can I ask java problem here?

no

ok, do you know a place where I can

any solution to it? if i remove it i wont get the right answer in other numbers

check if the array is not empty

ok, do you know a place where I can

a java group

check if the array is not empty

its not, i tried replacing array too. maybe d stands for something?

paste a return 1; after the printf

sorry does (enter) key included as an input?

 I am trying to return true if a sub-array exists at given index (idx), false otherwise. For example: if idx = -1, return false since data[-1] is out of bounds * if idx = 0, return true since data[0] refers to the first sub-array * if idx = 1, return true since data[1] refers to the second sub-array * ... * if idx = data.length - 1, return true since data[data.length - 1] refers to the last sub-array * if idx = data.length, return false since data[data.length] is out of bounds */

ooh thank you everyone, now i find the solution. instead of if(strlen(str) == 0) its work with if(strlen(str) < 2) because enter was still input after all 😅 thank you @coalio @freakyLuffy @K11M1

O(n)?

determine the time function T(n) of the program then you can find the function complexity

what's the purpose of empty templates? template<> int myfunction() { return 10; } i can't seem to find any good explanation online

If I'm not mistaken it's a full template specialization, basically you define a specialization for the specific types and it will be compiled as a normal function in a sense (compiled for a translation unit and then linked) https://en.cppreference.com/w/cpp/language/template_specialization

you need to count the total time your program would take in terms of the input. So if input is larger the time is larger. You don't use seconds for time tho since its different on each machine, instead you use a constant c ( you suppose each statement in your program takes constant amount of time call it c) for example for( i=0;i<n;i++){ count<<i;} count<<i; is one statement and it takes C as time but since there is a for loop so its gonna be repeated n times ( the input number) when n is larger the time taken is larger so your function T(n) = Cn. now you can find the function complexity , complexity is applied on functions not programs . there is a constant g so that g.T(n) upperbounds T(n) since for any function of order n you can always find a constant such that that constant times the function upperbounds your original function and O(n) is the class of functions that are upperbounded by some multiple of n and other functions that upperbound it for all constants >0 so for example 0.00001 n^2 will upperbound 1000n+2 eventually when n gets large

@mtermu

you can graph 0.00001 n^2 and 1000n+2 and see that 0.00001 n^2 will eventually upperbound it

what's the purpose of empty templates? template<> int myfunction() { return 10; } i can't seem to find any good explanation online

Example for what I said above https://wandbox.org/permlink/e7rECXuEDuNO6FGq

yeah about what

If I'm not mistaken it's a full template specialization, basically you define a specialization for the specific types and it will be compiled as a normal function in a sense (compiled for a translation unit and then linked) https://en.cppreference.com/w/cpp/language/template_specialization

i see, this answers my question, thanks!

I have 3 problems that i am not able to solve

Can someone help me with them?

Hash code hints do

Plsz

I have 3 problems that i am not able to solve

They are my practice problems that we are given

I tried solving them but not able to get the correct output

I tried solving them but not able to get the correct output

Are source bhej bhai

Source code*

bwoah, now its segmentation fault. need your help bro pastebin.com/SvWyqThj

Does anyone have c++ notes that he made?

Are class and struct only different in the default visibility? Or are there more differences?

Are class and struct only different in the default visibility? Or are there more differences?

technically only that and also when inheriting from structs, it's public inheritance by default However programmers often use structs to denote bunches of related data and in contrast classes as S.O.L.I.D. OOP classes

Can anyone explain what the benefits of operator Overloading and how it work

I have a problem with a very large two-dimensional matrix, and segmentation faults (core dumped), they told me that it is possible to solve it by dynamically allocating the memory, with malloc, I have found various solutions on StackOverflow but to no avail. Would anyone know how to help me?

We are talking about 25 / 30mbyte

I will try with that. Thank you. strangely, in my header file, it says that #include <string> file not found. :/ But the same code line is working in .cpp extension.

Because string header is exist on C++, not C

bwoah, now its segmentation fault. need your help bro pastebin.com/SvWyqThj

malloc is allocating uninitialized memory, but you pass it into strlen, an UB has occurred. I think you should use calloc since calloc is also initialize all the memory into zero

Because string header is exist on C++, not C

gcc compiles both C and C++

and the op is using it for C++

malloc is allocating uninitialized memory, but you pass it into strlen, an UB has occurred. I think you should use calloc since calloc is also initialize all the memory into zero

wow didnt expect that thank you

malloc is allocating uninitialized memory, but you pass it into strlen, an UB has occurred. I think you should use calloc since calloc is also initialize all the memory into zero

but if i could just made with static memory since i just need 10 character input

A dynamic array is an array whose size is only known during the runtime of a program. You can use the following two functions, malloc() or calloc() to define dynamic arrays. A strict sawtooth array is an array where the values of the sequence of elements should follow the up-down principle. The successive elements of the array should not be the same. The suc- cessive differences across the array should follow alternate +ve and -ve values. For example (1,4,2,5,4,8,6,10,9) and (-10,-15,0,-2,6,3) are strict sawtooth arrays of size 9 and 6, respectively, but (1,5,7,3,6) and (34,23,23,44) are not strict sawtooth arrays. In this program you have to use the concept of dynamic arrays to perform the following tasks with respect to sawtooth arrays. • Prompt the user to enter the size of the array as ‘n’. Declare a dynamic integer array of the same size. • Take input ‘n’ different integers into the array from the keyboard. • Check if the array is a sawtooth array or not. Use the function int isSawtooth(int *) that takes as argument a pointer to the array and returns 1 if the array is sawtooth, otherwise it returns 0. Print the appropriate message on the console. • If the array is NOT a sawtooth array, then find out the first position in the array where the sawtooth condition is violated. Use the function void position(int *, int *) which takes in two pointer arguments, first one is the pointer to the array and the second one a pointer to another integer variable declared in main. The position where the sawtooth condition is violated is written into the variable pointed by the second argument (Note that this function should NOT return the position). Also this function should be called only if the array is not sawtooth. 1 • The program then frees the dynamic array created. It asks whether the user wants to continue again or not. It prompts the user to input ‘Y’ (for Yes) or ‘N’ (for No) to continue the program. If ‘Y’ is entered, then the steps are repeated again and if ‘N’ is entered, the program exits. The array has to be dynamically allocated each time the program runs.

