Hey, i have a C question, i have a word that i read from keyboard, and alpfabed as a string. I need to parse the word and to find what index is each letter in alphabet string, so i came with this decision void *encode(char str[100], char alpha[26], char initialAlpha[26], size_t n) { int Index; int stringLength = strlen(str); for (int i = 0; i < stringLength; i++) { for(int j = 0; j < n; j++) { // printf("%d\n\n", strcmp(str[i], initialAlpha[j]) == 0); if (strcmp(str[i], initialAlpha[j]) == 0) { // str[i] = alpha[j]; printf("%c ", alpha[j]); } } } printf("%s", str); } but it returns nothing to me and shows that str[i] and initialAlpha[j] are char but should be Char * but when i add & in front of them error dissapear but it isn’t working as it should :c what should i do?

> char alphabet[26] = "abcdefghijklmnopqrstuvwxyz"; that's a mistake

Hey, i have a C question, i have a word that i read from keyboard, and alpfabed as a string. I need to parse the word and to find what index is each letter in alphabet string, so i came with this decision void *encode(char str[100], char alpha[26], char initialAlpha[26], size_t n) { int Index; int stringLength = strlen(str); for (int i = 0; i < stringLength; i++) { for(int j = 0; j < n; j++) { // printf("%d\n\n", strcmp(str[i], initialAlpha[j]) == 0); if (strcmp(str[i], initialAlpha[j]) == 0) { // str[i] = alpha[j]; printf("%c ", alpha[j]); } } } printf("%s", str); } but it returns nothing to me and shows that str[i] and initialAlpha[j] are char but should be Char * but when i add & in front of them error dissapear but it isn’t working as it should :c what should i do?

oh man its language c and I search solution on c++

int main() { int n = 26; char initialWord[100]; char alphabet[26] = "abcdefghijklmnopqrstuvwxyz"; char *shuffledAlphabet = shuffle(alphabet, n); printf("Initial alphabet: \n"); printArray(alphabet, n); printf("\n\nShuffled alphabet: \n"); printArray(shuffledAlphabet, n); printf("\n\nWrite word for encoding: "); scanf("%[^\n]s", initialWord); encode(&initialWord, shuffledAlphabet, alphabet, n); return 0; }

Hello everyone, I just want to clear my confusion. Why are suffixes appended on numeric or floating-point literals when the compiler already knows what kind of data they hold based on the declaration of data types? I know that appending suffixes are required in expressions, but what are the advantages of adding one in initialization? Moreover, what are the advantages of doing that aside from explicitly stating that a literal is a particular data type. I have been researching for over 30 minutes now, and I only have a general understanding of it.

I don't get it

Hello everyone, I just want to clear my confusion. Why are suffixes appended on numeric or floating-point literals when the compiler already knows what kind of data they hold based on the declaration of data types? I know that appending suffixes are required in expressions, but what are the advantages of adding one in initialization? Moreover, what are the advantages of doing that aside from explicitly stating that a literal is a particular data type. I have been researching for over 30 minutes now, and I only have a general understanding of it.

You meant when you type: float a = 2.3. You should add 'f' after 2.3? Otherwise compiler will change it to double?

yes, does the same concept applies on numeric types as well? So when I declare a variable as a long, it will be still seen as an int value instead of a long value because long is technically an integer data type still? I really just want to hear someone's thoughts to clear this annoying confusion in my head. Anyways, thank you so much!

I guess many of us can't understand it clearly)) for now, go ahead and just use it)) in the future you'll tell us why😁

sure, thanks!

Which resources d'you use for learning CPP?

yes, does the same concept applies on numeric types as well? So when I declare a variable as a long, it will be still seen as an int value instead of a long value because long is technically an integer data type still? I really just want to hear someone's thoughts to clear this annoying confusion in my head. Anyways, thank you so much!

I mean if you were referring to me

Have you read this ? https://stackoverflow.com/questions/25291351/c-and-number-suffixes#25291399

learncpp.com it's my recommendation for you. If you're English is good enough, you'll get it. Those guys often update the information. Very good explanation and examples.

do you know if there's a similar website like this but for C? Thanks btw!

I mean, for example: long x = 3000000000L; Even if I remove the 'L' suffix, it will still work the same. So what's the point of adding the 'L' suffix at the end when it doesn't make any difference at all, at least in my experience. Therefore, what are the advantages of appending suffixes in numeric literals aside from being explicit? I'm sorry if it's confusing, English is not my native language. Thanks!

