// { Driver Code Starts #include<bits/stdc++.h> using namespace std; // } Driver Code Ends class Solution { public: string FirstNonRepeating(string A){ // Code here } }; // { Driver Code Starts. int main(){ int tc; cin >> tc; while(tc--){ string A; cin >> A; Solution obj; string ans = obj.FirstNonRepeating(A); cout << ans << "\n"; } return 0; } // } Driver Code Ends

If i want to implement a double linked list using oops how would I do that

May i ask what are oops?

May i ask what are oops?

May i ask what are oops?

// A C++ program to find first // non-repeating character // from a stream of characters #include <iostream> #define MAX_CHAR 256 using namespace std; // A linked list node struct node { char a; struct node *next, *prev; }; // A utility function to append a character x at the end // of DLL. Note that the function may change head and tail // pointers, that is why pointers to these pointers are // passed. void appendNode(struct node** head_ref, struct node** tail_ref, char x) { struct node* temp = new node; temp->a = x; temp->prev = temp->next = NULL; if (*head_ref == NULL) { *head_ref = *tail_ref = temp; return; } (*tail_ref)->next = temp; temp->prev = *tail_ref; *tail_ref = temp; } // A utility function to remove a node 'temp' from DLL. // Note that the function may change the head and tail pointers, // that is why pointers to these pointers are passed. void removeNode(struct node** head_ref, struct node** tail_ref, struct node* temp) { if (*head_ref == NULL) return; if (*head_ref == temp) *head_ref = (*head_ref)->next; if (*tail_ref == temp) *tail_ref = (*tail_ref)->prev; if (temp->next != NULL) temp->next->prev = temp->prev; if (temp->prev != NULL) temp->prev->next = temp->next; delete (temp); } void findFirstNonRepeating() { // inDLL[x] contains pointer to // a DLL node if x is present // in DLL. If x is not present, then inDLL[x] is NULL struct node* inDLL[MAX_CHAR]; // repeated[x] is true if x is repeated two or more // times. If x is not seen so far or x is seen only // once. then repeated[x] is false bool repeated[MAX_CHAR]; // Initialize the above two arrays struct node *head = NULL, *tail = NULL; for (int i = 0; i < MAX_CHAR; i++) { inDLL[i] = NULL; repeated[i] = false; } // Let us consider following stream and see the process char stream[] = "geeksforgeeksandgeeksquizfor"; for (int i = 0; stream[i]; i++) { char x = stream[i]; cout << "Reading " << x << " from stream \n"; // We process this character only if it has not // occurred or occurred only once. repeated[x] is // true if x is repeated twice or more.s if (!repeated[x]) { // If the character is not in DLL, then add this // at the end of DLL. if (inDLL[x] == NULL) { appendNode(&head, &tail, stream[i]); inDLL[x] = tail; } else // Otherwise remove this character from DLL { removeNode(&head, &tail, inDLL[x]); inDLL[x] = NULL; repeated[x] = true; // Also mark it as repeated } } // Print the current first non-repeating character // from stream if (head != NULL) cout << "First non-repeating character so far " "is " << head->a << endl; } } /* Driver code */ int main() { findFirstNonRepeating(); return 0; }

// { Driver Code Starts #include<bits/stdc++.h> using namespace std; // } Driver Code Ends class Solution { public: string FirstNonRepeating(string A){ // Code here } }; // { Driver Code Starts. int main(){ int tc; cin >> tc; while(tc--){ string A; cin >> A; Solution obj; string ans = obj.FirstNonRepeating(A); cout << ans << "\n"; } return 0; } // } Driver Code Ends

#include<iostream> #include<stdlib.h> #include<ctype.h> #include<string.h> #define SIZE 50 using namespace std; struct STACK { char a [SIZE]; int top; }; typedef stuct STACK stack; void initialize (stack*s); void push (stack*s,char token); char pop (stack*s); int priority (char token); void intopost (stack*s,char infix[]); int main { char infix [SIZE]; stack s; system("CLS"); cout<<"\n\n Enter infix expression:"; cin>>infix; intopost(&s,infix); return 0; } void initialize(stack*s) { s->top= -1; } void push(stack*s,char token) { if(s->top!=SIZE-1) { s->top++; s->a[s->top]=token; } } char pop (stack*s) { char token; if(s->top!=-1) { token=s->a[s->top]; s->top--; return token; } return 0; } { int pri; switch(token) { case'^': pri=3; break; case'*': case'/': case'%': pri=2 break; case'+': case'-': pri=1; break; pri=0; default: } return pri; } { char postfix[SIZE],token; int i=0; j=0; length=0; initialize(s); push(s,'#'); length=strlen(infix); for(i=0; i<length; i++) { if(token=='(') { push(s,token); } else if (isalnum(token)) { postfix[j]=token; j++; } else if (token==')') { while(s->a[s->top]!='(') { postfix[j]=token; j++; } s->top--; } else { while(priority(s->a[s->top])>= priority(token)) { postfix[j]=pop(s); j++; } push(s,token); } while((token=pop(s))!='#') { postfix[j]= token; j++; } postfix[j]='10'; cout<<"\n\n The postfix Expression is"<<postfix; }

