This is because the char variable always holds ascii value instead of its real value. To convert it properly do minus '0' like that:

Actually my motif was to convert char to int type. Not the other way around. Thanks btw

atoi() can't do that with char type :[ Says: no matching function to call for atoi() Edit: Figured it out. I need to pass the address to the atoi() function

include <stdlib.h> bro

You meant binary?

Yes, it's binnary

Yes, it's binnary

not double n

biner. binary

I think it is time for me to leave this group. I dont like this stupid timer. Bye² all.

How can I use logarithms when I have to find the product of 4 variables (each variable is having a maximum possible range of 1e9)?

𝕂𝕦𝕤𝕙𝕒𝕘𝕣𝕒 🏳️‍🌈 sent a huge message, it has been re-uploaded as a file i recently started learning c, and was working on a program to swap variable values. i created t..

^ you are just swapping pointers, not the values, so the program just does what you have told it

#include <stdio.h> #include <stdlib.h> int main(void) { int a; print("Enter a number"); scanf("%d",&a); printf("you have entered %d",a); return EXIT_SUCCESS; }

#include <stdio.h> #include <stdlib.h> int main(void) { int a; print("Enter a number"); scanf("%d",&a); printf("you have entered %d",a); return EXIT_SUCCESS; } plz tell me , how to solw it

#include <stdio.h> #include <stdlib.h> int main(void) { int a; print("Enter a number"); scanf("%d",&a); printf("you have entered %d",a); return EXIT_SUCCESS; } plz tell me , how to solw it

solve what?

#include <stdio.h> #include <stdlib.h> int main(void) { int a; print("Enter a number"); scanf("%d",&a); printf("you have entered %d",a); return EXIT_SUCCESS; } plz tell me , how to solw it

printf

the first "print"

#include <stdio.h> #include <stdlib.h> int main(void) { int a; print("Enter a number"); scanf("%d",&a); printf("you have entered %d",a); return EXIT_SUCCESS; } plz tell me , how to solw it

What there doing "void", can someone explain? (it's not a nitpick)

The parameters of the main function are entered from the command line terminal

What there doing "void", can someone explain? (it's not a nitpick)

basically implies that the main function will NOT take any arguments, even if you provide it.

not double n

I mean binary, sorry😁

Hi all, https://github.com/mitesh-gohel/queries/blob/main/t2.c Can anyone help me to understand behaviour of this code ?

Hi all, https://github.com/mitesh-gohel/queries/blob/main/t2.c Can anyone help me to understand behaviour of this code ?

"For unsigned numbers, the bit positions that have been vacated by the shift operation are zero-filled. For signed numbers, the sign bit is used to fill the vacated bit positions. In other words, if the number is positive, 0 is used, and if the number is negative, 1 is used." so -1 as b11111111 after ">> 1" will be the same b11111111 which equal -1

guys read and write, when used for TCP socket communication, return -1 on error, right? For istance, server-side is stuck on a read, client-side the client closes the socket (close(client_socket) and exits (exit(0)). Well, the read server-side should return -1, right? Well, it returns 0 to me... and I'm not quite sure why this happens. Do you have any ideas? The code is for POSIX systems, but I'm coding on windows, I use WSL for terminal and gcc to compile.

Can everyone explain what the system ("pause") function is?

guys read and write, when used for TCP socket communication, return -1 on error, right? For istance, server-side is stuck on a read, client-side the client closes the socket (close(client_socket) and exits (exit(0)). Well, the read server-side should return -1, right? Well, it returns 0 to me... and I'm not quite sure why this happens. Do you have any ideas? The code is for POSIX systems, but I'm coding on windows, I use WSL for terminal and gcc to compile.

Can't you check the documentation? A read() call on a socket is equivalent to a recv() call without any flags. Here is a quote from the documentation for recv() for your use case. When a stream socket peer has performed an orderly shutdown, the return value will be 0 (the traditional "end-of-file" return). In future, learn to read the documentation.

"For unsigned numbers, the bit positions that have been vacated by the shift operation are zero-filled. For signed numbers, the sign bit is used to fill the vacated bit positions. In other words, if the number is positive, 0 is used, and if the number is negative, 1 is used." so -1 as b11111111 after ">> 1" will be the same b11111111 which equal -1

For signed integers, >> has implementation defined behavior. It is not always the case that the sign bit is used.

For signed integers, >> has implementation defined behavior. It is not always the case that the sign bit is used.

