But this one with a while loop. I can't do that.🙈 Is it even possible to do that with a While Loop?👇

is it nested ?

#include <iostream> using namespace std; class BankDeposit { int principal; int years; float interestRate; float returnValue; public: BankDeposit(); BankDeposit(int p, int y, float ir); BankDeposit(int p, int y, int ir); void display(); }; BankDeposit::BankDeposit() { cout << "you are bankrupt mf " << endl; } BankDeposit::BankDeposit(int p, int y, int ir) { principal = p; years = y; interestRate = float(ir) / 100; returnValue = principal; for (int i = 1; i <= years; i++) returnValue = returnValue * (1 + interestRate); } BankDeposit::BankDeposit(int p, int y, float IR) { principal = p; years = y; interestRate = IR; returnValue = principal; for (int i = 1; i <= years; i++) returnValue = returnValue * (1 + interestRate); } void BankDeposit::display() { cout << "return value of your amount " << principal << " in " << years << " years will be " << returnValue; } int main() { BankDeposit b1; BankDeposit b2(100, 2, 4); b2.display(); BankDeposit b3(100, 3, 0.04); b3.display(); return 0; }

redefinition of 'BankDeposit::BankDeposit(int, int, int)'

redefinition of 'BankDeposit::BankDeposit(int, int, int)'

Yes... You have it twice

is it nested ?

Do not understand the question🧐

Yes... You have it twice

guide me me with it

Do not understand the question🧐

is it nested loop ?

guide me me with it

you call it as 0.04 is that a double or float?

you call it as 0.04 is that a double or float?

i have crreated two constructors one has int parameter and other has float

yes

and you call it with double

but you don't have double variant

is it nested loop ?

With for loop business I have my question whether it works with while loop. Each digit should be displayed as often as it is. So 1 22 333 4444

but you don't have double variant

i called it with two different parameters once with int and second time with float

With for loop business I have my question whether it works with while loop. Each digit should be displayed as often as it is. So 1 22 333 4444

I am currently learning arduino in school🙈

i called it with two different parameters once with int and second time with float

you are calling it with double

you are calling it with double

got it..thank u...i m beginner

got it..thank u...i m beginner

float fc = 3.9999999f; double da = 1.0;

note the f

Well frankly speaking I programmed Windows in C++ back when I was in school, that is like 16 years ago... but I remember using init() as it had to be used, but I never question it.

https://stackoverflow.com/questions/4869216/calling-derived-class-function-from-base-class

Oh, that's why they do it.

float fc = 3.9999999f; double da = 1.0;

ohhhhhhhh....thank u

Hey guys, quick question. What is the function to exit the whole C++ program? Like if someone entered a certain value, it leads for the program to end. What is that function that does that?

std::exit is things are not catastrophic failure, std::terminate on catastrophic failure

https://stackoverflow.com/questions/4869216/calling-derived-class-function-from-base-class

Thanks

Hi everyone, I need a lot of help with this task, I have created my client and server but it seems that my code has several things that do not work, these are the requests to be fulfilled for the task "Link in pvt " , if you can help me contact me in pvt

the programming language used is c

Hello. Do I need to mark the variables in this function as const? bool testTriangleBBoxIntersect(const bbox& b, Plane p) { glm::vec3 c = (b.max + b.min) * 0.5f; glm::vec3 e = b.max - c; float r = e.x * std::abs(p.n.x) + e.y * std::abs(p.n.y) + e.z * std::abs(p.n.z); float s = glm::dot(p.n, c) - p.d; return std::abs(s) <= r; }

Hello. Do I need to mark the variables in this function as const? bool testTriangleBBoxIntersect(const bbox& b, Plane p) { glm::vec3 c = (b.max + b.min) * 0.5f; glm::vec3 e = b.max - c; float r = e.x * std::abs(p.n.x) + e.y * std::abs(p.n.y) + e.z * std::abs(p.n.z); float s = glm::dot(p.n, c) - p.d; return std::abs(s) <= r; }

It's a good practice to mark parameters const when you pass by reference to avoid any changes.

It's a good practice to mark parameters const when you pass by reference to avoid any changes.

I mean local variables (c, e, r, s)

I mean local variables (c, e, r, s)

You can as they are not getting updated.

Depends on you, your logic

I mean local variables (c, e, r, s)

If you don't intend to change them, mark as const, nobody will be hurt by that but the compiler will check that this intention is not changed

You can as they are not getting updated.

I will not update them. But usually, const is skipped in this case. So I ask: is it better to use const or omit?

What is self type in C++ ?