Implement linked list using object oriented programming language

oh the s made me think that you meant something else

Write a program in C to get input time in second and convert it into Hours, minute and second..

Write a program in C to get input time in second and convert it into Hours, minute and second..

1 #include<stdio.h> 2   3 void timeConversion(int seconds){ 4 double hours, minutes; 5   6 hours = seconds / 3600.0; 7 minutes = seconds / 60.0; 8   9 printf("%ds is %.5lfhr and %.5lfmin", seconds, hours, minutes); 10 } 11   12 int main(){ 13   14 int seconds; 15 printf("Enter the time in Seconds:"); 16 scanf("%d", &seconds); 17   18 timeConversion(seconds); 19 }

I would make 3600.0 and 60.0 a const

If I input 3600 to your code, it won't output 1 hour, it will output 1 hour and 60 minutes

It have me 1hour sir

If I input 3600 to your code, it won't output 1 hour, it will output 1 hour and 60 minutes

Enter the time in Seconds:3600 3600s is 1.00000hr and 60.00000min It would print exactly this on ur shell

He said convert minutes to hours and minutes 3600 minutes is 1hr and also 60 minutes

Also time.h is not a library, just a header

What does =a mean in the context of the asm macro in GCC C?

iirc, GCC uses AT&T syntax. Which means, source = destination. Eg: 5 = a instead of a := 5 like in x86 or RISC or newer asm languages

What does =a mean in the context of the asm macro in GCC C?

For what we use the % in c++ ?

hi i cant understand where i did wrong in this code but it not working can anybody help?

#include <iostream> #include <time.h> #include <stdlib.h> using namespace std; int main() { int kullanici, rasgele; cout << "Lutfen Tahmininizi Giriniz(1-6) -> "; cin >> kullanici; cout << endl; if (kullanici <= 10 && kullanici >= 1) { srand(time(NULL)); rasgele = rand() % 6 + 1; } if (rasgele == kullanici) { cout << "Tahmininiz Dogru!" << endl; } else { cout << "Tahmininiz Yalnıs!"; cout << "Aslında Sonuc ->" << rasgele << endl; } else { cout << "Lutfen Verilen Araliklarda Giriniz" << endl; } }

#include <iostream> #include <time.h> #include <stdlib.h> using namespace std; int main() { int kullanici, rasgele; cout << "Lutfen Tahmininizi Giriniz(1-6) -> "; cin >> kullanici; cout << endl; if (kullanici <= 10 && kullanici >= 1) { srand(time(NULL)); rasgele = rand() % 6 + 1; } if (rasgele == kullanici) { cout << "Tahmininiz Dogru!" << endl; } else { cout << "Tahmininiz Yalnıs!"; cout << "Aslında Sonuc ->" << rasgele << endl; } else { cout << "Lutfen Verilen Araliklarda Giriniz" << endl; } }

please show us the error so we can inspect it

'{': no matching token was found

Oh, I see. I think it might be because you have two else clauses on the last if statement

Ah, its if inside if

1 #include<stdio.h> 2 #include<math.h> 3   4 void printVoltage(double t){ 5   6 // decleration and assignment of constants 7 const int BATTERYVOLTAGE = 100; 8 const int RESISTEANCE = 1000; 9 const double CAPACITANCE = 0.5; 10 double voltage; 11   12 // compute voltage across capacitor 13 voltage = BATTERYVOLTAGE * (1 - exp(-1)); 14   15 // display in tabular form 16 printf("Time(s) \t\t Voltage(v)"); 17 printf("\n%lf \t\t %lf ", t, voltage); 18   19 } 20 int main(){ 21     double t; 22     t = 0; 23     // call function printVoltage 24     printVoltage(t); 25     t += 0.5; 26     printVoltage(t); 27     t += 0.5; 28     printVoltage(t); 29     t += 0.5; 30 }