#include <stdio.h> #include <ctype.h> #include <stdbool.h> int main() { bool upper, digit, dollar; char password[50]; printf("Password must include number, uppercase letter & a dollar sign"); printf("\n\nPlease Enter Your Password: "); scanf("%s", password); for(int i = 0; i <= 50 ; i ++){ if (isupper(password[i]) ){ upper = true; } if (isdigit(password[i])){ digit = true; } if ((password[i]) == '$'){ dollar = true; } } if(upper && digit && dollar){ printf("\nLoading...."); } else { printf("\nPassword must Include Capital letter, Number and Dollar sign!"); } return 0;

Thanks bro

It takes password from user Password must include 1. Uppercase 2. Digit 3. Dollar sign

How can i reduce the lines number of this code?... I guess it could use less lines:

Better code does less work with more lines of code

I'm trying to send the code here, but it takes too much size.

use pastebin

#include<stdio.h> #include<stdlib.h> void main(){ struct emp{ int eno; char ename[20]; float esal; }; struct emp* ptr; ptr=(struct emp*)malloc(sizeof(struct emp)); if (ptr==NULL) printf("no memory"); else printf("enter the details:"); scanf("%d,%s,%f",&ptr->eno,ptr->ename,&ptr->esal); printf("%d,%s,%f",ptr->eno,ptr->ename,ptr->esal); }

#include<stdio.h> #include<stdlib.h> void main(){ struct emp{ int eno; char ename[20]; float esal; }; struct emp* ptr; ptr=(struct emp*)malloc(sizeof(struct emp)); if (ptr==NULL) printf("no memory"); else printf("enter the details:"); scanf("%d,%s,%f",&ptr->eno,ptr->ename,&ptr->esal); printf("%d,%s,%f",ptr->eno,ptr->ename,ptr->esal); }

It's %lf instead

It's %lf instead

Guys what is the best approach/ method and resources to master C/C++ for a beginner ??

Guys what is the best approach/ method and resources to master C/C++ for a beginner ??

hello! anyone here who knows what is actual running time? is it the same as execution time or no? tia

What is the best book about STL programming?

Standard template library (STL)

Yes, Standard Library.

I need an elaborate answer , please

#include <stdio.h> #include <stdlib.h> int main() { int number[10]; int sum = 0; int counter=1; int count =1; do{ printf("Enter number %d: ",count); scanf(" %d", &number[10]); sum+=number[10]; counter++; count++; } while(counter <=10); printf("\nSum Of Your Entered Numbers = %d.", sum); return 0; }

Probably counter. And I would change 'count' to 'num' for readability.

Arguable

There is no index 10. I guess it's a typo and u meant to put a var there :)

Do you mean the figure in the [ ]?

Yeah

I took them out and the code is acting up bro

I took them out and the code is acting up bro

What

After editing it out, the sum i get from the program is wrong

Edit what out?

That's because you not reusing it, you just write your value into some memory outside of the array and then use it for the sum. You don't even need an array for that

What did u put instead of 10?

Kind of new to this Started learning C like 2 days ago so i don’t really get you

Just “& number”

Kind of new to this Started learning C like 2 days ago so i don’t really get you

int number[10]; declares an array of 10 elements Then number[10] points to the 11th element from the array. Which is just some memory next to the array

If i get you right that means line 13 just increases the array’s size?

You are lucky it doesn't crash

But it worked as expected Its what surprises me

#include <stdio.h> #include <stdlib.h> int main() { int number; int sum = 0; int counter=1; do{ printf("Enter number %d: ",counter); scanf(" %d", &number); sum+=number; counter++; } while(counter <=10); printf("\nSum Of Your Entered Numbers = %d.", sum); return 0; }

I think this is how you guys are describing it to be

Yes, from looking at it, it looks much more correct

#include <stdio.h> #include <stdlib.h> int main() { int number; int sum = 0; int counter=1; do{ printf("Enter number %d: ",counter); scanf(" %d", &number); sum+=number; counter++; } while(counter <=10); printf("\nSum Of Your Entered Numbers = %d.", sum); return 0; }

#include <stdio.h> #include <stdlib.h> int main() { int number[10]; int sum = 0; int counter=1; int count =1; do{ printf("Enter number %d: ",count); scanf(" %d", &number[10]); sum+=number[10]; counter++; count++; } while(counter <=10); printf("\nSum Of Your Entered Numbers = %d.", sum); return 0; }

Is this c++ ?

If you want to be pedantic, the running time is actually the time that your program is being executed by the CPU (ignoring other things like I/O, process being context switched and all). The execution time is the time from the start of the program till the time it ends. So if your process is blocked, it will add to the execution time but running time won't be affected. But people usually use the terms interchangeably and it is often used to mean the time the thr program takes from start to finish.

#include <stdio.h> #include <stdlib.h> int main() { int number; int sum = 0; int counter=1; do{ printf("Enter number %d: ",counter); scanf(" %d", &number); sum+=number; counter++; } while(counter <=10); printf("\nSum Of Your Entered Numbers = %d.", sum); return 0; }

Anyone here knows how array works?🥺

Two dimensional array