@programminginc - страница 3537

Daulet

Now it finds the length, and I would like it to also find the word itself. I really not understand how to do it

const char* maxword(TQueue& q){ int v; int maxi=0; const char* str; while(!isEmpty(q)){ v=strlen(deQueue(q)); if(v>maxi){ maxi=v; str = deQueue(q); } } return str; }

Ольга

const char* maxword(TQueue& q){ int v; int maxi=0; const char* str; while(!isEmpty(q)){ v=strlen(deQueue(q)); if(v>maxi){ maxi=v; str = deQueue(q); } } return str; }

In this code, the 2nd word in the queue is returned, not the largest

the best for everyone

// // Created by hassa on 01/10/2022. // #include <stdio.h> #include <stdlib.h> #include <conio.h> #define size 5 int stack[size]; int top=-1; int data; void push(); void pop(); void peek(); void display(); void push(){ printf("Enter the data that you want "); scanf("%d",&data); if(top==size-1) printf("the stack has been overflow"); else{ top++; stack[top]=size; // pay attention // until be full // it needs to understand much better } } void pop(){ int item; if(top==-1) printf("underflow"); else{ item= stack[top]; // pay attention // and if you dont want to write the pop item there is no need to write this line top--; printf("%d",item); } } void peek(){ // top if(top == -1) printf("the stack is empty"); else printf("the top is %d",stack[top]); } void display(){ for (int i=top ; i>=0 ; i--) { printf("the value of the stack << is %d",stack[i]); } } int main() { int choice=1; int d; do { printf("1- to push it\n"); printf("2- to pup them\n"); printf("3- to show the last top\n"); printf("4- to display them \n"); printf(" pressed 0 to get out \n"); printf("Enter your choice: "); scanf("%d", &choice); switch (choice) { case 1: push(); // printf("\nEnter A value:"); // scanf("%d",&d); break; case 2: pop(); break; case 3: peek(); break; case 4: display(); break; default: printf("wrong choice\n"); } } while (choice !=0);// it will get out if we pressed 0 getch(); }

https://dpaste.org/DkXi5#L5,8,10,11

the best for everyone

How it should work?

could you copy and past the code to see it

the best for everyone

I have sent it too in the link

Ольга

https://onlinegdb.com/Co_7gjr21 go through this updated code

Oh now I understand, Thank you, you are already helping me again, thank you for that

Ольга

const char* maxword(TQueue& q){ int v; int maxi=0; const char* str; while(!isEmpty(q)){ v=strlen(deQueue(q)); if(v>maxi){ maxi=v; str = deQueue(q); } } return str; }

Thanks for the advice

Maxter

how to resolve that "cannot find gcc" problem of vs code

Captain

https://dpaste.org/DkXi5#L5,8,10,11

Remove conio.h and getch() and in push function stack[top]=data.

Anonymous

Do you know any online compilers that support modules? I tried to enable/use them on wandbox using gcc and clang but without luck: https://wandbox.org/permlink/dRxtXqPMcMPip8gW

import std.core is supported only by MSVC. Gcc and Clang support header units and building your own modules. Conversion of standard library into modules is still a far way away as far GCC and Clang are concerned. So you will have to live with #include <iostream> in global module fragment or import <iostream> within the module purview (depending on your use cases). This is what GCC and Clang support now

Anonymous

the program throws std::regex_error what() invalid special open parenthesis

There is a problem with regex standard library's support for lookbehind but in most cases you can overcome it. We can help you if you share your code

Void

#include <stdio.h> #include <string.h> #include <math.h> int main() { char a[50]; scanf("%s",a); int i,len,sum,n; len=strlen(a); for(i=0,sum=0;i<len;i++) { sum=sum+(a[i]-48); } int t=sum; //求出位数n for( ;t>0;n++) { t=t/10; } int x; for(x=0;sum>0;n--) { x=sum/int(pow(10,n-1)); switch(x) { case'1':printf("yi");break; case'2':printf("er");break; case'3':printf("san");break; case'4':printf("si");break; case'5':printf("wu");break; case'6':printf("liu");break; case'7':printf("qi");break; case'8':printf("ba");break; case'9':printf("jiu");break; case'0':printf("ling");break; } printf("\n"); sum=sum%int(pow(10,(n-1))); } return 0; }