help me with this problem

in this I am not able to find the position function

gcc compiles both C and C++

gcc and g++ are diffrent i think. Maybe the OP compile C++ using gcc but he/she forgor to give -lstdc++ parameter

I am trying to solve my assignment but it is too hard please can you solve it the assignment is to input a number between 100 and 999 using c++ Thank you😍

I am trying to solve my assignment but it is too hard please can you solve it the assignment is to input a number between 100 and 999 using c++ Thank you😍

no

Why

Why

Because it's easy

I am trying to solve my assignment but it is too hard please can you solve it the assignment is to input a number between 100 and 999 using c++ Thank you😍

What is hard about it?

First time learning c++

I only know if and else

They said to me to use loop 😟

your request doesn't sound that you want to learn. it seems that you just want us to make the work instead of you

No bro

but if i could just made with static memory since i just need 10 character input

Yeah you can, but don't forgot to initialize the array to zero type arr[x] = {0} The first until the end of the array are initialized to zero

They said to me to use loop 😟

Have you tried googling it?

Loop is in basic programming

Loop is in basic programming

First time learning about language

First time learning about language

prioritize learning in documents and in google instead of asking people to solve your problems

if you have questions because you tried to solve it but you have an error, then you can ask

but you also have to engineer the function by yourself, especially in something so simple that you could find it in google in 10 minutes

pls what frame work is good gor c++ GUI

pls what frame work is good gor c++ GUI

sdl2

gtk, qt, imgui

pls what frame work is good gor c++ GUI

Qt or GTK

lol

Okay, thank you guys

Hi. I'm trying to use SDL2 as a dependency in Meson, but linking fails because it can't find SDL2.lib.

at the end of compilation, it says LINK : fatal error LNK1181: can't open input file 'subprojects\SDL2-2.0.18\sdl2.lib'

Is there anyone who can help me with this problem 😐 Suppose😷 you have a cubic shaped container full of water and the height of that container is h. You accidentally dropped a metallic ball that has a radius of r (where r<h) and v volume of water overflowed from the container. Write a C program that takes h and r as input and displays the volume of water that overflowed. Sample input: 10 5 Sample output: 607.30

Am just a biginner Thanks in advance

Am just a biginner Thanks in advance

you have just posted your assigment, but not your problem

you have just posted your assigment, but not your problem

Can u help me with that😢 Or where I can find this types of problems+solution to Practice??

Can u help me with that😢 Or where I can find this types of problems+solution to Practice??

problems and solutions? hm... maybe some book or sites like leetcode? maybe? idk i haven't needed solutions

if i needed some snippet of code i used google

Is there anyone who can help me with this problem 😐 Suppose😷 you have a cubic shaped container full of water and the height of that container is h. You accidentally dropped a metallic ball that has a radius of r (where r<h) and v volume of water overflowed from the container. Write a C program that takes h and r as input and displays the volume of water that overflowed. Sample input: 10 5 Sample output: 607.30

Find a formula for that problem first , then you can write a code easily.

Yeah you can, but don't forgot to initialize the array to zero type arr[x] = {0} The first until the end of the array are initialized to zero

thank you

i have written a code, to convert digit into words to 1-100 i wanna make it infinity like if user input 3000, 4560? also when i write 30 it return 30 d

#include<iostream> using namespace std; int main() { int number,a1,a2; char array1[][10]={"one","two","three","four","five","six","seven","eight","nine","ten"}; char array2[][10]={"eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"}; char array3[][10]={"twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninty","hundred"}; cin>>number; { if(number<0) cout<<"the number is negative number"; else if(number>0 && number<=10) cout<<"the number is "<<array1[number-1]; else if(number>10 && number<20) cout<<"the number is "<<array2[number-11]; else if(number>=20 && number<=100) a1=number/10; a2=number%10; cout<<"the number is "<<array3[a1-2]<<" "<<array1[a2-1]; } return 1; }

can someone help me here?

i have written a code, to convert digit into words to 1-100 i wanna make it infinity like if user input 3000, 4560? also when i write 30 it return 30 d

parse it as an int and convert to string using itoa (edit: this was a quick glance, i just read your code and i see that's not what you meant)

#include<iostream> using namespace std; int main() { int number,a1,a2; char array1[][10]={"one","two","three","four","five","six","seven","eight","nine","ten"}; char array2[][10]={"eleven","twelve","thirteen","fourteen","fifteen","sixteen","seventeen","eighteen","nineteen"}; char array3[][10]={"twenty","thirty","fourty","fifty","sixty","seventy","eighty","ninty","hundred"}; cin>>number; { if(number<0) cout<<"the number is negative number"; else if(number>0 && number<=10) cout<<"the number is "<<array1[number-1]; else if(number>10 && number<20) cout<<"the number is "<<array2[number-11]; else if(number>=20 && number<=100) a1=number/10; a2=number%10; cout<<"the number is "<<array3[a1-2]<<" "<<array1[a2-1]; } return 1; }

you cant make it infinite, but you can restructure this so it looks nicer