ok but why the position is in hex,but not bin or other?

the computer only knows bin numbers right?

yes

but why it is in hex?

that question is like 'why can my screen show me images if everythinf the computer krows are numbers'

i have the same question

printf converts the value tho ascii characters before printing them

i have the same question

your computer isn't showing you numbers. its converting them in order for your screen to understand those numbers

ok i see

Maybe think of it like

'why do you understand english even though its not your native language?'

i have the same question

thank you anyway

😄

Sure

i have the same question

All information, not only image but sound too, it's " splitted" to digital units. In the case of characters, there is the Ascii table (basic 255 chars) so 2^8=256, that's how you can store a character on a 8bits register. (I'm a native Spanish speaker, sorry if it's hard to read but I'm trying to pass my knowledge with you all)

Even when the information its in fact stored in binary form, according to the kind of information it's convenient to manipulate it on other numeric system

Even when the information its in fact stored in binary form, according to the kind of information it's convenient to manipulate it on other numeric system

sir may i ask you a question?

sir may i ask you a question?

Sure

what will output in this code

#include <stdio.h> int main(void){ int a = 1; a = a++; a=a++; printf("%d",a); }

it makes me confused

just remeber X++ will first assign the value and then increase it and ++X wiil first increse the value then assign it

yes,but then second what is the value of the second" a=a++"

i thought it is 2

but it is 1

see, during first a++ first value of a is assigned 1 and then incresed by 1 , so a is now 2

during second a++ initially value of a is assigned 2 and then incresed by 1 , so a is now 3

yes i think so but the compiler says it is 1

that is why during printting a is 3

it ia 1 in my computer

that is why during printting a is 3

have you run this code ?

if not , run it , it is not 3 ,it is 1!

that's why i think its strange

i ran the code and it is fine

It's undefined behavior, so the compiler is free to do what it wants.

output is 3

Hence you can experience different results on different compilers

It's undefined behavior, so the compiler is free to do what it wants.

why so?

Because the standard says so - in an expression variables may be updated at most once between sequence points. (side effect on scalar is unsequenced relative to other side effect on same scalar object) (C and C++17) for an int i and int a[3] and function void f(int, int): f(i, ++i); and a[i] = ++i; are also UB

it seems make sence

most of the online C compilers are giving 1 as output

while my standard gnu gcc is showing output as 3

Because the standard says so - in an expression variables may be updated at most once between sequence points. (side effect on scalar is unsequenced relative to other side effect on same scalar object) (C and C++17) for an int i and int a[3] and function void f(int, int): f(i, ++i); and a[i] = ++i; are also UB

👍

Because the standard says so - in an expression variables may be updated at most once between sequence points. (side effect on scalar is unsequenced relative to other side effect on same scalar object) (C and C++17) for an int i and int a[3] and function void f(int, int): f(i, ++i); and a[i] = ++i; are also UB

Hello guys

Any Indian in the house

Ok

Let us c++

Because the standard says so - in an expression variables may be updated at most once between sequence points. (side effect on scalar is unsequenced relative to other side effect on same scalar object) (C and C++17) for an int i and int a[3] and function void f(int, int): f(i, ++i); and a[i] = ++i; are also UB

It seems that, in C++17, it's not UB any longer.

It seems that, in C++17, it's not UB any longer.

Why?

Why?

'cause the standard well-defines things like func(i, ++i), in C++17.

Where?

Anyway, in real productive environment, one who writes this kind of codes is about to be smashed.

Where?

see eval_order page in cppreference: https://en.cppreference.com/w/cpp/language/eval_order

That is, in C++17, some new sequenced-before rules are added to define the behavior of compilers and program compiled.

it makes me confused

Well, it'll not just confuse you, but will confuse anyone else. Hence, from my engineering experience, self-increment/self-decrement operators (++i, i++, --i, i--) should only be used as a single expression. This is not a restrict rule from C++ standard, but just a rule from experience. Following this rule, self-increment/self-decrement operators will have clear meaning and will never confuse anyone who is reading the snippet of code. #include <stdio.h> int main(void){ int a = 1; a++; a++; printf("%d",a); } Forget the discussion about evaluation order in C++ standards above, and just remember that you writing codes for human reading, not for maching optimizing. The later thing is the work of compiler — trust your compiler, it'll do enough optimization for your program.

(in almost all cases)

(in almost all cases)

i think it's great,thank you

Such an awesome group of developers!!!

Thanks for creating this chat!!!

Cplusplus for Professionals.

#cppbook

https://www.geometrictools.com/Documentation/IntersectionOfCylinders.pdf So this states that - A better alternative to a cylinder is a capsule, the set of points a specified distance from a line segment. But isnt the end of a capsule curved instead of sharp like a cylinder? If so how would using a capsule be an alternative or maybe could somehow check if the intersection is at the end of a capsule and call it not a intersection? Basically im running a simulation with like hundreds of cylinders so got to optimise as much as possible

tfw when hardest part of the sim is finding when 2 particles collide

anyone can tell me how can i add members in my group with username

anyone can tell me how can i add members in my group with username

#googleit

what is this?

i need one for duckduckgo

www.fuckingduckduckgoit.com

aww

Please i need help with CARE 2X installation

Please i need help with CARE 2X installation

#googleit

Please i need help with CARE 2X installation

Let me 🔎 Google that for you: 🔎 care 2x installation

i need one for duckduckgo

Let me 🦆 DuckDuckGo that for you: 🔎

Let me 🔎 Google that for you: 🔎 care 2x installation

Let me check

oh, a new googleit response

ah, nah, it isn't