Anyone pls material on how to develop C software

What's Brain Kernighan and dennis ritchie?

int search(int* nums, int numsSize, int target){ int right, left, pivot; numsSize = strlen(nums); right = numsSize-1; left = 0; while(left <= right) { pivot = left + (right -left)/2; if(nums[pivot] == target) return pivot; if(target < nums[pivot]) right = pivot -1; else left = pivot +1; } return -1; }

P1642R11: Freestanding Library: Easy [utilities], [ranges], and [iterators] https://www.open-std.org/jtc1/sc22/wg21/docs/papers/2022/p1642r11.html

@QNeko what do you think ?

Deitel&Deitel How to program books for introduction

Please share me C++ DSA notes

Anyone know how to debug executable which compiled by msvc (Microsoft compiler) using gdb? Msvc store debugging symbols in sepatare .pdb file only and gdb can't parse them.

Hi, I just had this question for a long time abt address buses in CPUs and how we can measure our CPUs address bus width, I had read an article about the amount of supported RAM in different CPUs, and it was said that 2 to the power of the number of CPU bus address wires width(2^Address Bus Width = Addressable amout of memory by CPU). here is the question; For example an 8088 CPU that has 20 bits address bus, which is equivalent to 1,048,576 bytes although equal to 1 MB of RAM(it can address and support 1MB of RAM), even though its registers are 16 bits(So the calculations were not performed on the registers; it performed on address bus width), but a 32-bit CPU is not measured by the address bus width like 8088, it performed on 32 bit registers(vice versa) and the bits are measured is equal to 4GB, which we all know about(for those who dk, 32 bit CPUs cant address more that 4GB of Ram for example if you snap in an 8GB Ram it only supports 4GB of it!). And the 64 bit cpu is measured in the same way as 32 bit, does this mean that the 32 bit cpu has 32bit address bus width and the 64 bit cpu has 64? If this is the case, then why do 64-bit CPUs that address petabytes of RAM have a RAM support limit of less than 128GB depending on the CPU model in most cases; and if this is not the case, then why do we address the size of rigesters for amount of addressable RAM?

64-bit is the maximum capasity on a ... billion ... and never up to 128-bit that's so many long long long bit maybe trillion size i have an a article for your question 😎

64-bit is the maximum capasity on a ... billion ... and never up to 128-bit that's so many long long long bit maybe trillion size i have an a article for your question 😎

Please I need mega link data structures in c course Any help

what are mega link data structures? need more details.

what are mega link data structures? need more details.

Mega.nz is a file hosting site

Can anyone suggest me how to learn C ? Any app or some other YouTube videos ?? Note : I'm a beginner

don’t even try courses or something

what are mega link data structures? need more details.

Hi there. Why I should write: class S { static constexpr size_t size = 100; }; instead of this? class S { constexpr size_t size = 100; };

static tells that the member is static to the class, not stored in each instance. constexpr doesn't change this aspect.

But why constexpr must change this aspect?

It shouldn't

I find it strange to give a compile error

What kind of error do you get?

Invalid use of non - static data member with constexpr

Do you use it as size of c-array or template argument?

No, I use it only like in example. Maybe it depends on compiler.

#include<stdio.h> #include<conio.h> void main() { float dollar, inr, rupees; int ch; clrscr(); do { printf("\n\n* WelCome to Webeduclick Currency Converter *"); printf("\n\n 1.Rupees -> Dollar"); printf("\n\n 2.Dollar -> Ruppes"); printf("\n\n 3.Pound -> Ruppes"); printf("\n\n 4.Euro -> Ruppes"); printf("\n\n 5.Kuwaiti Dinar -> Ruppes"); printf("\n\n 6. Exit"); printf("\n\nEnter your choice = "); scanf("%d",&ch); switch(ch) { case 1:printf("\n\nEnter the currency in Rupees = "); scanf("%f",&rupees); dollar=rupees/75; printf("\n\nThe currency in dollar is = %.2f$",dollar); break; case 2:printf("\n\nEnter the currency in Dollar = "); scanf("%f",&rupees); inr=rupees*65; printf("\n\nThe currency in Ruppes is = %.2f",inr); break; case 3:printf("\n\nEnter the currency in Pound = "); scanf("%f",&rupees); inr=rupees*100; printf("\n\nThe currency in Ruppes is = %.2f",inr); break; case 4:printf("\n\nEnter the currency in Euro = "); scanf("%f",&rupees); inr=rupees*85; printf("\n\nThe currency in Ruppes is = %.2f",inr); break; case 5:printf("\n\nEnter the currency in Kuwaiti Dinar = "); scanf("%f",&rupees); inr=rupees*240; printf("\n\nThe currency in Ruppes is = %.2f",inr); break; case 6:exit(0); } } while(ch<4); getch(); }

No, I use it only like in example. Maybe it depends on compiler.

So you just declare it and not use?

You could at least format this code

Ok

Right, now I see, I didn't know that, but it seems that they can't be non-static (however I get different error) https://stackoverflow.com/questions/27408819/why-cant-non-static-data-members-be-constexpr

hello every one i've created a start condition (for string) in flex and everything works fine but when I parse the same string twice a string the elements using the start condition vanish how can i solve it ?

Can someone explain why my program doesn't work and return a strange value, please. I think it's segmentation fault, but I can't find it. Code: #include <iostream> class String { public: static constexpr size_t init_size = 100001; size_t current_size = init_size; char* string; String() { string = static_cast<char*>(malloc(init_size)); } String(const char* s) { size_t i = 0; while (s[i] != '\0') { if (i <= current_size) { string[i] = s[i]; i++; } else throw std::out_of_range("Out of range"); } } }; int main() { String sample; sample = String("hi"); //Program returned: 139 }

Try to put i++ under if(i <= current_size)

Why? At first I should consider string[0]

Why? At first I should consider string[0]

Ты знаешь русский?

No

Ok. Error is in second constructor with argument const char*. You forget allocate memory

But I did it, no? Because at first program invoke default ctor

But I did it, no? Because at first program invoke default ctor

i need help what this thing means {((unsigned char)(((int)param2)))}(ptr5, *(ptr4 + 48), param2, param3, *ptr4);

If you pass nothing (), then invokes first constructor. If you pass string(const char*), then invokes second constructor

help

i need help what this thing means {((unsigned char)(((int)param2)))}(ptr5, *(ptr4 + 48), param2, param3, *ptr4);

where is your code