@programminginc - страница 3549

Khadija

Do share with me if you come across any good source

Okey ,, ✨

Khadija

I didn’t know how to analyze the time complexity here : For(I=1 ; i <=n; I++) For(j=1;j<=n;j++) {p=false ; k=1; While((!P && k<=j) If(A[i][j][k] == x) p=true; else k++; } The first loop of course O(n) But I didn’t know how to finish the rest … Can someone help me ? Thank you so much ✨

klimi

I didn’t know how to analyze the time complexity here : For(I=1 ; i <=n; I++) For(j=1;j<=n;j++) {p=false ; k=1; While((!P && k<=j) If(A[i][j][k] == x) p=true; else k++; } The first loop of course O(n) But I didn’t know how to finish the rest … Can someone help me ? Thank you so much ✨

could you please reformat your message so the code is correctly indented and with ``` ?

Khadija

could you please reformat your message so the code is correctly indented and with ``` ?

How ? I wrote it as I found it😢

ALTER EGO

How ? I wrote it as I found it😢

Copy code and goto codebeautify.org/cpp-formatter-beautifier to format. On telegram RMB -> Edit -> Paste code -> Select code -> CTRL+SHIFT+M -> Send

klimi

How ? I wrote it as I found it😢

How? well just manually indent put it in monospace with ```, the classic stuff

Daniel

Hi, im newbie in c++ and i have to do an assignment i've been 3 hours struggling. The assignment is to show a name list with a unidemsional array of 10 positions with all the positions empties, find where are the empties positions (.find) to replace, them ask the user for a name name. The user will give the names until all the array[10] is full (while). It will be great if someone can help me fix my code.

ㅤㅤㅤ

I tried GFG Add two numbers represented by two arrays but getting error can anybody point it out https://practice.geeksforgeeks.org/problems/add-two-numbers-represented-by-two-arrays2408/1 class Solution{ public: string calc_Sum(int *a,int n,int *b,int m){ // Complete the function int num1=0,num2=0,sum; for(int i=0;i<n;i++){ num1 = num1*10+a[i]; } for(int i=0;i<m;i++){ num2 = num2*10+b[i]; } sum = num1+num2; return sum; } };

Talula

I tried GFG Add two numbers represented by two arrays but getting error can anybody point it out https://practice.geeksforgeeks.org/problems/add-two-numbers-represented-by-two-arrays2408/1 class Solution{ public: string calc_Sum(int *a,int n,int *b,int m){ // Complete the function int num1=0,num2=0,sum; for(int i=0;i<n;i++){ num1 = num1*10+a[i]; } for(int i=0;i<m;i++){ num2 = num2*10+b[i]; } sum = num1+num2; return sum; } };

Convert both the array of numbers to string, convert to it to int and add...

Anonymous

Convert both the array of numbers to string, convert to it to int and add...

Either read the question completely and then reply or don't reply at all.

Anonymous

I tried GFG Add two numbers represented by two arrays but getting error can anybody point it out https://practice.geeksforgeeks.org/problems/add-two-numbers-represented-by-two-arrays2408/1 class Solution{ public: string calc_Sum(int *a,int n,int *b,int m){ // Complete the function int num1=0,num2=0,sum; for(int i=0;i<n;i++){ num1 = num1*10+a[i]; } for(int i=0;i<m;i++){ num2 = num2*10+b[i]; } sum = num1+num2; return sum; } };

This is wrong because int datatype is too small to store a number with 100000 digits. You have to manually do the addition like you did in school with carryover and stuff

Anonymous

Anybody good at data structure and algorithm(DSA)?

klimi

Anybody good at data structure and algorithm(DSA)?

don't ask meta questions, thanks

Anonymous

I tried GFG Add two numbers represented by two arrays but getting error can anybody point it out https://practice.geeksforgeeks.org/problems/add-two-numbers-represented-by-two-arrays2408/1 class Solution{ public: string calc_Sum(int *a,int n,int *b,int m){ // Complete the function int num1=0,num2=0,sum; for(int i=0;i<n;i++){ num1 = num1*10+a[i]; } for(int i=0;i<m;i++){ num2 = num2*10+b[i]; } sum = num1+num2; return sum; } };

Error with the parameters regarding the data types

Subhajit

Any one have object oriented programming book 6th edition by E balagurusamy?

Subhajit

Any one have object oriented programming book 6th edition by E balagurusamy?

With c++

Edward

int* ammo = (int*)getPointerAddress(moduleBase + FullAmmoAddr, { 0x28, 0x224, 0x0 }); float* subAmmo = (float*)getPointerAddress(moduleBase + FullAmmoAddr, { 0x108, 0x44, 0x10 }); float FullAmmo = ammo + subAmmo; error code C2110 '+' : cannot add two pointers I've searched the internet and couldn't find any examples other than the string data type an example on the internet is just a string, then how do you add up the values of the *ammo and *subammo pointers?

labyrinth

how to know if a unique_ptr is holding a pointer that is not freed? it could potentially be called with ::get and deleted somewhere else.