That's mainly for readability. Also, it is useful when you use auto keyword. The main reason why numbers are suffixed. auto x = 3.04f; If I am checking if a floating number x is equal to 3.04 The compiler considers 3.04 as a double and return the result as false.(Since rounding of double is different from that of float). If I use if (x == 3.04f), 3.04 is considered as a float and it returns true

Can anyone explain term oop?

Sir I tried many websites or videos content to understand this concept but i didn't. Please explain as simple as possible you can.

Hiii everyone! I've a question : I want to make a game w c++. Actually rubik's cube! Somebody told me u have to install OpenGL for graphics library. Is that right ? And what's the next step. What compiler should i download for windows ...

For graphics use sfml

That's mainly for readability. Also, it is useful when you use auto keyword. The main reason why numbers are suffixed. auto x = 3.04f; If I am checking if a floating number x is equal to 3.04 The compiler considers 3.04 as a double and return the result as false.(Since rounding of double is different from that of float). If I use if (x == 3.04f), 3.04 is considered as a float and it returns true

Hello, can someone help me with this exercise please? It is a record of books that is saved in a file and they ask me that in case you want to add a book that is already added (I have to verify it by the code) the quantities to be added must be added. How can I do that function? struct tl{ char title[30]; float price; int cod,amount; }; tl book; void write(); int main (int argc, char *argv[]) { write(); getch(); return 0; } void write() { char resp; ofstream asal; asal.open("A2.txt",ios::app); if(asal==NULL) { cout<<"failed to open"; getch(); } resp='S'; while (resp=='S'|| resp=='s'){ cout<<"enter code"; cin>>book.cod; cout<<"enter amount"; cin>>book.amount; cout<<"enter price"; cin>>book.price; cin.sync(); cout<<"enter title"; cin.getline(book.title,30); asal<<book.cod<<" "; asal<<book.amount<<" "; asal<<book.price<<" "; asal<<book.title<<endl; cout<<"want to enter another? s/n"; cin>>resp; } asal.close(); }

Code without indentation，I really want them to learn Python and feel the charm of indentation

Can i define a macro by setting its value equal to a function? Something like: #ifndef INT_MIN #define INT_MIN std::numeric_limits<int>::min() #endif

Airport simulation code in c language i want can any one send me

Airport simulation code in c language i want can any one send me

Uh, why? Have you tried searching on github?

you have to do your own projects!

yeah i did i didnt find can you help me in it

ios: :sync_with_stdio(0); cin.tie(0);

ios: :sync_with_stdio(0); cin.tie(0);

Disable sync with C stream and doesn't flush ostream before getting input from istream

Somebody please tell me , what does it mean?

They do two different things: std::ios_base::sync_with_stdio(false) This will disable the synchronization between C and C++ streams. After disabling the sync, you can no longer mix cout and printf and expect correct results. std::cin.tie(nullptr) By default, cin is tied to cout. this means that before cin does something, it will flush cout. This command will disable that. so std::cout << 12; std::cin >> a; may ask for your input before printing anything. Both of these can lead to IO performance improvements.

Input/output can be a performance bottleneck in C++ programs. By default, the standard iostreams (cin, cout, cerr, clog, and their wide-character counterparts) are synchronized with the C stdio streams (stdin, stdout, stderr), so that reads from cin and stdin, or writes to cout and stdout, can be freely intermixed. However, this coupling has a performance cost, because of the buffering in both kinds of streams. In the pre-standard "classic" iostreams library, unsynchronized mode was the default. If there is no need for a program to make calls to both standard C streams and C++ iostreams, synchronization can be turned off with this line of code: std::ios_base::sync_with_stdio(false); If any input or output operation has occurred using the standard streams prior to the call, the effect is implementation-defined. Otherwise, called with a false argument, it allows the standard streams to operate independently of the standard C streams (§IS-27.4.2.4). Another standard default is to flush all output to cout before reading from cin, for the purpose of displaying interactive prompts to the application user. If this synchronized flushing is not needed, some additional performance can be gained by disabling it: std::cin.tie(0); Ref: https://www.stroustrup.com/Performance-TR.pdf

memset one, but that all is unsafe in some terms