Why without using return?

I know how to solve it with return I'm in search for a new way to solve it

#include<stdio.h> int max(int arr[],int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; printf("%d ",arr[i]); } } int main() { int arr[7]={1,22,5,43,6,42,6},n=7; max(arr,n); }

I want the printf operation take place in main() function

I know how to solve it with return I'm in search for a new way to solve it

Ok, so if you don't want to return from your function, then you need to replace the return type with void, and then you can't use it in the assignment.

I want the printf operation take place in main() function

You can just move it there, your you use the same variable name with the global variable, so it should just work

You can just move it there, your you use the same variable name with the global variable, so it should just work

or wait, global variable was in some another code snippet, but anyway you have the same name for that array in main

#include<stdio.h> void max(int arr[], int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } int main() { int arr[7]={1,22,5,43,6,42,6}; int n=7; max(arr,n); int i; for(i=0;i<n;i++) { printf("%d ",arr[i]); } }

I want the printf operation take place in main() function

something like this I guess

I want the printf operation take place in main() function

Use another loop

Well somehow there is always a way 😂. But no, it is not supported by default, only overloading the usual operators is

You can overload operator[] for your class. It is done for a lot of STL containers https://en.cppreference.com/w/cpp/language/operators

char CNames[128]; int NumCurr = 0; int ccyIdx(char* name) { char Ccy[4]; memcpy(Ccy,name,4); Ccy[3] = 0; for(int n=0; n<32; n++) { if(!CNames[n*4]) { // not yet stored strcpy(CNames+n*4,Ccy); NumCurr++; return n; } if(strstr(CNames+n*4,Ccy)) return n; } return 0; } In the code above: Regarding if(!CNames[n*4]) What is the logic? If CNames[n*4] is not what? What am I missing?

What do you mean by custom operator, like £ operator? :) No, unfortunately it's not possible, you are right

char CNames[128]; int NumCurr = 0; int ccyIdx(char* name) { char Ccy[4]; memcpy(Ccy,name,4); Ccy[3] = 0; for(int n=0; n<32; n++) { if(!CNames[n*4]) { // not yet stored strcpy(CNames+n*4,Ccy); NumCurr++; return n; } if(strstr(CNames+n*4,Ccy)) return n; } return 0; } In the code above: Regarding if(!CNames[n*4]) What is the logic? If CNames[n*4] is not what? What am I missing?

Numbers can be implicitly or explicitly converted to bool int a = 6; bool b = a; The value of the resulting bool will be false only if the value of the integer was zero. In all other cases it will be true. So this if (!CNames[n*4]) Is equivalent to this if(CNames[n*4] == 0)

Numbers can be implicitly or explicitly converted to bool int a = 6; bool b = a; The value of the resulting bool will be false only if the value of the integer was zero. In all other cases it will be true. So this if (!CNames[n*4]) Is equivalent to this if(CNames[n*4] == 0)

Are you saying that, if nothing is stored in CNames[128], then each element inside the array of CNames has the value of 0?

Are you saying that, if nothing is stored in CNames[128], then each element inside the array of CNames has the value of 0?

If the element by that index is zero, usually that means end of c-string, or empty space after a c-string in a buffer

This code seem to iterate over chunks 4 byte each, not sure the exact logic

This code seem to iterate over chunks 4 byte each, not sure the exact logic

The goals is that, we have 32 words, and each word has 3 letters, and each word is an element. And every element needs a null terminator (so 32 ×4 =128). We are trying to give a number(index to each word)

#include <iostream> #include <string> #include <sstream> using namespace std; struct person_str { int age; void input(); void print(); }; void person_str::print() { cout<< this->age << endl; } void person_str::input(person_str*) { person_str p; cout<<"Enter age: "; cin>>p.age; } int main() { person_str p; p.input(&p); p.print(); return 0; } Hello maybe someone can explain what I do not right. Because I can't understand how it is

#include <iostream> #include <string> #include <sstream> using namespace std; struct person_str { int age; void input(); void print(); }; void person_str::print() { cout<< this->age << endl; } void person_str::input(person_str*) { person_str p; cout<<"Enter age: "; cin>>p.age; } int main() { person_str p; p.input(&p); p.print(); return 0; } Hello maybe someone can explain what I do not right. Because I can't understand how it is

You pass p to your function but not using it there, instead you create a new variable inside the functuon

The goals is that, we have 32 words, and each word has 3 letters, and each word is an element. And every element needs a null terminator (so 32 ×4 =128). We are trying to give a number(index to each word)

Sounds reasonable, I guess this code checks for the first symbol in the 3 letters and checks if that's the null terminator (then the word is not filled yet)

Oh, I think you just made it clearer. Thank you so much

You pass p to your function but not using it there, instead you create a new variable inside the functuon

Thanks

You pass p to your function but not using it there, instead you create a new variable inside the functuon

But you mean input function?

But you mean input function?

