@programminginc - страница 725

Mat

Second case i'd always use an array First case i'd use a vector if i don't care about speed but i'd like to not have size problems or have some sort of optimization about the memory usage (I don't know how much optimization however) or an array if i can estimate an upper bound and i'm able to occupy that amount of memory all the time i'll have that array

Mat

Is it wrong?

Anonymous

i=7, j=8, k=9; printf("%d", i-7 && j++ <k); printf("%d %d %d", i, j, k);

Anonymous

What will be the output?

糕糕

I'm a software engineer with 6 years of industry experience (most in Java & Python). Recently, I got a new job that requires me to learn C++. I just started doing some Leetcode practice problems. Wondering may I get some help in code review if possible? Want to make sure the C++ code I wrote is up to industry standard. I'm happy to help on Java / python in exchange. Thank you very much!

糕糕

Those are my code for leetcode question 427 and 538. It seems I'm too new here to post external links, sorry for the inconvience.

klimi

I think about a situation where you don't know how much you'll need vs a situation where you know more or less how much you need

0-255

klimi

Those are my code for leetcode question 427 and 538. It seems I'm too new here to post external links, sorry for the inconvience.

https://leetcode.com/problems/construct-quad-tree/

糕糕

Thank you Klimi!

klimi

No worries

klimi

Anything for a cute kitty

Anonymous

What do you think on SICP? Is it worth reading today?

Anonymous

Explain your motivations

j

https://gist.github.com/rexto/08351900294f1b082f2081c04419e80f

j

help me pls

j

i dont get why it does not compile

j

im passing the array as an argument

j

but i must bedoing sth wrong

j

okay, solved

Anonymous

i=7, j=8, k=9; printf("%d", i-7 && j++ <k); printf("%d %d %d", i, j, k);

Nobody knows this ?

Mr. Mahesh

#cpp

Mr. Mahesh

#cppbook

Anonymous

Thanks

Anonymous

Hey guys

Anonymous

Which IDE did you used

Anonymous

For those extremely large project

olli

What will be the output?

Tried running it?

Ak47

i=7, j=8, k=9; printf("%d", i-7 && j++ <k); printf("%d %d %d", i, j, k);

For 1st printf= 1 For 2nd one 0,9,9

olli

For 1st printf= 1 For 2nd one 0,9,9

probably not

Abdul

how to calculate the number of days for a year to determine leap years based on the number of days for one year ...

olli

how to calculate the number of days for a year to determine leap years based on the number of days for one year ...

Calculate the number of days [...] based on the number of days?

Abdul

Calculate the number of days [...] based on the number of days?

counting days for one year

Abdul

to determine leap years

Anonymous

For 1st printf= 1 For 2nd one 0,9,9

That is what I thought but first print is 0

olli

counting days for one year

Count where from? What information will be given to your function?

Anonymous

How is that possible

olli

That is what I thought but first print is 0

Of course, why should it be one?

Anonymous

How

Anonymous

Can you explain please

olli

Can you explain please

7-7 && true is false. Since the left side is false the statement can not be true. Therefore the right expression will not be evaluated. Hence the statement has not side effect and the values remain unchanged. To cite The && operator groups left-to-right. The operands are both contextually converted to bool. The result is true if both operands are true and falseotherwise. Unlike &, && guarantees left-to-right evaluation: the second operand is not evaluated if the first operand is false. The result is a bool. If the second expression is evaluated, every value computation and side effect associated with the first expression is sequenced before every value computation and side effect associated with the second expression [expr.log.and]

Anonymous

7 -7 && j++ is 0, 0<k true, so 1

Anonymous

That is how I think

Anonymous

7-7 && true is false. Since the left side is false the statement can not be true. Therefore the right expression will not be evaluated. Hence the statement has not side effect and the values remain unchanged. To cite The && operator groups left-to-right. The operands are both contextually converted to bool. The result is true if both operands are true and falseotherwise. Unlike &, && guarantees left-to-right evaluation: the second operand is not evaluated if the first operand is false. The result is a bool. If the second expression is evaluated, every value computation and side effect associated with the first expression is sequenced before every value computation and side effect associated with the second expression [expr.log.and]

Thank you so much

olli

Thank you so much

No worries :)

Ak47

That is what I thought but first print is 0