Void

Guys why does switch statement not work🥲

Anonymous

#include <stdio.h> #include <string.h> #include <math.h> int main() { char a[50]; scanf("%s",a); int i,len,sum,n; len=strlen(a); for(i=0,sum=0;i<len;i++) { sum=sum+(a[i]-48); } int t=sum; //求出位数n for( ;t>0;n++) { t=t/10; } int x; for(x=0;sum>0;n--) { x=sum/int(pow(10,n-1)); switch(x) { case'1':printf("yi");break; case'2':printf("er");break; case'3':printf("san");break; case'4':printf("si");break; case'5':printf("wu");break; case'6':printf("liu");break; case'7':printf("qi");break; case'8':printf("ba");break; case'9':printf("jiu");break; case'0':printf("ling");break; } printf("\n"); sum=sum%int(pow(10,(n-1))); } return 0; }

what's %S.

Руслан

#include <stdio.h> #include <string.h> #include <math.h> int main() { char a[50]; scanf("%s",a); int i,len,sum,n; len=strlen(a); for(i=0,sum=0;i<len;i++) { sum=sum+(a[i]-48); } int t=sum; //求出位数n for( ;t>0;n++) { t=t/10; } int x; for(x=0;sum>0;n--) { x=sum/int(pow(10,n-1)); switch(x) { case'1':printf("yi");break; case'2':printf("er");break; case'3':printf("san");break; case'4':printf("si");break; case'5':printf("wu");break; case'6':printf("liu");break; case'7':printf("qi");break; case'8':printf("ba");break; case'9':printf("jiu");break; case'0':printf("ling");break; } printf("\n"); sum=sum%int(pow(10,(n-1))); } return 0; }

You use int x type numbers

Руслан

But in case use ' ' words

Void

You use int x type numbers

!!Thanks

Void

what's %S.

character string?

Anonymous

character string?

it's %c.

Void

it's %c.

%c is a single character

Anonymous

%c is a single character

and %s is?

Void

a character string

artemetra 🇺🇦

#include <stdio.h> #include <string.h> #include <math.h> int main() { char a[50]; scanf("%s",a); int i,len,sum,n; len=strlen(a); for(i=0,sum=0;i<len;i++) { sum=sum+(a[i]-48); } int t=sum; //求出位数n for( ;t>0;n++) { t=t/10; } int x; for(x=0;sum>0;n--) { x=sum/int(pow(10,n-1)); switch(x) { case'1':printf("yi");break; case'2':printf("er");break; case'3':printf("san");break; case'4':printf("si");break; case'5':printf("wu");break; case'6':printf("liu");break; case'7':printf("qi");break; case'8':printf("ba");break; case'9':printf("jiu");break; case'0':printf("ling");break; } printf("\n"); sum=sum%int(pow(10,(n-1))); } return 0; }

because x is an int, and your cases have '1', not 1

Void

because x is an int, and your cases have '1', not 1

Yes,it has been solved😊thanks!

the best for everyone

Remove conio.h and getch() and in push function stack[top]=data.

what is the problem with conio.h and getch function

the best for everyone

I did as you told me but the problem still existed

Olayinka

and %s is?

%d=integer , %c = single character, %s = multiple string of character

Deepak Chaurasia

%d=integer , %c = single character, %s = multiple string of character

Can give examples of %s

Deepak Chaurasia

Char a = "hello world" p..("%s", a)?

Deepak Chaurasia

Works or need to declare array

Daulet

Char a = "hello world" p..("%s", a)?

use char* a or const char*

Deepak Chaurasia

asterisk use with char for?

Unknown man

Can anyone tell how to master all topic of c master from question and theory

Sleeves

can anyone help explain whats happening at line 16 here https://hastebin.com/isuhotizug.swift

Sleeves

*pn = 10 * *pn + c - '0';

Daulet

*pn = 10 * *pn + c - '0';

c - '0' is translates ascii character digit to integer.

Sleeves

c - '0' is translates ascii character digit to integer.

im having trouble understanding firstly the purpose of that line of code in the function

Daulet

im having trouble understanding firstly the purpose of that line of code in the function

Constructing number from digits. Example 345. 300 + 40 + 5 Iteration 1. *pn = 3. Read digit and *pn = 3 * 10 + 4 = 34 Iteration 2. *pn = 34. Read digit and *pn = 34*10 + 5 = 345

void

Can anyone tell how to master all topic of c master from question and theory

calculus discrete math etc, before learnong C

Sleeves

Constructing number from digits. Example 345. 300 + 40 + 5 Iteration 1. *pn = 3. Read digit and *pn = 3 * 10 + 4 = 34 Iteration 2. *pn = 34. Read digit and *pn = 34*10 + 5 = 345

thank you, i understand better now

Daulet

C

Dima

Bruh

Jose

*pn = 10 * *pn + c - '0';

