Pointer is so hard to learn

I think in that case your memory allocated in stack. And after constructor method do work then that allocated memory frees (stack pops). New operator uses memory from heap

I think in that case your memory allocated in stack. And after constructor method do work then that allocated memory frees (stack pops). New operator uses memory from heap

So, Should i avoid declaring array like int A[size]; ?

ISO C++ doesn't support Variable length array

ISO C++ doesn't support Variable length array

Just use std::vector and you can use it with C and C++ I/O

It also doesn't support variable strings as parameter? I assume...how do i convert these to literals?

vector is looks complicated and hard.. it has all sorts of symbols <>... Any alternative which is simple?

type ptr[x] is *(ptr + x * sizeof(type))

Strange decision because STL is main thing in C++ to know

vector is looks complicated and hard.. it has all sorts of symbols <>... Any alternative which is simple?

vector is looks complicated and hard.. it has all sorts of symbols <>... Any alternative which is simple?

The right conversion is this https://t.me/programminginc/476407

That not so complicated. Simple methods push_back(), size(), resize(). You can use it like array [i]. Iterate like foreach for(auto it:vec).

There are two types right . One pointer only points to first member.. and the other type points to the whole array.. In the second case.. i think we don't need to do sizeof??

Yes you need to do, because accessing pointer can be casting into another types. Yet, it's done by adding specific bytes and then access the address

long long p = -1; char *ptr = &p printf(℅hhd\n", ptr[1]) This is legal

(Data model LLP64) in this case, p is 8 bytes. Thus it's same with char p[8] then memset it all to -1

What is LLP64?

Data model

thanks ..... Can you suggest me a good resource for learning pointer property?

That not so complicated. Simple methods push_back(), size(), resize(). You can use it like array [i]. Iterate like foreach for(auto it:vec).

(Data model LLP64) in this case, p is 8 bytes. Thus it's same with char p[8] then memset it all to -1

type ptr[x] is *(ptr + x * sizeof(type))

type ptr[x] is *(ptr + x * sizeof(type))

Got it.... Just to be sure . soo whenever type cast a void pointer, +/- operator automatically increments as per datatype's size?

Got it.... Just to be sure . soo whenever type cast a void pointer, +/- operator automatically increments as per datatype's size?

for (size_t i = 0; i < size; i++) {                 cout << *(ptr + i) << endl; }

for (size_t i = 0; i < size; i++) {                 cout << *(ptr + i) << endl; }

for (size_t i = 0; i < size; i++) {                 cout << *(ptr + i) << endl; }

Or you can just using for range loop

Size_t is also datatype?

Size_t is also datatype?

Yes. Its size depent on system. 32bit system has 32bit size_t, 64 has 64bit

Yes. Its size depent on system. 32bit system has 32bit size_t, 64 has 64bit

What is work of size_t .... Is it only used for integer array?

size_t on x86 is 16 bit

Are you sure?

You can sizeof everything

Are you sure?

Hello i wanna convert my C code to Java code can I do that?

I can't understand.. can you make it in detail pls

It depends what code you want to convert

int main() { typedef(size_t); return 0; } Its showing error

The code is : #include <stdio.h> int main () { int a,b,c; a = b = c = printf("what is a = \n"); scanf("%d", &a); printf("what is b = \n"); scanf("%d", &b); printf("what is c = \n"); scanf("%d", &c); int sum = a + b + c; printf("sum is : %d ", a + b + c); return 0; }

Heck, size_t is a typedef to scalar types like int, unsigned long

public static void main(String args[]) { int a, b, c; Buffered reader or Scanner.......

To scalar type means? 😢😅😅

Sorry, built-in types

Actually i don't know Java so can you please translate all that code and send it to me please?? I am doing this because i want to share my program as an apk and we can't convert our c code to apk right? But we can convert our Java program to an apk

Ohh . So user defined data type...size_t like int...

Noooo, it's compiler defined exactly

https://t.me/programminginc/462467

Thats not correct. Because size_t, uintptr_t can't be accesable in Real Mode. stdlib is os dependent thing.

type ptr[x] is *(ptr + x * sizeof(type))

size_t is defined in cstddef and uintptr_t is defined in cstdint. Both the headers will be available on a freestanding implementation and therefore those types will be available to use.

class sample{ int var; static int count; public: sample(int var):var(var){ // What exactly does this line do? could you please explain? cout<<"Count = "<<count<<endl; count++; } };

Thats not correct. Because size_t, uintptr_t can't be accesable in Real Mode. stdlib is os dependent thing.

I am using cxxdriod for Android.. for running code is it supported?

I have not used cxxdroid. But cxxdroid is not a freestanding implementation but a hosted implementation. It will support the standard library in its entirety.

Ohkay.. can you tell me vscode freestanding or not,

size_t is defined in cstddef and uintptr_t is defined in cstdint. Both the headers will be available on a freestanding implementation and therefore those types will be available to use.

You can implement own header with that types. But its not same with stdint.h.

What do you mean? cstdint is a header that must be available on freestanding implementations.

I going to useless discussion. I mean stdint.h implemented first for cstdlib and defined in c99 standart. But yes you can implement freestanding stdint.h, but formally(not in practice) that header not same with stdint.h

No. Freestanding implementations are when you are developing for a system with no operating system.

Most of the time, yes, but sometimes you just want to opt out shitty C lib and C++ libs like GNU crap for example

(well, you are kinda forced into accepting the freestanding part of libstdc++ since no other major library supports freestanding)

libc++ does support freestanding if I am not wrong