you'd need some quite complex processing to make it work your own.

the same applies to old stuff like GTK+ (which supports a subset of CSS)

I tried it and it gives me an error: P.S. Sorry, I should have mentioned it earlier, parse_subsequence is prototyped like this: int parse_subsequence(const char **format, va_list args) Error: ft_printf.c:91:27: error: cannot take the address of an rvalue of type 'const char *' n += parse_subsequence(&++format, args);

It should still work unless you made a mistake somewhere else.

It should still work unless you made a mistake somewhere else.

it can't work &++pointer is like &324242 which doesn't reside in a memory cell

because, as the compiler states, *pointer is definitely a rvalue (because you used ++)

it can't work &++pointer is like &324242 which doesn't reside in a memory cell

#include <iostream> void func(const char** ptr){ std::cout << *ptr << std::endl; } int main() { const char* ptr = "hello"; func(&++ptr); return 0; }

#include <iostream> void func(const char** ptr){ std::cout << *ptr << std::endl; } int main() { const char* ptr = "hello"; func(&++ptr); return 0; }

I'm using C

Or there's no diff?

I'm using C

shouldn't be an issue

#include <iostream> void func(const char** ptr){ std::cout << *ptr << std::endl; } int main() { const char* ptr = "hello"; func(&++ptr); return 0; }

wait ++pointer makes pointer, not long ?

I'm using C

Doesn't matter. The pre-increment operator does not return a rvalue. It returns a lvalue

wait ++pointer makes pointer, not long ?

You should read about pointers.

Doesn't matter. The pre-increment operator does not return a rvalue. It returns a lvalue

Okay, I'll have to do some reading on that

Qt parses and compiles CSS and draws to GDI/GLUT contexts based on OS, frame type (window) and shape (and other variables. I don't know if Qt draws directly on framebuffer, but I know it will use OpenGL whenever possibile)

I want to make a gui without the need for any framework. Is this possible with assembly language or if there is another way, please help me

Because I'm losing the sense on lvalue and rvalue... and thanks for your help :)

You should read about pointers.

int main() { const char* ptr = "hello"; func(&(+ptr)); return 0; } Shouldn't this work too then?

int main() { const char* ptr = "hello"; func(&(+ptr)); return 0; } Shouldn't this work too then?

The unary + does not return a lvalue

Because I'm losing the sense on lvalue and rvalue... and thanks for your help :)

C/C++ syntax is: lvalue = rvalue

The unary + does not return a lvalue

ohhhh I see what you mean

C/C++ syntax is: lvalue = rvalue

No.

No.

what's wrong about that?

what's wrong about that?

const int a = 10; a = 5; //error Here a is an lvalue but it can't be on the left side of an assignment

const int a = 10; a = 5; //error Here a is an lvalue but it can't be on the left side of an assignment

well because it's const

well because it's const

But you said lvalues can be on LHS of assignment operators. It is wrong because I gave you an example where it can't be

But you said lvalues can be on LHS of assignment operators. It is wrong because I gave you an example where it can't be

the fact that you can't assign to a const doesn't mean that const is not a lvalue

a is a lvalue, just it's const so you can't assign to it

the fact that you can't assign to a const doesn't mean that const is not a lvalue

I never said it is. You did by saying lvalue = rvalue

I never said it is. You did by saying lvalue = rvalue

ah, I meant expressions, not specifically an assignment

I wanted to put it like in Math

left side of equation and right side

I thought it was the quickest way to explain it

ah, I meant expressions, not specifically an assignment

That is wrong still. In a = 5; a on LHS is a lvalue expression that can't be assigned to. Lvalue refers to expressions that have both an identity and value. Rvalue refers to expressions that have just a value but not identity. In C++, it is slightly more muddled with lvalues, glvalues, xvalues, rvalues and prvalues

That is wrong still. In a = 5; a on LHS is a lvalue expression that can't be assigned to. Lvalue refers to expressions that have both an identity and value. Rvalue refers to expressions that have just a value but not identity. In C++, it is slightly more muddled with lvalues, glvalues, xvalues, rvalues and prvalues

why do you say that? int a = 5; a = 7; maybe I'm not getting what you're trying to say

why do you say that? int a = 5; a = 7; maybe I'm not getting what you're trying to say

I was referring to a where it is defined as a const int and not a plain int

what is lvalue rvalue gvalue prvalue??

I was referring to a where it is defined as a const int and not a plain int

Ah I see. Yes, in that case I agree

what is lvalue rvalue gvalue prvalue??

Look it up on google

aha okay thanks

Team mate, greetings to you all. I'm a nubby in programming. The gave us an assignment to write a mini calculator using functions for -, +, /, *, ln, exponential and log

I need help please

I need help please

What kind of help you need?

Team mate, greetings to you all. I'm a nubby in programming. The gave us an assignment to write a mini calculator using functions for -, +, /, *, ln, exponential and log

You need to learn the language then

It's like, the very basics.

I need help please

Try yourself first

If they are stuck or have question its okay to ask tho ¯\_ (ツ) _/¯

How to create an html file

How to create an html file

Start Microsoft Word. In the New Document task pane, click Blank Web Page under New. On the File menu, click Save. NOTE: The Save as type box defaults to Web Page (*. htm; *. html). In the File name box, type the file name that you want for your document, and then click Save.

