Da

//#include "circle.h" #include <iostream> using namespace std; int main() { int x,y,r; cin>>x>>y>>r; Circle c(x,y,r); int cx,cy; c.getO(cx,cy); cout<<cx<<' '<<cy<<endl; cout<<c.getR()<<endl;

#include "circle.h" #include<iostream> using namespace std; void Circle::getO(int &cx,int &cy) { cx=x; cy=y; } int Circle::getR() { return r; } void Circle::move(int move_x,int move_y) { x+=move_x; y+=move_y; } void Circle::setR(int new_r) { r=new_r; }

#ifndef CIRCLE_H_INCLUDED #define CIRCLE_H_INCLUDED class Circle { private: int x; int y; int r; public: Circle(int _x,int _y,int _r){x=_x;y=_y;r=_r;} //~Circle(); void getO(int &cx,int &cy); int getR(); void move(int move_x,int move_y); void setR(int new_r); }; #endif // CIRCLE_H_INCLUDED

why can't my program run?

can some expert help me?

//#include "circle.h" #include <iostream> using namespace std; int main() { int x,y,r; cin>>x>>y>>r; Circle c(x,y,r); int cx,cy; c.getO(cx,cy); cout<<cx<<' '<<cy<<endl; cout<<c.getR()<<endl;

you're missing a brace

that's part of the program

but the error happens there

the error is :undefined reference to Circle::get0(int&,int&)

getO is declared but not defined

probably a linker error

are you sure you're including your headers and sources when compiling it?

are you sure you're including your headers and sources when compiling it?

thank you so much ,you're so fucking smart

thank you so much ,you're so fucking smart

oh its just that it has happened to me so many times before lol

Can you all

Guide

h m m m m m m

what kind of..

Me for c++ I am a beginner

i see

Any suggestions

have you tried...

Yess

googling

I now a little

Any suggestions

yeah dont give up

Bit

C++ is a rich feature language, but you dont need to know everything to use it

Yeah that's why I come

I recommend you to start a little project, if you don't know how to do something, you can always google it

how good are you in programming in general?

are you an absolute beginner or you know other language already

No bubby I am a beginner

I started this from one week

hmmm, i recommend you to make a codingame account

there's many easy puzzles to solve if you're a beginner

and if you get stuck you can always google how to do it

Give me

I recommend you to watch some tutorials, because you might need guidance

Give me

codingame.com (im not affiliated with thid website im recommending it from my personal experience)

I recommend you to watch some tutorials, because you might need guidance

for example, you can set a study plan from monday to friday and solve puzzles in the weekends

Thank you

you're welcome

if you have questions or you're stuck feel free to dm me

Ok

It's trusted

Hey guys I'm still confused about This incremental thing Int i; ++i ; i++ ; Thier d/ce

++i: return the increased value and increase it

i++: increase value and return original

👍

int i = 1; printf("%d", ++i); // 2 printf("%d", i++); // 1

This code may cause misunderstanding

`` int a = 1; printf("%d", ++a); // 2 int b = 1; printf("%d", b++); // 1 ``

i++: increase value and return original

Well actually, i++ means return the value of i and then increment. ++i means increase the value of i and then return.

Well actually, i++ means return the value of i and then increment. ++i means increase the value of i and then return.

isnt that exactly what i said but phrased differently

yes it is.

well nice

i++: increase value and return original

But you said original value, that could mean it is doing the act of incrementing and then keeping the original value...

`` int a = 1; printf("%d", ++a); // 2 int b = 1; printf("%d", b++); // 1 ``

yeah you're right, i actually meant the printf as separate tests and not sequential statements

But you said original value, that could mean it is doing the act of incrementing and then keeping the original value...

increase value and return original doesn't mean return increased and keep original

thats a misunderstanding from your part

increase value and return original doesn't mean return increased and keep original

Then how would it return the "original" value if it didn't keep it?

int a = 1; int original = a; return ++original; ?

a return statement is completely independent from the value of the variable

original refers to the original value

a return statement is completely independent from the value of the variable

I was just saying, they way you put your statement is bit confusing... i++, means return the value and increment later... ++i means increment the value first and then return it...

because value is incremented after returning

I was just saying, they way you put your statement is bit confusing... i++, means return the value and increment later... ++i means increment the value first and then return it...

you just had a misunderstanding

but if it was confusing then thanks for the clarification

I was just saying, they way you put your statement is bit confusing... i++, means return the value and increment later... ++i means increment the value first and then return it...

Ehem...are you sure?

Ehem...are you sure?

Are you not?

Are you not?

Prefix incrementation has more priority

Prefix incrementation has more priority

Yes and in i++ happens after the value is returned... not before it.

Yes and in i++ happens after the value is returned... not before it.

So read what u wrote

Prefix incrementation has more priority

Sorry I understand what you mean, corrected it.

Sorry I understand what you mean, corrected it.

Ok, np

🙏 @MissRose_bot

Hi guys, could someone give an idea how to implement such thing 1 1 1 1 1 1 1 0 1 1 1 1 1 0 0 0 1 1 1 0 0 0 0 0 1 0 0 0 0 0 1 1 1 0 0 0 1 1 1 1 1 0 1 1 1 1 1 1 1 in 2D array? I tried to do that here, but it was unsuccessful #include <stdio.h> #define n 7 void print(int a[n][n]) { for(int i = 0; i < n; i++) { printf("\n"); for(int j = 0; j < n; j++) { printf("%d ", a[i][j]); } } } void main() { int a[n][n] = { 0 }; for(int i = 0; i < n; i++) { for(int j = 0; j < n; j++) { a[7-j][j] = 1; } } print(a); }

Hi everyone. I have a problem. I can find -74 but i dont know how to swipe big matris to right. Can you help me please. I cant send pic. Lets think matris1 is 21 19 17 25 28 71 76 73 68 59 153 164 157 155 200 201 190 185 180 205 210 215 230 232 Matris 2 -1 -1 -1 -1 8 -1 -1 -1 -1 First we multiple matris1 * matris2 but size is matris2size then we have to do swipe right. Like we multiple 19*-1 +17*-1+ 25 *-1 + 76*-1+73*8+ 68*-1+ 164*-1+164*-1+157*-1 I hope you guys understand. I cant share pic. So sorry.