I thought about that but it takes function as third argument... And due to function call time may increase..

It's best to run Benchmarks. In this example, time did *not* increase. http://quick-bench.com/j_QMwY3SqjjGlZvAGE3_vApkYfY When enabling optimization the functor might be inlined, so no function call occurs https://godbolt.org/g/6uuMBE I think using count_if would be a good use. Since C++17 you can pass an execution policy and 'counting' might be processed in parallel

Post increments(x++) first returns value of x and than increments it... While pre increments (++x) increases value and than returns increases value..

Output is 5693 How

{ int x=20,y=35; x=y++ + x++; y= ++y + ++x; printf("%d%d",x,y); }

It should print x=55,y=93

Does Any one participates in competitive Coding Contests? i.e. Codechef, Hackerrank, Hackerearth etc.

Output is 5693 How

first x = x + y, then x++

{ int x=20,y=35; x=y++ + x++; y= ++y + ++x; printf("%d%d",x,y); }

first ++y and ++x then y = y + x

So x = 20 + 35, then 55++ => 56

Got 56 How 93

So ++35 (36) and ++56 (57), then y = 36 + 57 => 93

It's kinda simple

Ok Got It ThankU I am Begineer

No problem. Go catch a good book/course/whatever about C/C++ and study every day :)

Ya i Have One

Ansi c

from brian w. kernighan

K&R? Nice :)

Spelling mistake bro

Output is 5693 How

Because you don't have a space in the middle

http://cppquiz.org/quiz/question/125

do you think this quiz even has the right answer?

Yes it has

do you think this quiz even has the right answer?

yes, why not?

@Neko_cpp @ollirz i said, that program shouldn't even compiled... the main() not returning an int value to the function caller...

the function caller a.k.a. the os

Still can be compiled

And called

But later meh

@Neko_cpp @ollirz i said, that program shouldn't even compiled... the main() not returning an int value to the function caller...

If control flows off the end of the compound-statement of main, the effect is equivalent to a return with operand 0.§ 6.6.1.5 (n4659) No explicit return is like returning 0

reference link?

hi there

Who can help me with multithreding?

This is my code with segmentation fault

@Neko_cpp @ollirz i said, that program shouldn't even compiled... the main() not returning an int value to the function caller...

You can even jump the int from the main() definition

reference link?

http://eel.is/c++draft/basic.start.main#5

You can even jump the int from the main() definition

what does it mean? you mean void main() ?

http://eel.is/c++draft/basic.start.main#5

thx

what does it mean? you mean void main() ?

main() {} will be compiled

There are no multithreaded stuff

main() {} will be compiled

old C-style?

wasn't it already forbidden in modern C++?

wasn't it already forbidden in modern C++?

Yep, but it will compile. Just saying that you can avoid stuff in the main function

It just throws a warning

If control flows off the end of the compound-statement of main, the effect is equivalent to a return with operand 0.§ 6.6.1.5 (n4659) No explicit return is like returning 0

what the "control" means? is it the "statements"?

It just throws a warning

nope

nope

Mmmm, sorry for it. I forgot the part where is up to the compiler to manage this kind of stuff

My bad

ok

gcc just throws a warning

np

what the "control" means? is it the "statements"?

the control flow describes the order of the statements. If the control flow exits main without an explicit return then 0 will be returned

the control flow describes the order of the statements. If the control flow exits main without an explicit return then 0 will be returned

exists? you mean "exits"?

yes.. I do - fixed..

I am trying to convert string to int

but getting error stoi was not declared in this scope

I am trying to convert string to int

Use stringstream

ok ill google stringstream

will*

but getting error stoi was not declared in this scope

Have you imported the right lib?

ok ill google stringstream

ill as I'll is correct :)

string. h

If control flows off the end of the compound-statement of main, the effect is equivalent to a return with operand 0.§ 6.6.1.5 (n4659) No explicit return is like returning 0

ok, so i guess that this sentence means: if all the statements in main() executed flawlessly, and if there's no explicit "return 0;" in the code, it'll be read as an implicit "return 0;" by the compiler, right?

Use stringstream

Stoi its better

ok, so i guess that this sentence means: if all the statements in main() executed flawlessly, and if there's no explicit "return 0;" in the code, it'll be read as an implicit "return 0;" by the compiler, right?

Yep

ok, so i guess that this sentence means: if all the statements in main() executed flawlessly, and if there's no explicit "return 0;" in the code, it'll be read as an implicit "return 0;" by the compiler, right?

👍

:)

@Occupato @ollirz ok, thx for the info

Stoi its better

but its giving error

but getting error stoi was not declared in this scope

Are you using it as intended?

you're welcome

and also thx @Neko_cpp

string. h

C++'s string header does not end with .h #include <string>

i cant get what intended is

And be sure that string is included

#include <string>

this is code

Don't. See the pinned message to give us a proper rapresentation of your code

You're NOT using it properly

Stoi its better

Not, it not type safe