Anonymous

how to know if a unique_ptr is holding a pointer that is not freed? it could potentially be called with ::get and deleted somewhere else.

That is Undefined Behavior. You shouldn't do it. The moment your unique_ptr's destructor runs, your code will run into UB territory. So if you are worried that a unique_ptr may hold an already deleted pointer, then you should worry more about teaching the concerned developer about C++ and worry about your code later.

Anonymous

int* ammo = (int*)getPointerAddress(moduleBase + FullAmmoAddr, { 0x28, 0x224, 0x0 }); float* subAmmo = (float*)getPointerAddress(moduleBase + FullAmmoAddr, { 0x108, 0x44, 0x10 }); float FullAmmo = ammo + subAmmo; error code C2110 '+' : cannot add two pointers I've searched the internet and couldn't find any examples other than the string data type an example on the internet is just a string, then how do you add up the values of the *ammo and *subammo pointers?

float fullAmmo = ammo + subAmmo; should be float fullAmmo = *ammo + *subAmmo; The int will automatically get converted to a float.

Edward

float fullAmmo = ammo + subAmmo; should be float fullAmmo = *ammo + *subAmmo; The int will automatically get converted to a float.

thankyou its working now

Anurag

vector<int> leaders(int a[], int n){ vector<int> ans; if(n == 1){ ans.push_back(a[0]); return ans; } else{ ans.push_back(a[0]); } int indx = 0; int j = 1; while(indx < n-1){ for(int i = (indx + 1); i < n; i++){ if(a[i] > ans[j - 1]){ ans.pop_back(); ans.push_back(a[i]); indx = i; } } ans.push_back(a[indx + 1]); j++; } return ans; }

Anurag

vector<int> leaders(int a[], int n){ vector<int> ans; if(n == 1){ ans.push_back(a[0]); return ans; } else{ ans.push_back(a[0]); } int indx = 0; int j = 1; while(indx < n-1){ for(int i = (indx + 1); i < n; i++){ if(a[i] > ans[j - 1]){ ans.pop_back(); ans.push_back(a[i]); indx = i; } } ans.push_back(a[indx + 1]); j++; } return ans; }

can anyone tell me why am I geeting "Abort signal from abort(3) (SIGABRT)" error for this code, and how can I resolve it?

mj12

can anyone tell me why am I geeting "Abort signal from abort(3) (SIGABRT)" error for this code, and how can I resolve it?

Something's probably throwing an exception, attach gdb or any other debugger and have a look

Anonymous

can anyone tell me why am I geeting "Abort signal from abort(3) (SIGABRT)" error for this code, and how can I resolve it?

you're indexing the default initialized vector. You should rather declare the vector with the size of the array and initialized all values to the default before using index operation

Void

I wonder how to move all characters one place forward?

code

I can help CP(codeforces, codechef, ...) contest and some assignments. Please contact me.

Void

The second char

Void

Like , abcde → bcde

Void

It's actually more complicated😭

code

I can help CP(codeforces, codechef, ...) contest and some assignments. Please contact me. I am a Grand Master of Codeforces.

Anonymous

I wonder how to move all characters one place forward?

In C I know you could: #include <stdio.h> int main(void) { char arr[13] = "Hello World"; printf("String before: %s\n", arr); arr[12] = '\0'; for (int i = 12; i > 0; i--) { arr[i] = arr[i - 1]; } printf("String after: %s\n", arr); return 0; } but can also use memmove which is probably better: #include <stdio.h> #include <string.h> int main(void) {   char arr[13] = "Hello World";     printf("String before: %s\n", arr);   memmove (&arr[1], arr, strlen(arr));   printf("String after: %s\n", arr);   return 0; } Both run as expected.

Void

In C I know you could: #include <stdio.h> int main(void) { char arr[13] = "Hello World"; printf("String before: %s\n", arr); arr[12] = '\0'; for (int i = 12; i > 0; i--) { arr[i] = arr[i - 1]; } printf("String after: %s\n", arr); return 0; } but can also use memmove which is probably better: #include <stdio.h> #include <string.h> int main(void) {   char arr[13] = "Hello World";     printf("String before: %s\n", arr);   memmove (&arr[1], arr, strlen(arr));   printf("String after: %s\n", arr);   return 0; } Both run as expected.

Thank you! I'll try

Anonymous

In C I know you could: #include <stdio.h> int main(void) { char arr[13] = "Hello World"; printf("String before: %s\n", arr); arr[12] = '\0'; for (int i = 12; i > 0; i--) { arr[i] = arr[i - 1]; } printf("String after: %s\n", arr); return 0; } but can also use memmove which is probably better: #include <stdio.h> #include <string.h> int main(void) {   char arr[13] = "Hello World";     printf("String before: %s\n", arr);   memmove (&arr[1], arr, strlen(arr));   printf("String after: %s\n", arr);   return 0; } Both run as expected.

What memmove does is copy the length of the string to the second character of the same string.

Anonymous

What memmove does is copy the length of the string to the second character of the same string.

Bro

Anonymous

A simple help i need did anyone know about imgui?

DaviChan