ohh i get it, so whenever we any kind of loop it makes the program iteration,right?

Yep, you are right. Iteration is when the same procedure is repeated multiple times.

Hi, any recommendations for books to learn write large code base in c, i mean the process of software development, write multiple parts and link them togeter, learn build system, debugging?

But what is extern for

why C and C++ programming languages force every code be written in functions ? why the programmer isn't allowed to decide whether to write the code in function(s) or not just like in javaScript ?? what's the rationale behind C and C++ to force programmers to write code in manageable functions ?? i know its easy to read code and manage huge softwares this way but i dont think that this is the reason C and C++ force code be written inside functions. Madhu

if you are talking about top-level code, C/C++ requires an entry point, the main function, it needs to know where to start the execution

No im not talking about the main function or the entry point of a C/C++ program. i just want to know why we are forced to write every single piece of executable code inside functions in C and C++. why we aren't given the freedom to write code freely without functions like in javaScript

how i compare two sets element by for loop?

- because C/C++ is compiled to machine code and linked to libraries, it yet again requires to have a main function - it's more managable and scalable - because headers are a thing and this might lead to unexpected code execution

what compiling,linking has to do with C/C++ forcing code be written within functions ? can you give an in depth explanation sir please 😃

how do you write it without functions?

http://stackoverflow.com/questions/2796796/ddg#2796804 A good resume

I've been getting an infinite loop

But what mean naming and calling conventions

i have found this code typedef unsigned long long Out; volatile Out out,tmp; Out register rax asm("rax"); asm volatile("rdtsc":"=A"(rax)); out=out*tmp+rax; but what the double long means

as I understood, you can make your functions reusable by other languages, and to make it you need them be "callable" as C functions. So, if you write a C++ library and want to use the functions from this library, you need to make them compatible with the C calling convention (and naming). In this case you use the extern keyword.

long double is a floating point type, here's more info (it's about C++, but should be similar in C) https://en.cppreference.com/w/cpp/language/types

for ( Preset &preset : presets ) { auto presetBag = presetsBags.at ( preset -> pBagIndex ); preset -> pGeneratorIndex = presetBag.generatorIndex; preset -> pModulatorIndex = presetBag.modulatorIndex; } why do this says that preset is not a pointer

This code is not enough to see the type of preset, show how you declare presets

but it can be done also with other types

you mean the class

The variable

The variable

vector < Preset > presets;

Then preset is not a pointer, it is a reference, you should use . instead of ->

Hello guys how to embed lua in C/C++ code, have tried on Fedora and it ain't working

Then preset is not a pointer, it is a reference, you should use . instead of ->

Then preset is not a pointer, it is a reference, you should use . instead of ->

Preset * preset = &presets.at ( i );

Yes, because you take adress of it with &

Yes, because you take adress of it with &

also in the loop

No, in the loop you use it to determine that your type is reference, these are two different meanings of &

so how i get the pointer

Why do you need the pointer even?

because in that way i have not to repleace the object every time

What do you mean by "replace"?

after modifying it i have to do presets.at ( i ) = preset

Are you sure? it should directly modify the value, since it's a reference

If you didn't put & on your type, then it would be a copy and that would be needed

Preset * preset = &presets.at ( i );

why it doesnt give a pointer

Because you don't need a pointer there

also if i dont use it it doesnt work

i try without the & and i see if it modify the value without replacing

"doesn't work is very vague", can you show the code that "doesn't work" and tell what it should do?

You mean Preset instead of Preset&? You should use Preset& in the loop

You mean Preset instead of Preset&? You should use Preset& in the loop

Why

Otherwise you will get a copy, and you said you need to modify the original record

You said if i use & it give me a copy

Otherwise you will get a copy, and you said you need to modify the original record