Ditto that. Yes, fflush(stdin) is UB. If it's implementation defined at all, it won't be portable. Ref: https://stackoverflow.com/questions/2979209/using-fflushstdin

Thanks I didn't know that

Anyone can help me with tcp client/server calculator in c?

indeed it has to be written in English but... it still seems that it is just some assignment from some school...

Anyone can help me with tcp client/server calculator in c?

What's the issue?

I will not update them. But usually, const is skipped in this case. So I ask: is it better to use const or omit?

Pavel has explained well

Hi Guys I have a some questions I have a some ardunios code how can I convert STM 32 from ardunio. I couldn't find any converter on the internet for this

Hi everyone. I have a function foobar(n) that executes another function based on integer type. Is following construction possible in C? If yes, how can I detect which type n belongs to? Pseudo code: void foobar(n) { if (typeof(n) == int) foo(n); else if (typeof(n) == unsigned int) bar(n); } int main(void) { int a; foobar(a); unsigned int b; foobar(n) return (0); }

Hi everyone. I have a function foobar(n) that executes another function based on integer type. Is following construction possible in C? If yes, how can I detect which type n belongs to? Pseudo code: void foobar(n) { if (typeof(n) == int) foo(n); else if (typeof(n) == unsigned int) bar(n); } int main(void) { int a; foobar(a); unsigned int b; foobar(n) return (0); }

typeof is GNU Extension

Thanks! The main question rather how foobar(n) function should be prototyped to take any integer type, so that it could work with n later on.

Thanks! The main question rather how foobar(n) function should be prototyped to take any integer type, so that it could work with n later on.

size_t ?

Hi everyone. I have a function foobar(n) that executes another function based on integer type. Is following construction possible in C? If yes, how can I detect which type n belongs to? Pseudo code: void foobar(n) { if (typeof(n) == int) foo(n); else if (typeof(n) == unsigned int) bar(n); } int main(void) { int a; foobar(a); unsigned int b; foobar(n) return (0); }

Sadly C-family languages generally lack pattern matching

They also generally lack static reflection

Sadly C-family languages generally lack pattern matching

Actually someone told me to look into _Generic keyword and it is not dissapointing! #define typecheck(X) _Generic((X), \ unsigned int: 1, \ int: 2 \ )

Actually someone told me to look into _Generic keyword and it is not dissapointing! #define typecheck(X) _Generic((X), \ unsigned int: 1, \ int: 2 \ )

Keep in mind that it is platform specific

Keep in mind that it is platform specific

Meaning Mac vs Windows vs Linux?

Meaning Mac vs Windows vs Linux?

No, gcc vs msvc vs clang vs nvcc vs craycc...

Hi everyone. I have a function foobar(n) that executes another function based on integer type. Is following construction possible in C? If yes, how can I detect which type n belongs to? Pseudo code: void foobar(n) { if (typeof(n) == int) foo(n); else if (typeof(n) == unsigned int) bar(n); } int main(void) { int a; foobar(a); unsigned int b; foobar(n) return (0); }

Why do you want this? you can do this however #include <stdio.h> #include <math.h> void foo_impl_i(int i) { puts("Signed version called"); } void foo_impl_ui(unsigned int i) { puts("Unsigned version called"); } #define foo(x) _Generic((x), \ int: foo_impl_i, \ unsigned int: foo_impl_ui)(x) int main(void) { foo((int)123); foo((unsigned int)123); }

No, gcc vs msvc vs clang vs nvcc vs craycc...

Thanks for mentioning, that's actually pretty important in my case 😔

Why do you want this? you can do this however #include <stdio.h> #include <math.h> void foo_impl_i(int i) { puts("Signed version called"); } void foo_impl_ui(unsigned int i) { puts("Unsigned version called"); } #define foo(x) _Generic((x), \ int: foo_impl_i, \ unsigned int: foo_impl_ui)(x) int main(void) { foo((int)123); foo((unsigned int)123); }

My code somewhat doubles in size if I don't check the type. Thanks for the implementation!

