Anonymous

What does (:) mean in this for loop ?

Anonymous

And what is the the output?

Roxifλsz 🇱🇹

What does (:) mean in this for loop ?

It loops trough x and puts every value into y. The output is CPP!

Anonymous

It loops trough x and puts every value into y. The output is CPP!

But the application has different answer

Roxifλsz 🇱🇹

But the application has different answer

Oh shit :D I missed the part that all the cases have no break; statements

Anonymous

Oh shit :D I missed the part that all the cases have no break; statements

Can you go by details please?

Anonymous

Can you go by details please?

Starts with x=1

Anonymous

Prints CPP!

Anonymous

As no breaks

Anonymous

Nothing at 2. Not PP! at 3 .. P! at 7 and ! at 8

Anonymous

So CPP!PP!P!!

Anonymous

I need to know where we can use for(i:j)? What is this used for? And how this could be used?

Anonymous

Hello I'm a new student of computer science and I have a subject by the name of Programing I don't know any thing about it 😔 Please help me

Roxifλsz 🇱🇹

I need to know where we can use for(i:j)? What is this used for? And how this could be used?

When you need to iterate over all elements of an array, vector, etc.

Anonymous

When you need to iterate over all elements of an array, vector, etc.

So what will be value of i and j initially? Can you please provide a sample code?

Anonymous

Hello I'm a new student of computer science and I have a subject by the name of Programing I don't know any thing about it 😔 Please help me

Learn

Anonymous

Ok Thanks

Anonymous

So CPP!PP!P!!

But why case 1 printed once , case 2 twice , case 3 thrice and case 4 four times ? I didn't get it

Anonymous

But why case 1 printed once , case 2 twice , case 3 thrice and case 4 four times ? I didn't get it

Nope

Anonymous

Read what I wrote with patience

Anonymous

But the application has different answer

The elements in that array are from one to 10 But in switch case cases are for 1,3,7,8 ie case 1://something case 3: case 7: case 8: when y is passed as parameter to switch value stored y will be 1. So one switch case will match ie: "C" will be printed but there are no break statement after it so it prints letters from other cases as well. Until now CPP! will be printed. Now when y is incremented value of y will be 2 so there will be no match in switch case, then again when y will be incremented value of y will be 3 so again it will print anything written in case 3. As there are no break statements it will keep on printing letters until last case is not done. So now the letters CPP!PP! will be printed and this will be followed till end

Anonymous

The elements in that array are from one to 10 But in switch case cases are for 1,3,7,8 ie case 1://something case 3: case 7: case 8: when y is passed as parameter to switch value stored y will be 1. So one switch case will match ie: "C" will be printed but there are no break statement after it so it prints letters from other cases as well. Until now CPP! will be printed. Now when y is incremented value of y will be 2 so there will be no match in switch case, then again when y will be incremented value of y will be 3 so again it will print anything written in case 3. As there are no break statements it will keep on printing letters until last case is not done. So now the letters CPP!PP! will be printed and this will be followed till end

Guys let me know if I left something or I am wrong. I will appreciate it. Thanks

Anonymous

/c_gcc@rextester_bot

Anonymous

/c_gcc@rextester_bot

Ok, give me some C_gcc code to execute

Anonymous

Ok, give me some C_gcc code to execute

void main() { int a; printf("%d",a); }

Anonymous

void main() { int a; printf("%d",a); }

How to execute the code I tried with a sample but nothing happened!

Anonymous

/vb@rextester_bot

Anonymous

/about@rextester_bot

Anonymous

/vb@rextester_bot

Ok, give me some Vb code to execute Changed your mind? /cancel

Anonymous

Created by @GingerPlusPlus, powered by rextester.com.

Anonymous

/cancel@rextester_bot

Anonymous

/cancel@rextester_bot

Cancelled

Anonymous

/cpp_gcc@rextester_bot

Anonymous

/cpp_gcc@rextester_bot

Ok, give me some Cpp_gcc code to execute

Anonymous

Ok, give me some Cpp_gcc code to execute

#include<iostream> Using namespace std; Int main (){ cout<<"hi"; return 0; }

Anonymous

/cpp_clang@rextester_bot

Anonymous

/cpp_clang@rextester_bot

Ok, give me some Cpp_clang code to execute Send it as text, or pass a file

Anonymous

Ok, give me some Cpp_clang code to execute Send it as text, or pass a file

#include<iostream> Using namespace std; Int main (){ cout<<"hi"; return 0; }

Anonymous

The elements in that array are from one to 10 But in switch case cases are for 1,3,7,8 ie case 1://something case 3: case 7: case 8: when y is passed as parameter to switch value stored y will be 1. So one switch case will match ie: "C" will be printed but there are no break statement after it so it prints letters from other cases as well. Until now CPP! will be printed. Now when y is incremented value of y will be 2 so there will be no match in switch case, then again when y will be incremented value of y will be 3 so again it will print anything written in case 3. As there are no break statements it will keep on printing letters until last case is not done. So now the letters CPP!PP! will be printed and this will be followed till end

Got it , thank you 🙏🏻

Anonymous

Is this you?

Anonymous

/ban soft porn

Anonymous

one is call by value and one is call by reference

Mr. COwO2 Preis

On (pc) you pass the value of pc into the function On (&pc) you pass the adress where the value is saved to the functiom

Mr. COwO2 Preis

yes

Mr. COwO2 Preis

Welcome

Anonymous

basically, in call by value .. the value of the argument is copied and execution is done on the copied value, hence no chnage in the original value. But in call by reference, the address is copied instead so all changes are made on the original value, it gets altered in this case.

M.Azam

Digital 24 hours clock😍

M.Azam

Anonymous

i dont get what you mean

Anonymous

struct *pc as an argument?

Anonymous

struct isnt a data type right?

Anonymous

struct isnt a data type right?

It is

Anonymous

i mean can you use it the way he is doing? never seen it that way

Anonymous

struct x and than x *pc is possible .. but sturct * pc ?

Anonymous

If you have Struct Pc pc being pc an instance of your struct Pc and want a pointer to the struct when you call your function you pass &pc and in the prototype yo write struct Pc *pc

Anonymous

I'm not quite sure about the prototype bc I always use typedef

Anonymous

Typedef struct Pc pc{ ... ... }Pc;

Anonymous

And create a variable like this: Pc pc;

Anonymous

but see what he did

Anonymous

function (struct* pc)

Anonymous

talking about the function declaration here