https://learn.microsoft.com/ru-ru/windows/win32/psapi/enumerating-all-processes all the processes that I found in this way turned out to be user (I compared their sid and user) how to find all the others?

Hi I want to help about program for c++ please 🥺

Alright

Thanks Ok From where can I start

#include <stdio.h> int main() { int number; printf("plase enter a number"); scanf("%d",&number); if(number>0) { printf("pozitif"); } else { if (number == 0) { printf("number is eaqul 0") ; } else { printf("the number is negatif"); } } }

void printNumbers(){ int i; for(i =0;i < 5; i++) {cout << “Numbers :” << i<< endl;} } Please how do I pass this void function to my c++ main function?

You can start with learning the data types involved in the c++ program

just call the function inside your main function printNumbers()

Ohh okay So void functions take no arguments in their calling?

Do you main in struct?

no, void function can take arguments, void functions do not return anything

Not really I’m just a member here also , learning but I can assist if you want

Yeah, I need to assist please 🥺

I just want to learn how to calculate auxiliary space and space complexity

#include <iostream> #define ULI unsigned long int ULI fact(ULI value){ if(value < 2){ return 1; } return value * fact(value-1); } double check(ULI value){ return ((fact(value-1)+1)/value); } int main(){ int value = 9; double x = (fact(value-1)+1)/value; std::cout << (fact(value-1)+1)/value << "\n"; // why not in decimals? std::cout <<x; // why not it decimals? }

because you are using whole number arithmetics

value-1 => int fact() => return int fact() + 1 => int ()/value => none is floating point so whole number division => int

value-1 => int fact() => return int fact() + 1 => int ()/value => none is floating point so whole number division => int

and then the last step is to convert it to double and store it in x

it is implicitly converted from int to double

if you want fixed double number in the std::cout see this https://stackoverflow.com/questions/5907031/printing-the-correct-number-of-decimal-points-with-cout But your calculation is not made as floating point arithmetic (so just storing it in double doesn't make much sense)

but when it's converted to double it doesn't have those decimal values and i need them...

well... the result is 4480.0000000000

well.... I mean when value = 9 then fact(8)+1 = 40320 + 1 = 40321 and 40321/9 = 4480.11...11

well 40321/9 is 4480

you are making whole number division

if you want to do floating point arithmetic you need to use double or float

double x = static_cast<double>(fact(value-1)+1)/value;

No problem

#include <iostream> double fact(double value){ if(value < 2){ return 1; } return value * fact(value-1); } double check(double value){ return ((fact(value-1)+1)/value); } int main(){ int value = 9; double x = (fact(value-1)+1)/value; std::cout << (fact(value-1)+1)/value << "\n"; // why not in decimals? std::cout <<x; // why not it decimals? }

#include <iostream> #define ULI unsigned long int ULI fact(ULI value){ if(value < 2){ return 1; } return value * fact(value-1); } double check(ULI value){ return ((fact(value-1)+1)/value); } int main(){ int value = 9; double x = (fact(value-1)+1)/value; std::cout << (fact(value-1)+1)/value << "\n"; // why not in decimals? std::cout <<x; // why not it decimals? }

using ULI = unsigned long int;

Hi, I have a C++ code given to me by one of my colleagues and it has this statement #define __USE_MINGW_ANSI_STDIO 0 What does it mean? I understand that 0 disables it but what is its function when enabled to 1?

What is MINGW_ANSI_STDIO though?

What is MINGW_ANSI_STDIO though?

Is there anyone who can guide me with c++ programming

Yes I can