While a lot of programming languages are defined by their implementation, that is rarely the case for older languages like C, C++, lisp flavours... Where instead implementations follow a more or less vague guide book

And that guide book says, for C and C++, that anything starting with __ may or may not cause demons and pixies flying out of your nose

And that guide book says, for C and C++, that anything starting with __ may or may not cause demons and pixies flying out of your nose

not sure how this applies here, yes n1570 7.1.3 reserves identifiers beginning with an underscore that is either followed by an uppercase letter or another underscore for any use, but then 6.4.1 lists _Generic as Keyword

not sure how this applies here, yes n1570 7.1.3 reserves identifiers beginning with an underscore that is either followed by an uppercase letter or another underscore for any use, but then 6.4.1 lists _Generic as Keyword

Oh, what version of C? I am afraid I have not used more recent version of C than C89

Oh, what version of C? I am afraid I have not used more recent version of C than C89

ISO/IEC 9899:201x Committee Draft April 12, 2011 N1570

Ah my bad then

tbf I don't like it, but it was the attempt to bring Generics to C....

Thanks for mentioning, that's actually pretty important in my case 😔

^ please read the above

tbf I don't like it, but it was the attempt to bring Generics to C....

Bruh

not sure how this applies here, yes n1570 7.1.3 reserves identifiers beginning with an underscore that is either followed by an uppercase letter or another underscore for any use, but then 6.4.1 lists _Generic as Keyword

Am I understanding that right? Just because ISO/IEC 9899:201x standard reserves use of _Generic, then it is safe to use in case of C99?

Am I understanding that right? Just because ISO/IEC 9899:201x standard reserves use of _Generic, then it is safe to use in case of C99?

No, but in C11 it is

No, but in C11 it is

Thanks for guiding through :)

Hi guys I have an issue with this procedure: HWND Container::createWindow(void) const { int width = CLASSNAME_APP_MIN_WIDTH; int height = CLASSNAME_APP_MIN_HEIGHT; auto parentHandle = this->getParent()->getHWND(); auto hInstance = this->getInstance(); return ::CreateWindow( _T(CLASSNAME_CONTAINER), nullptr, WS_CHILD, 0, 0, width, height, parentHandle, nullptr, hInstance, nullptr ); } The debugger says that CreateWindowW is trying to call a null pointer to a function deep inside user32.dll I guess some of the parameters are wrong. I know for sure that: 1. parentHandle comes from the hwnd parameter of WM_CREATE ; 2. hInstance is valid 3. the other nullptr s are not the issue. What would you suggest?

#include<stdio.h> int main(){ int a = 178; char *ptr; ptr =( char *)&a; printf("%d ",*ptr); return 0; } how it's printing -78

#include<stdio.h> int main(){ int a = 178; char *ptr; ptr =( char *)&a; printf("%d ",*ptr); return 0; } how it's printing -78

char is signed, not unsigned

Max value of signed char is 127, 2 ^ 7

Data type overflow i think

okay

#include<stdio.h> int main(){ int a = 178; char *ptr; ptr =( char *)&a; printf("%d ",*ptr); return 0; } how it's printing -78

It's implementation defined.

#include<stdio.h> int main(){ int a = 178; char *ptr; ptr =( char *)&a; printf("%d ",*ptr); return 0; } how it's printing -78

On big-endian machine, this would yield 0.

Is there any specific reason to declare variable outside loop beside compability with ANSI C (C89) ? type i; for (i = n; ;) for (type i = n; ;)

Is there any specific reason to declare variable outside loop beside compability with ANSI C (C89) ? type i; for (i = n; ;) for (type i = n; ;)

Apart from compatibility with ANSI C (C89), this is required when you still use the variable outside the loop body. for (int i = 0; i < n; i++) { // you can use i here } // you cannot use i here ^ As such, if you still want to access the i, it must be declared outside the loop.

/report

Guys can any 1 help me out here? I was trying to swap two numbers using this #include<iostream> using namespace std; void swapNums(int,int); int main() { int a=10,b=20; cout<<"before swap value of a is "<<a<<" and value of b is "<<b<<endl; swapNums(a,b); cout<<"after swap value of a is "<<a<<" and value of b is "<<b<<endl; return 0; } void swapNums(int x,int y) { int z=x; x=y; y=z; } Output: before swap value of a is 10 and value of b is 20 After swap value of a is *10* and value of b is *20*. But why is this happening even when i called the function inside main function?

Guys can any 1 help me out here? I was trying to swap two numbers using this #include<iostream> using namespace std; void swapNums(int,int); int main() { int a=10,b=20; cout<<"before swap value of a is "<<a<<" and value of b is "<<b<<endl; swapNums(a,b); cout<<"after swap value of a is "<<a<<" and value of b is "<<b<<endl; return 0; } void swapNums(int x,int y) { int z=x; x=y; y=z; } Output: before swap value of a is 10 and value of b is 20 After swap value of a is *10* and value of b is *20*. But why is this happening even when i called the function inside main function?

Did you use pointer ?

Nope

Nope

Then use it