Hi, can someone give me an idea of how I can make a conversion with 5 choices and the 6th choice is exit. Then in each choice there should be 10 sub-choices that also have conversion

Assume you declared int* p, and p’s current value is 100. What is p + 1 ?

Assume you declared int* p, and p’s current value is 100. What is p + 1 ?

Assuming 100 as the address value, then p+1 would be 104

how to create a thread when tcpsocket get a new connection?

Guys, how I can start learn C programming?

misi

you watch some videos / you read some books, you try to code something, you try to understand what the code means and such

Which book do you recommend?

c++ question .... your code subclasses something from libX, overriding some virtual functions, and marks them as override....... new version of libX comes out your code now fails because the virtual function you re-implement no longer exist..... if you remove them, it fails to build against the old libX do you just remove the override keyword? the functions dont actually do anything, only exist because the base class was pure abstract and they needed an implementation

c++ question .... your code subclasses something from libX, overriding some virtual functions, and marks them as override....... new version of libX comes out your code now fails because the virtual function you re-implement no longer exist..... if you remove them, it fails to build against the old libX do you just remove the override keyword? the functions dont actually do anything, only exist because the base class was pure abstract and they needed an implementation

c++ question .... your code subclasses something from libX, overriding some virtual functions, and marks them as override....... new version of libX comes out your code now fails because the virtual function you re-implement no longer exist..... if you remove them, it fails to build against the old libX do you just remove the override keyword? the functions dont actually do anything, only exist because the base class was pure abstract and they needed an implementation

hello everyone , im currently study to OS exam , and i learn about dangling pointers which means that we use a pointer that we already free. i ask the chatGPT to generate me example and this is the code that he return : #include <stdlib.h> int *get_largest(int *arr1, int *arr2) { if (arr1[0] > arr2[0]) { return arr1; } else { return arr2; } } void dangling_pointer_example() { int arr1[10] = {0}; int arr2[10] = {1}; int *largest = get_largest(arr1, arr2); // ... // arr1 or arr2 is freed, but largest still points to it free(arr1); *largest = 5; } i think there is no dangling pointer here since the pointer largest is point to the first value of arr2 , which is not freed . am i right?

Well I wouldn't use such a library to begin with. It doesn't follow the semantic versioning rules. Assuming it did and the bump up was a major version change, I would still not use it because it doesn't respect the interfaces it created. So you can expect non compatible changes in the future from such a library maintainer. In such a case, if the library must be used, i will then fixate on the version that works and not upgrade (i.e fix the library version to a particular release in the build tool). In the meantime, i will also hunt for alternatives or try writing the library from scratch myself.

Hello guys I would like to ask how to run 2 while loops simultaneously? Im still new to C++ programming #include <iostream> using namespace std; int main() { int a,b; a = 1, b = 0; while (a <= 10) { // while() loop which keep repeating the output until condition achieved cout << "Im handsome x" << a << endl; a += 1; // a = a + 1 } while (a <= 10) { b += a; // b = b + a a += 1; } cout << "Sum of 1 to 10 is " << b << endl; system("pause"); return 0; } For the output on the second loop, the output is wrong.

Why my records are getting recorded like this sabin thamel Öå ºaccountant  ºý úD

how to create a thread when tcpsocket get a new connection?

I have to calculate the sum of all products in an array but i want that if the day array value increase sum starts with 0 not the value in the previous day array value calculation

I am not getting its logic

hi guys, so I have a problem with writing on sockets in C. Imagine you want to write two messages (server) to the Client: write(socket, "HELLO", strlen(HELLO))...; // Other code (non blocking calls); write(socket, "BUDDY", strlen(BUDDY))...; Well, you would expect (Client-side) this to happen: First read: HELLO Second read: BUDDY Instead this happens: HELLOBUDDY So the two writes on socket are merged. How can I avoid this? It does not happen in this case: write(socket, "HELLO", strlen(HELLO))...; // Other code, but this time BLOCKING calls, like read(socket, buff, sizeof(buff)); write(socket, "BUDDY", strlen(BUDDY))...; Or this case: write(socket, "HELLO", strlen(HELLO))...; // Other code (non blocking calls); // sleep(some time); write(socket, "BUDDY", strlen(BUDDY))...; But the former rarely occurs (sometimes I just have to send two different things on the net) and the latter won't be accepted by my professor. I will be thankful for every suggestion!

Hello everyone could u tell me how to let the user enter his marks plzzzz And display them Struct student { Int Marks[20]; }; Int main (){ Student s1[100]; ……………. // cout what ? }

vector<vector<Point> > contoure;

Hello, don't get bored, sorry, can someone explain to me what it does in this vector that uses a point

Does any one knows about C++ programming to teach?

If I will install kali linux, which program I can use for C language with live prewie of code result

I am looking for a teacher in c++programing

Нуъмонжонов Пахлавон sent a code, it has been re-uploaded as a file

If I will install kali linux, which program I can use for C language with live prewie of code result

If I will install kali linux, which program I can use for C language with live prewie of code result

I am looking for a teacher in c++programing

If you know at least something you can learn fast with our without mentor

I need a person debug my errors