Because I trying not to make a new variable but it don't work

You pass p to your function but not using it there, instead you create a new variable inside the functuon

Sorry, I'm stupid, now everything works(thanks so much)

Can we return more than one datatype in a defined function(in c++)? Because while defining a function we have to specify a datatype too and for eg if we specify int then we can not return char or string datatypes.

Does void() function return anything?

No

Can we return more than one datatype in a defined function(in c++)? Because while defining a function we have to specify a datatype too and for eg if we specify int then we can not return char or string datatypes.

there are multiple ways to return two values: - pack them into a struct - pack them into a tuple - return second and more values through mutable reference arguments e.g. if we want to return an int and a float, we can have something like this struct: struct OurStruct { int val1; int val2; }; OurStruct ourFn() { ... OurStruct ourStruct; ourStruct.val1 = value1; ourStruct.val2 = value2; return ourStruct; } int main() { auto [value1, value2] = ourFn(); } tuple: std::tuple<int, float> ourFn() { ... return std::make_tuple(value1, value2); } int main() { auto [value1, value2] = ourFn(); } out parameter: int ourFn(float& outValue) { ... outValue = value2; return value1; } int main() { float value2; int value1 = ourFn(value2); }

How can i fix " error id returned 1 exit status"?

does anyone do leetcode

#include <iostream> using namespace std; int main() { cout << "Hello"; return 0; } But returns (error id returned 1 exist status) how can i fix this error?

#include <iostream> using namespace std; int main() { cout << "Hello"; return 0; } But returns (error id returned 1 exist status) how can i fix this error?

I may guess, the old instance of your program is still running. Windows does not allow to change the files which are currently "in use" and your linker cannot write the new .exe on the top of the running one. Try stopping/killing your program.

CppCon 2022 @ Denver Schedule (Ongoing) https://lnkd.in/gFuauGb3 Watch the recorded videos at https://www.youtube.com/user/cppcon The Friday events were live streamed. Sorry about not sharing the link earlier.

#include <stdio.h> int main() { int x,y,z; for(x=0;x<=100;x++) { for(y=0;y<=100;y++) { for(z=0;z<=100;z++) { if(5*x+3*y+z/3==100&&x+y+z==100&z%3==0); printf("%d,%d,%d",x,y,z); } } } return 0; }

Guys what's wrong with my code

#include <stdio.h> int main() { int x,y,z; for(x=0;x<=100;x++) { for(y=0;y<=100;y++) { for(z=0;z<=100;z++) { if(5*x+3*y+z/3==100&&x+y+z==100&z%3==0); printf("%d,%d,%d",x,y,z); } } } return 0; }

I don't see any problem, what problem you have with it? It doesn't compile? Or it produces unexpected results?

#include<stdio.h> void max(int arr[], int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } int main() { int arr[7]={1,22,5,43,6,42,6}; int n=7; max(arr,n); int i; for(i=0;i<n;i++) { printf("%d ",arr[i]); } }

int max(); int main() { int arr[7]={1,22,5,43,6,42,6},i; int* result=(int*)malloc(sizeof(int)); for(i=0;i<7;i++) { *(result+i)=max((arr,7); } for(i=0;i<7;i++) { printf("%d\n",*(result+i)); } } int max(int* arr,int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } Why I can't achieve my desire through this method?

int max(); int main() { int arr[7]={1,22,5,43,6,42,6},i; int* result=(int*)malloc(sizeof(int)); for(i=0;i<7;i++) { *(result+i)=max((arr,7); } for(i=0;i<7;i++) { printf("%d\n",*(result+i)); } } int max(int* arr,int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } Why I can't achieve my desire through this method?

What is your desire? :)

int max(); int main() { int arr[7]={1,22,5,43,6,42,6},i; int* result=(int*)malloc(sizeof(int)); for(i=0;i<7;i++) { *(result+i)=max((arr,7); } for(i=0;i<7;i++) { printf("%d\n",*(result+i)); } } int max(int* arr,int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } Why I can't achieve my desire through this method?

Your max declaration and definition are different

int max(); int main() { int arr[7]={1,22,5,43,6,42,6},i; int* result=(int*)malloc(sizeof(int)); for(i=0;i<7;i++) { *(result+i)=max((arr,7); } for(i=0;i<7;i++) { printf("%d\n",*(result+i)); } } int max(int* arr,int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } Why I can't achieve my desire through this method?

Your max function has int return value, but you don't return anything, this is undefined behavior

#include <stdio.h> int main() { int x,y,z; for(x=0;x<=100;x++) { for(y=0;y<=100;y++) { for(z=0;z<=100;z++) { if(5*x+3*y+z/3==100&&x+y+z==100&z%3==0); printf("%d,%d,%d",x,y,z); } } } return 0; }

Semicolon after if condition.

int max(); int main() { int arr[7]={1,22,5,43,6,42,6},i; int* result=(int*)malloc(sizeof(int)); for(i=0;i<7;i++) { *(result+i)=max((arr,7); } for(i=0;i<7;i++) { printf("%d\n",*(result+i)); } } int max(int* arr,int n) { int i; for(i=0;i<n;i++) { arr[i]=arr[i]+1; } } Why I can't achieve my desire through this method?

