vim ai on: struct *bar foo(struct bar *foobar) { if (!foobar) foobar = malloc(sizeof(struct bar)); return (*bar)foobar; }

sorry.. indented you can see better

sorry.. indented you can see better

Seriously, I don't understand unindented code 😷

seriusly.. i don't know how indent with my android

xD

seriusly.. i don't know how indent with my android

use termux+vim there

or quickedit :)

i will try it

vim ai on: struct *bar foo(struct bar *foobar) { if (!foobar) foobar = malloc(sizeof(struct bar)); return (*bar)foobar; }

Btw, malloc can return a null ^-^

Which is sad

Btw, malloc can return a null ^-^

Yeah :(

Yes

Shashank https://ptpb.pw/3NTg/c

👍

Big o notation

Yes

Big o notation

I can't argue with it

It's 72n

How to assign the memory address of a vector char v[50][50] to a double pointer char **p

How to assign the memory address of a vector char v[50][50] to a double pointer char **p

why would you ever need to do that?

How to assign the memory address of a vector char v[50][50] to a double pointer char **p

use pointers to pointers that points to pointers that pointes to another pointer that points to another one and so on :)

Shashank https://ptpb.pw/3NTg/c

Thanks buddy!

you're welcome

😄

😊

How to assign the memory address of a vector char v[50][50] to a double pointer char **p

v is the pointer you're searching for

And v[50][50] is an array, not a vector

How to assign the memory address of a vector char v[50][50] to a double pointer char **p

you mean malloc?

He means pointercasts i think

He means pointercasts i think

char[50][50] is a type, and char[49][49] is another type vector is dynamic and has a type vector<char>, not vector<char[50]> You could make a vector of char[50], but why? :c

How about we ignore questions that don't provide enoufd context?

Btw : my code isn't working can anybody tell me why? Pls sir!

Btw : my code isn't working can anybody tell me why? Pls sir!

Same problem?

Or are you making a stupid question

To show an example of a stupid question?

To show an example of a stupid question?

Precisely this

Same problem?

I've given up, ill refactor the rest of tde code and figure that shit out later

Lol

#include <iostream> #include <vector> int main() { std::vector<std::vector<char>> vec{{'1', '2', '3'}, {'6', '5', '4'}}; int l1 = vec.size(); int l2 = vec.data()->size(); char** ptr = (char**)malloc(l1); for(int i = 0; i < l1; i++) ptr[i] = vec[i].data(); for(int i = 0; i < l1; i++) { for(int j = 0; j < l2; j++) std::cout << ptr[i][j] << " "; std::cout << "\n"; } std::cout << std::endl; free(ptr); return 0; }

Result: 1 2 3 6 5 4

Don't laugh, the request is more stupid than the code xD

Result: 1 2 3 6 5 4

Doesn't rely on any input so just hardcode the outputs

x1 ans are not showing display

-nan

yeah

its right

its working right

so its NaN

doesnt have roots

Not a Number

Anyone knows any accredited online computer programs?

Thank you

doesnt have roots

he has to put a conditional before make SQRT: if ((b*b-4*a*c) < 0) { SQRT * -i}

Heyyyyy...... Does anyone know how i can convert php to html en css3

Heyyyyy...... Does anyone know how i can convert php to html en css3

Yes

hey guys, a bit of confusion

a uint64_t is the same as saying uint8_t a[8]; right ?

memory map wise, yes

alright. what would be the advntage of one over the other?

the one is just an array of numbers the other is a number

ahhh okay, so uint64_t iwould be 123456788 and `uint8_t a[8] = {12345678, 12345678 etc};` ?

ahhh okay, so uint64_t iwould be 123456788 and `uint8_t a[8] = {12345678, 12345678 etc};` ?

the array couldn't hold numbers bigger than 255

the array couldn't hold numbers bigger than 255

ohhhh yeah right

cuz ascii values right?

but you can reinterpret cast the array to a uint64_t

or what?

cuz ascii values right?

8 bits can only hold 256 states

8 bits can only hold 256 states

what do you mean when you say states?

a state

either on or off

I also try

oh ok lol 😂

either on or off

those are the two states of a bit

Ok lol

two bit can have four states already

1 or 0 hehe

two bit can have four states already

this grows exponentially

1

those are the two states of a bit

yea i understand thanks