I couldn't find mentions about this dependency. But also I am a not a c or c++ programmer. I found Draft n4835 which says in 7.6.7-3: The value of E1 >> E2 is E1/(2^E2), rounded down. [Note: E1 is right-shifted E2 bit positions. Right-shift on signed integral types is an arithmetic right shift, which performs sign-extension. — end note]

"For unsigned numbers, the bit positions that have been vacated by the shift operation are zero-filled. For signed numbers, the sign bit is used to fill the vacated bit positions. In other words, if the number is positive, 0 is used, and if the number is negative, 1 is used." so -1 as b11111111 after ">> 1" will be the same b11111111 which equal -1

Thanks @zolokonst

I couldn't find mentions about this dependency. But also I am a not a c or c++ programmer. I found Draft n4835 which says in 7.6.7-3: The value of E1 >> E2 is E1/(2^E2), rounded down. [Note: E1 is right-shifted E2 bit positions. Right-shift on signed integral types is an arithmetic right shift, which performs sign-extension. — end note]

You are looking at the C++ Standard while code is in C. Even in C++, the right shift operation was implementation defined until C++20 and it was made an arithmetic shift with sign extension only in C++20 (you are referring to the draft copy for the standard after this change). Here is the quote from Cppreference: For negative a, the value of a >> b is implementation-defined (in most implementations, this performs arithmetic right shift, so that the result remains negative). (Pre C++20) The value of a >> b is a/2b , rounded down (in other words, right shift on signed a is arithmetic right shift). (Since C++20) In C however, right shifts on a negative integer is Implementation Defined Behavior while left shift on a negative integer is Undefined Behavior.

Can't you check the documentation? A read() call on a socket is equivalent to a recv() call without any flags. Here is a quote from the documentation for recv() for your use case. When a stream socket peer has performed an orderly shutdown, the return value will be 0 (the traditional "end-of-file" return). In future, learn to read the documentation.

That's right, my professor anyway says that it must return -1 when client collapses. Which is very strange, since when the client abandons in an unpredictable way it must return -1 as it is an error, but if all writing process correctly close the connection on the client side, then it returns 0. But my professor insists it returns -1 anyway, that's the reason of my question. When I hit the client with CTRL+C the client will close socket, and on the other side the server, stuck in the read, will return Errno= 0 Streerror(errno)= SUCCESS and i really don't know if it is correct, but I take it as SUCCESS means that on the other side the channel was properly handled

At this point I think we had a misunderstanding, as the documentation is very clear and even in his papers, when talking about PIPEs, he says that a read call returns 0 when all writers processes correctly close the pipe on the other side

Hello guys, I am experiencing problems trying to make intellisense and MSVC compiler recognise includePaths for my ns3 simulation c++ code. Running the compilers throws errors that the header files cannot be found, and intellisense shows red squiggly lines under the specified headers.

I have specified the headers in the c/c++ compiler configuration in the .vscode folder but nothing seem to work.

There might be something like include paths but I am not Ms fan

Yes, I specified it but intellisense happens to ignore it

Dαɾƙ Tαɳɠҽɳƚ sent a code, it has been re-uploaded as a file

Dαɾƙ Tαɳɠҽɳƚ: Sample Input 2: 2 9 1 3 6 2 5 4 3 2 4 12 6 2 8 10 5 -2 5 10 Sample Output 2: 0 2 when i do second testcase then it is showing 3 as output instead of 2

If you can see compiler commands somewhere check if it is set there https://learn.microsoft.com/en-us/cpp/build/reference/i-additional-include-directories?view=msvc-170

I have ns3 installed built on wsl on windows and I am interfacing it using vscode from windows through a mapped UNC address to the wsl virtual drive

Dαɾƙ Tαɳɠҽɳƚ sent a code, it has been re-uploaded as a file

Dαɾƙ Tαɳɠҽɳƚ: Sample Input 2: 2 9 1 3 6 2 5 4 3 2 4 12 6 2 8 10 5 -2 5 10 Sample Output 2: 0 2 when i do second testcase then it is showing 3 as output instead of 2

Pls someone help

Dαɾƙ Tαɳɠҽɳƚ: Sample Input 2: 2 9 1 3 6 2 5 4 3 2 4 12 6 2 8 10 5 -2 5 10 Sample Output 2: 0 2 when i do second testcase then it is showing 3 as output instead of 2

??

