/get 0_to_show_item_use"#item"

/get findprojects

/saved

Yes, i think

Ty

Now the notes make complete sense.. Admin, please add a point on "notes usage" in the pinned message. Thank you.

Hi

I want learn c++who help me personally

#findprojects

Please

Please

No one will personally teach you. Just try something and when you have a problem come here describe your issue and we'll help you

#howtoask

whooo my message is pinned :P

No one will personally teach you. Just try something and when you have a problem come here describe your issue and we'll help you

+1, as long as you're contructive in your question-asking we will gladly help.

whooo my message is pinned :P

I'm sorry but is that a tidepod in your profile picture?

😂 no lol

NEM logo

that is hand-drawn

Sorry but it looks like a tidepod

I guess I kind of see it, lol. funny

Hello

Hi

Anyone knows about C++ boost library?!

Anyone knows about C++ boost library?!

I know nothing

Anyone knows about C++ boost library?!

Never used it but yes

I've heard of it but yeah I know nothing about it

Never used it but yes

Please send article link or any reference

Please send article link or any reference

YOU JUST ASKED ME TO GOOGLE FOR YOU

I don't know you

But i can google for you

10€/search

Is that okay?

Is that okay?

No

I will search it

Why not?

Okay

@bo0tzz

Hi

/notes

#cpp

None posted how to use notes. Here is the short tutorial: To get info from notes, have to use /get "keyword_from_list"

No need to get

Just #

#learn

Exactly

Lol

Hello ma boys

Hello ma boys

Hellau

int var; int * pointer = &var; *pointer = 20; delete [] pointer; Int var; var = 20; Someone can tellme what is the diference of this two things?

Nah im not a human, im DETROIT: BECOME A HUMAN

int var; int * pointer = &var; *pointer = 20; delete [] pointer; Int var; var = 20; Someone can tellme what is the diference of this two things?

The result is exactly the same

You just modify the value trough a pointer in the first one, and modify it directly in the second

Ahhhh

Thats all?

Well, thx, thats a very very nice group ;) Thanks again.

Well, thx, thats a very very nice group ;) Thanks again.

yw

Nah

yw

You not xd

your welcome

xd

No wey :v

priv

@bo0tzz

Lol

/notes

Hy

I am human

Hello everyone. I want to learn programing concepts begining from C. #include<stdio.h> Int main () { Printf("Hello programmers \n"); Return 0; }

I'm look for someone who will take me through this teaching process.

#goodgoogling

I had no idea Google had a user manual

Nearly 100ppl haven't click our captcha

I mean, i am not getting why/how it is pointing to string "three"?

Don't know whether you received an answer.. Where do you mean? s[0] is "one", s[1] is "two" and s[2] is "three". When initializing p you take a pointer to the third (s[2]) element, so p is a "c-string" and points to "three". Incrementing the pointer - when doing ++p - will simply add the size of the element it's pointing to. char is one byte so it advances one byte. When incrementing pointers to "c-string" you basically skip the current first character, now p points to the "h" in "three".

I'm look for someone who will take me through this teaching process.

Someone who will follow you personally, am i right?

I mean, i am not getting why/how it is pointing to string "three"?

0x65fdf0: 0x6f 0x6e 0x65 0x00 0x00 0x00 0x00 0x00 0x65fdf8: 0x74 0x77 0x6f 0x00 0x00 0x00 0x00 0x00 0x65fe00: 0x74 0x68 0x72 0x65 0x65 0x00 0x00 0x00 Maybe this makes it more clear. The array s might look like the following (see map above) where each line represents one of the strings, the first is "one", the second "two" and the third "three". After initialization p points to the last row. If you print p as string all characters will be printed until the \0 termination is found. When incrementing p it will move one position to the right, not down! So it is basically pointing to s[2] + 1 which is the second element in the last row, representing the "h". When printing as string, again all characters will be printed until \0 is reached. The interesting part however is the side effect of ++p as parameter, which triggers ub/idb. Depending on the compiler either "three" or " hree" will be printed. Obviously, the last four letters will be "hree" since the second argument will point to the "h" for sure. C and C++ do not specify the order of argument evaluation, which means every compiler is free to either compute *(p-1) first and then ++p, or the other way around. Depending on the side affect of the incrementation the result may vary, letting *(p-1) either point to a \0 symbol (last element in second row) or to the "t" of "three".

Hello group

Hi

Hi

Hi

How ru??

How ru??

Nice, n u?