Yes. String

Yes. String

But if I want to call a function with only one parameter I have not to pass also the size right?

Yes. But i dont know what happend after. Maybe bug, because function doesnt know string size(where '\0' character)

I have asked to my friend he said it is used to call a go function from c++

Yes it's true.

Yes it's true.

But you need to know where is located that function(address)

Thank you

#Puzzle #include <deque> #include <memory> #include <vector> struct A { // (a) removing the following line - code compiles std::deque<int> d; // (b) removing the following line - code compiles std::vector<std::unique_ptr<int>> v; // (c) adding the following line - code compiles //A(A&&) = default; // note: even without 'noexcept' // (d) adding the following line - code compiles // std::unique_ptr<int> p; A() = default; }; int main() { std::vector<A> v; // (e) removing the following line - code compiles v.emplace_back(); } The code above fails to compile. It would compile if you follow any one of the 5 instructions marked a,b,c,d and e. Why?

Hey people, I am working on a framework and here is an anonymous survey about what containers and data structures you use regularly as a developer. I would really appreciate every answer :) https://cloud.nekoit.xyz/apps/forms/wjDndPnLtNHeryqb

Do you have it as a list? can't copy from that page

Do you have it as a list? can't copy from that page

Can we change references? In cpp

When you change a reference, it is the referenced value that gets changed. You can't change a reference to make it refer to some other variable after it is initialized once. As for a reference in a range-for loop, every iteration creates a new reference. Ex: for(auto& e: vec){...} Here the reference e is a new reference that is created and initialized everytime during each iteration.

Can C++ be used for backend...

Yes

How ?

https://www.reddit.com/r/cpp/comments/afh0mo/c_backend_service_framework/

How ?

Why is it mandatory to make a default constructor in C++??

Hi there, does anyone mind explaining what the quote (') here means? int Var = 0b10111100'10111100

Why is it mandatory to make a default constructor in C++??

#include<iostream> using namespace std; class BankDeposit{ int principal; int years; float interestRate; float returnValue; public: BankDeposit(){} BankDeposit(int p, int y, float r); // r can be a value like 0.04 BankDeposit(int p, int y, int r); // r can be a value like 14 void show(); }; BankDeposit :: BankDeposit(int p, int y, float r) { principal = p; years = y; interestRate = r; returnValue = principal; for (int i = 0; i < y; i++) { returnValue = returnValue * (1+interestRate); } } BankDeposit :: BankDeposit(int p, int y, int r) { principal = p; years = y; interestRate = float(r)/100; returnValue = principal; for (int i = 0; i < y; i++) { returnValue = returnValue * (1+interestRate); } } void BankDeposit :: show(){ cout<<endl<<"Principal amount was "<<principal << ". Return value after "<<years << " years is "<<returnValue<<endl; } int main(){ BankDeposit bd3; int p, y; float r; int R; cout<<"Enter the value of p y and r"<<endl; cin>>p>>y>>r; BankDeposit bd1 = BankDeposit(p, y, r); bd1.show(); cout<<"Enter the value of p y and R"<<endl; cin>>p>>y>>R; BankDeposit bd2 = BankDeposit(p, y, R); bd2.show(); return 0; }

what do this code mean ptrStore = (_DWORD *)(*(int (**)(void))(*(_DWORD *)*ptrStore + 92))();

pov: you have a nightmare

no it is from a decompiler

oh ok now it makes sense

oh ok now it makes sense

what do this code mean ptrStore = (_DWORD *)(*(int (**)(void))(*(_DWORD *)*ptrStore + 92))();

idk but it’s possible

idk but it’s possible

it looks like a pointer to a pointer to an int function taking 0 args?

it looks like a pointer to a pointer to an int function taking 0 args?

yes

good luck with the rest

what int (**)(void) means

https://cdecl.org/?q=int+%28**a%29%28void%29

neither do i, what are you decompiling?

https://cdecl.org/?q=int+%28**a%29%28void%29

https://cdecl.org/?q=int+%28**a%29%28void%29

https://cdecl.org/?q=int+%28**a%29%28void%29

i didnt know about that site

but in the code i sent there isnt a

it is very useful for such cases, but note that I've added a variable name for it to understand

Yeah, it is pretty limited, needs a proper declaration

why if i write ptrStore = (_DWORD *)(*(int (**a)(void))(*(_DWORD *)*ptrStore + 92))(); it tells me bad charter '='

I have no idea what all that means, sorry

why if i write ptrStore = (_DWORD *)(*(int (**a)(void))(*(_DWORD *)*ptrStore + 92))(); it tells me bad charter '='

this is a function pointer definition

you can use typedef for function pointer definition