How to create an html file

Open an editor such as Notepad or VS code. Write something, then save it as filename.html The .html should be there.

Chinnu love to play games, one day Chinnu played a game in which she was given 'n' number of bits, where initially all bits are 0. Assume that the position of bits starts from 1 to n. Now, Chinnu has to traverse the bits 'n' times and flip in the following manner: -> While traversing 1st time, flip the bits which are in the position multiple of 1. -> While traversing 2nd time, flip the bits which are in the position multiple of 2. -> While traversing 3rd time, flip the bits which are in the position multiple of 3 and so on till 'n' times. Filp means if the bit is 0 flip it and make it 1 and if the bit is 1 flip it and make it 0. The task is to print number of 1's and 0's after 'n' traversals. For example assume that n=5, then the bits are initially 0 0 0 0 0 1st traversal -> 1 1 1 1 1 ( all positions are multiple of 1. i.e, filp all bits) 2nd traversal -> 1 0 1 0 1 ( positions 2 and 4 are multiple of 2. i.e, flip bits in position 2 and 4) 3rd traversal -> 1 0 0 0 1 ( position 3 is multiple of 3. i.e, flip bit in position 3) 4th traversal -> 1 0 0 1 1 ( position 4 is multiple of 4. i.e, flip bit in position 4) 5th traversal -> 1 0 0 1 0 ( position 5 is multiple of 5. i.e, flip bit in position 5) After n traversals, the bits are 1 0 0 1 0. Here Number of 1's = 2 and Number of 0's = 3.

https://github.com/rby90/Project-Based-Tutorials-in-C

thought that said project-based-tutorials-in-A

because `GitHub - rby90/project-based-tutorials-in-c: A `

thought that said project-based-tutorials-in-A

Well, afaik there was only a B language, which has hobby compilers still, but not an A language lol.

lol

guys can anyone tell me

why this gives an error cout«arr[]; //if i have created an array arr[]=[1,2,3,4,5]; like this

why this gives an error cout«arr[]; //if i have created an array arr[]=[1,2,3,4,5]; like this

Are you using C++ or NodeJS? You have to tell C++, which element of array you want to display, it'll not do it for you... int main() { int a[] = {1,2,4,5,6}; int size = sizeof(a)/sizeof(a[0]); cout<<size<<endl; for (int i = 0; i <= size-1; i++) cout<<a[i]; return 0; }

why this gives an error cout«arr[]; //if i have created an array arr[]=[1,2,3,4,5]; like this

https://www.google.com/amp/s/www.geeksforgeeks.org/arrays-in-c-cpp/amp/

why this gives an error cout«arr[]; //if i have created an array arr[]=[1,2,3,4,5]; like this

Obviously it will give error

Either u have to specify which of the array u want to print

Or u have to use the for loop to print the whole array

Are you using C++ or NodeJS? You have to tell C++, which element of array you want to display, it'll not do it for you... int main() { int a[] = {1,2,4,5,6}; int size = sizeof(a)/sizeof(a[0]); cout<<size<<endl; for (int i = 0; i <= size-1; i++) cout<<a[i]; return 0; }

C++

https://www.google.com/amp/s/www.geeksforgeeks.org/arrays-in-c-cpp/amp/

I m learning from there already.Some theory part.

Or u have to use the for loop to print the whole array

Ok.I just wanted to confirm is there any way to print out the whole array like this.If not what's the problem actually. Well i am aware of traversing the array through loops.

Thanks for your kind responses guys.

I need a suggestion for my final project and I want to make it simple.do anyone of you have a plan in mind?

#include<iostream> using namespace std; int main() { int i,N; int arr[N]={}; //entering number of integers that arr will contain cin>>N; for(i=0;i<N;i++) {cin>>arr[i]; //inputting arr elements } //for printing elements in reverse order for(i=(N-1);i>=0;i--) {cout<<arr[i]<<" "; } return 0; } for input

4

1 4 3 2

output is: 4 1

#include<iostream> using namespace std; int main() { int i,N; int arr[N]={}; //entering number of integers that arr will contain cin>>N; for(i=0;i<N;i++) {cin>>arr[i]; //inputting arr elements } //for printing elements in reverse order for(i=(N-1);i>=0;i--) {cout<<arr[i]<<" "; } return 0; } for input

Cin>>N in 2nd line after int i N

idk what's making this happen.There's something logically incorrect probably

Cin>>N in 2nd line after int i N

? it;'s correct no?

? it;'s correct no?

Ha

it's a program to simply input array elements and then print them in reversed order but i m not getting it correct.

#include<iostream> using namespace std; int main() { int i,N; //entering number of integers that arr will contain cin>>N; int arr[N]={}; for(i=0;i<N;i++) {cin>>arr[i]; //inputting arr elements } //for printing elements in reverse order for(i=(N-1);i>=0;i--) {cout<<arr[i]<<" "; } return 0; } for input

it's a program to simply input array elements and then print them in reversed order but i m not getting it correct.

Did you get it?

Hi

I need an code for run length encoding

Can someone help me

Can someone help me

Search on google you will get it with explanation