Your max function returns nothing here

Your max function returns nothing here

And you can't return whole array

Semicolon after if condition.

Thanks!!

I don't see any problem, what problem you have with it? It doesn't compile? Or it produces unexpected results?

I added an extra semicolon, which caused the program to keep outputting😂

https://onlinegdb.com/iwIfItEAD Hello! Maybe someone can tell me why this warning appears. Any help would be appreciated

What is your desire? :)

I want whole array as output with everyone get +1 but it didn't work as my expectation I want to solve it without any return; I want to solve it with assigning dynamic memory

https://onlinegdb.com/iwIfItEAD Hello! Maybe someone can tell me why this warning appears. Any help would be appreciated

Do you understand what that warning means?

Your max function has int return value, but you don't return anything, this is undefined behavior

I get it

Do you understand what that warning means?

Well, it seems that the function is defined to return a value, but I don't return anything with it. But I don't need to return any value, I just need to know if the check is valid or not. Or I mistaken?

hello

Well, it seems that the function is defined to return a value, but I don't return anything with it. But I don't need to return any value, I just need to know if the check is valid or not. Or I mistaken?

If not how I can make this for working correct?

I am an Angular frontend developer. I would like to print data online without going through the browser to communicate with my network printer by specifying the printer's ip. Can someone help me with a script or guide me with a package because I don't know the system environment very well?

Do you understand what that warning means?

I solved this error by adding another return at the end of the function, is this normal or wrong?

Hello. I have a hierarchy of classes, all deriving from one base. I want each of them to print a message upon creation. I don't want to call the printing method every time. https://godbolt.org/z/19dbhYj9Y Could you please help?

https://github.com/mustafakraizim98/Skyland-Coding-Challenge

Guys can you check my code

#include <stdio.h> #include <math.h> int main() { float t,p2; scanf("%f",&t); if(t<5) {p2=0;} else if(t=5) {p2=2; } else if(t>5) { t=(t-5)/5; t=ceil(t); p2=t*2; } printf("%.1f",p2); return 0; }

When t=11,p2 should be 4 right?🤔

#include <stdio.h> #include <math.h> int main() { float t,p2; scanf("%f",&t); if(t<5) {p2=0;} else if(t=5) {p2=2; } else if(t>5) { t=(t-5)/5; t=ceil(t); p2=t*2; } printf("%.1f",p2); return 0; }

t==5 in else if

t==5 in else if

Thanks😭

https://github.com/mustafakraizim98/Skyland-Coding-Challenge

Support 💐🤷‍♂️

I may guess, the old instance of your program is still running. Windows does not allow to change the files which are currently "in use" and your linker cannot write the new .exe on the top of the running one. Try stopping/killing your program.

Thanks its working now

Can someone provide me with an idea for a c++ project as i am a beginner for this and internet is providing way too complex ones . It would be helpful if this project actually helps me grow

Can someone provide me with an idea for a c++ project as i am a beginner for this and internet is providing way too complex ones . It would be helpful if this project actually helps me grow

Bank management system

Bank and hotel management, would I be able complete it within a month

Bank and hotel management, would I be able complete it within a month

You can do anything you set your mind to 👍

Bank and hotel management, would I be able complete it within a month

Yes even3 days is enough

Yes even3 days is enough

Thanks i will try it and if i get good remarks i would be grateful

Thanks i will try it and if i get good remarks i would be grateful

Yeah,Good luck buddy👍

https://onlinegdb.com/iwIfItEAD Hello! Maybe someone can tell me why this warning appears. Any help would be appreciated

Guys I realy trying to fix it but my solution didn't help. I hope someone will help

Guys I realy trying to fix it but my solution didn't help. I hope someone will help

Share the fixed code, if you've fixed the problems that we told you about

#include <stdio.h> #include <math.h> int main() { float x; int p; scanf("%f",&x); x=ceil(x); if(x<3) {p=10; } else if(3<x<=13) {p=10+2*(x-3); } else if(x>13) {p=10+2*(x-3)+3*(x-13); } printf("%d",p); return 0; }

I think something is wrong but i can't find out😐

Share the fixed code, if you've fixed the problems that we told you about

https://onlinegdb.com/mgJA54dI_A

I found on the Internet that this will help solve the problem (and there is no warning), but now the code does not work as it should

is it possible to get random element from list?

Thanks its working now

you're welcome. To be honest, I just searched for your problem on the internet and found the answer. If you have any questions, you can ask them in the group. Certainly, people with a lot of experience can help you, but don't forget that the internet is the answer to all problems.

is it possible to get random element from list?

Sure