I think you are breaking the rules

Don know wat it is supposed to do for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ if(sum==arr[i]+arr[j]){ pair++; } } } but try to put arr[i]+arr[j] into parenthesis

Don know wat it is supposed to do for(int i=0;i<n;i++){ for(int j=0;j<n;j++){ if(sum==arr[i]+arr[j]){ pair++; } } } but try to put arr[i]+arr[j] into parenthesis

It will check the statement and only if it is true then only if will add one in the pair

It is not wrong because there are two test case first is right but in second when it is printing 3 but the right answer is 2

It is not wrong because there are two test case first is right but in second when it is printing 3 but the right answer is 2

have you tried it?

hmm ok addition seems to have priority over comparison

at least at onlinegdb :D

have you tried it?

Yes

It will check the statement and only if it is true then only if will add one in the pair

could you describe the "statement" ?

I guess you might want to exclude cases when i==j

But i have no idea what is your code supose to do

Hello there good people! How do I typecast a char array element to an int element? For example: char a[10]; a[5] = '2'; int b = (int)a[5] + 0; printf("%d", b); I wish to convert the a[5] element into an integer data type. But the code above doesn't seem to achieve that. (It doesn't print 2. But prints the ASCII value of 2. Which is 50)

Because the casting treats the same value (50, 0x32) as 2 different types. That not means the ascii representation of 2 will be printed as 2 as a decimal value. 0x32 is not 0x02

could you describe the "statement" ?

Bro I can't send photo of the question in grp

Hello

As I see in many sources the code of depth first and breadth first but I didn’t understand the code well any suggestions from where I can understand well the code of depth first and breadth first . Thank you !

How to ise thread library in with mingw compulier i have getting an error

How to ise thread library in with mingw compulier i have getting an error

What thread library? C or C++? What is the error?

As I see in many sources the code of depth first and breadth first but I didn’t understand the code well any suggestions from where I can understand well the code of depth first and breadth first . Thank you !

Learn the programming language that you like to read code in well first. Then learn about DFS and BFS along with other graph algorithms. Now look at the code again.

i install clang from script in their site - but now terminal cant find clang and cant run in terminal

i install clang from script in their site - but now terminal cant find clang and cant run in terminal

Command 'clang' not found, but can be installed with: sudo apt install clang

Command 'clang' not found, but can be installed with: sudo apt install clang

have you tried running clang with it's fullpath?

have you tried running clang with it's fullpath?

i find it - i must type clang-15

i find it - i must type clang-15

there you go

i find it - i must type clang-15

I am curious, why have you installed it from their site and not from the repositories?

I am curious, why have you installed it from their site and not from the repositories?

because in repo is clang version 11

because in repo is clang version 11

ah, understandable; thanks :)

because in repo is clang version 11

???? If the repo is 11 where do you think Clang 15 was built from? Not sure which repo you are looking at

???? If the repo is 11 where do you think Clang 15 was built from? Not sure which repo you are looking at

you must add 15 to end of all pacakges

you must add 15 to end of all pacakges

I have Clang built from the llvm compiler infrastructure repo and I have the latest version of Clang.

I have Clang built from the llvm compiler infrastructure repo and I have the latest version of Clang.

you can install all from script just copy and paste and enter

everyone do it with different methods

???? If the repo is 11 where do you think Clang 15 was built from? Not sure which repo you are looking at

they are probably on some stable or old debian or something

they are probably on some stable or old debian or something

You can build clang-15 from the repo even on a very old Debian distribution. LLVM just expects a C+11 compiler to build Clang (not sure if it has been upgraded to C++14 now)

You can build clang-15 from the repo even on a very old Debian distribution. LLVM just expects a C+11 compiler to build Clang (not sure if it has been upgraded to C++14 now)

well but then you _have_ to compile it and not just download it no?

You can build clang-15 from the repo even on a very old Debian distribution. LLVM just expects a C+11 compiler to build Clang (not sure if it has been upgraded to C++14 now)

It was upgraded to C++14 long time ago

well but then you _have_ to compile it and not just download it no?

Yes. But you can then upgrade to later versions easily. With the script you have to wait for it to be made available. The same with your distro's package managers.

And actually it needs C++17 now

It was upgraded to C++14 long time ago

Alright. Thanks.

And actually it needs C++17 now

C++17 is with LLVM 16. That I know for sure. For 15, it works with C++14. I thought they would move from C++11 directly to C++17. No point in switching to C++14 which had very minor additions on top of C++11

C++17 is with LLVM 16. That I know for sure. For 15, it works with C++14. I thought they would move from C++11 directly to C++17. No point in switching to C++14 which had very minor additions on top of C++11

https://reviews.llvm.org/D122976 Yes, probably