("is this two %c \n",name[2]); printf("is this three %c \n",name[3]); printf("is this four %c \n",name[4]); printf("is this five %c \n",name[5]); printf("is this six %c \n",name[6]); printf("full char %s \n",name); scanf("%s", name); return 0; }output Enter your name: loren is this one l is this one o is this two r is this three e is this four n is this five is this six Ç full char lorenQ: why there is empty in name[5]: ?

zero terminate byte '\0' from zero terminated string.

Anonymous

zero terminate byte '\0' from zero terminated string.

👍

Nameful

code int main() { char name[10]; printf("Enter your name: "); scanf("%s", name); printf("is this one %c \n",name[0]); printf("is this one %c \n",name[1]); printf("is this two %c \n",name[2]); printf("is this three %c \n",name[3]); printf("is this four %c \n",name[4]); printf("is this five %c \n",name[5]); printf("is this six %c \n",name[6]); printf("full char %s \n",name); scanf("%s", name); return 0; }output Enter your name: loren is this one l is this one o is this two r is this three e is this four n is this five is this six Ç full char lorenQ: why there is empty in name[5]: ?

Without that "empty", printf() and similar does not know where the string ends

Nameful

You can try setting it to something else and printing the string

olli

That is theory, in practice mutex on all libraries I have tested lock using their thread_id and noop same thread multilocking

That's what the standard says. Sure implementations have not to deadlock but relying on not dead locking is stupid.

Parra

That is theory, in practice mutex on all libraries I have tested lock using their thread_id and noop same thread multilocking

what do you mean?

olli

That is theory, in practice mutex on all libraries I have tested lock using their thread_id and noop same thread multilocking

furthermore #include <mutex> #include <cstdio> int main() { std::mutex mutex; printf("L0\n"); mutex.lock(); printf("L1\n"); mutex.lock(); printf("L2\n"); } deadlocks with GCC/libstdc++. and that's why std::recursive_mutex exists. Had several discussions about that at my previous company...

Krunal

Where

Krunal

I got it all

MᏫᎻᎯᎷᎷᎬᎠ

What?

Krunal

What is file handling in C++

BinaryByter

read the name aloud 10 times

Mihail

read the name aloud 10 times