Use parenthesis to help to understanding the pointers use. In my case, I use this conversion to understand the pointer usage: *pn = (10) * (*pn) + (c - '0'); pn[0] = (10) * (pn[0]) + (c - '0'); The point here is separate the usage of the pointer from the declaration of the pointer variable. The function contains various parts: - c - '0' is a hack to convert from ASCII number to their numerical form. The hex code of ASCII characters says that the hex value of 0x30 belongs to the character '0', the 0x31 is the character '1', and so on. This is a hack because it implies you are using ASCII notation to receive the "numbers" The second part, the multiplication, comes before the adding, so 10 * (pn[0]) says you are moving a digit to the left and adding a 0. Visually, it means: 10 * (the value of the first pn) = the partial result (10) * (pn[0]) = partial_result (10) * ( 5) = 50 (10) * (17362) = 173620 This is the mathematical translation of "displace to the left in decimal notation" The last part is the joining of both: The value you received from c (the character) and the value you displaced to the left

the best for everyone

Remove conio.h and getch() and in push function stack[top]=data.

I did that but nothing has changed

Captain

I did that but nothing has changed

It is working for me, what ide, compiler are u using?

Александр

Hello folks! Could you help me with an advice on how to fix my problem? I have a simple code with raylib. It is a dapper dasher. Character is running, but I want to change it's sprite when it is jumping. However, I cant figure out where to put this logic. It seems like a simple: if (velocity > 0); CharFrame = 4; Does not work.. Could you please help me with that? Dont want to paste whole code in here. Maybe pm? Have a nice evening!

Void

Guys I wonder how to insert spaces in an array of strings?

Anonymous

Tried to use import <iostream>; as in the first example here, with no luck also: https://en.cppreference.com/w/cpp/language/modules

This should work on a local system. But for this you should generate a header unit. As of now online compilers don't support generating header units. You can try it locally. For ex: //Main.cpp import <iostream>; int main(){ std::cout << "Hello World\n"; } On clang, I would compile it like this: >>clang -std=c++20 -xc++-system-header --precompile iostream -o iostream.pcm >>clang -std=c++20 main.cpp -fmodule-file=iostream.pcm -o main >>./main Hello World >>

Anonymous

Anyone can help me In learning c++ from basics

𝓐𝓷𝓴𝓾𝓼𝓱𝓱

Anyone can help me In learning c++ from basics

Let's learn together

Naufal

hello everyone, nice to meet you, here I am as a beginner and want to learn programming, and am looking for a complete c programming cheat sheet, if you have one, I beg you to ask, thank you

Arjun

typedef struct { int data; NODEPTR link; }*NODEPTR;

Arjun

which error

Daulet

typedef struct { int data; NODEPTR link; }*NODEPTR;

Is it C?

²

which error

y

²

need more code

Anonymous

Any recommended book/resource for learning data structures and algorithms for total beginners?

Hermann

Check in resources

Void

int a[10]; scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]); Guys why i input 1 0 2 0 3 4 1 9 8 7 and it shows a={1, 1, 0, 2, 0, 3, 4, 1, 9, 8}

Руслан

int a[10]; scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]); Guys why i input 1 0 2 0 3 4 1 9 8 7 and it shows a={1, 1, 0, 2, 0, 3, 4, 1, 9, 8}

Are you realy?

Руслан

Using a loop for (int i = 0; i < 10; i++) { scanf("%d", &a[i]); } instead of this scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]);

huluhulu

int a[10]; scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]); Guys why i input 1 0 2 0 3 4 1 9 8 7 and it shows a={1, 1, 0, 2, 0, 3, 4, 1, 9, 8}

&a[0]

Void

&a[0]

Ohhh thanks

Void

Using a loop for (int i = 0; i < 10; i++) { scanf("%d", &a[i]); } instead of this scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]);

Thank you!!

Void

Using a loop for (int i = 0; i < 10; i++) { scanf("%d", &a[i]); } instead of this scanf("%d %d %d %d %d %d %d %d %d %d",&a[1],&a[2],&a[3],&a[4],&a[5],&a[6],&a[7],&a[8],&a[9],&a[10]);

But can the numbers entered still be separated by spaces?