#include <stdio.h> int main(){ int n,i,total=0,x; printf("Enter the numbers of elements :"); scanf("%d",&n); int odd_num[n]; int even_num[n]; int numbers[n]; for (i=0;i<n;i++){ printf("Enter your sum_of_elements : "); scanf("%d",&numbers[i]); if (numbers[i]%2 == 0) { even_num[n] = numbers[i]; } else { odd_num[n] = numbers[i]; } } printf("even numbers are = %d \n",even_num[n]); printf("odd numbers are = %d \n",odd_num[n]); return 0; printf("%d",numbers[n]); }

Enter the numbers of elements :5 Enter your sum_of_elements : 9 Enter your sum_of_elements : 8 Enter your sum_of_elements : 6 Enter your sum_of_elements : 7 Enter your sum_of_elements : 3 even numbers are = 6 odd numbers are = 3 -------------------------------- Process exited after 13.84 seconds with return value 0 Press any key to continue . . . what's wrong ? why i couldn't store all numbers?

Enter the numbers of elements :5 Enter your sum_of_elements : 9 Enter your sum_of_elements : 8 Enter your sum_of_elements : 6 Enter your sum_of_elements : 7 Enter your sum_of_elements : 3 even numbers are = 6 odd numbers are = 3 -------------------------------- Process exited after 13.84 seconds with return value 0 Press any key to continue . . . what's wrong ? why i couldn't store all numbers?

for your odd and even array, you only accessed it out of bounds odd_num[n] and you only print a single element in the end and not the whole array.

/get cppbookguide

Bruh

int main();

int main();

Semi column?

Here i am getting the output

But looking for an alternative.

But looking for an alternative.

what do you mean by "an alternative"? if you have written the code, you will be able to rewrite it differently

Can i use string instead of char

also, that formatting will probably make others not even look at the code btw

well you are certainly using C++ so you can use std::string... why not

what do you mean by "an alternative"? if you have written the code, you will be able to rewrite it differently

No i am a beginner,

No i am a beginner,

?

?

This code is copied from somewhere.

also, that formatting will probably make others not even look at the code btw

Yes sorry, just copy paste.

and your goal is to mask it as you have you written it or why do you need to change it?

There's something I don't understand so i thought there might be another option to do this.

Val=strcmp("yes",robotChk);

And cin>>robotChk

And cin>>robotChk

cin: https://en.cppreference.com/w/cpp/io/cin strcmp: https://en.cppreference.com/w/c/string/byte/strcmp

Hello. I read an article about memcpy optimization and i think I aim dying for help

Hello. I read an article about memcpy optimization and i think I aim dying for help

Dying for help?

*desperate

https://www.embedded.com/optimizing-memcpy-improves-speed/

What didn't you get?

they give an example for making the coping word size. and than they do checking to see 4 bits alignment i think they do wrong comparison

An algorithm that offers better performance on wider memory buses, such as the one on the evaluation board I used, can be found in GNU's newlib source code. I've posted the code here. If the source and destination pointers are both aligned on 4-byte boundaries, my modified-GNU algorithm copies 32 bits at a time rather than 8 bits. Listing 2 shows an implementation of this algorithm. Listing 2: The modified-GNU algorithm void * memcpy(void * dst, void const * src, size_t len) { long * plDst = (long *) dst; long const * plSrc = (long const *) src; if (!(src & 0xFFFFFFFC) && !(dst & 0xFFFFFFFC)) { while (len >= 4) { *plDst++ = *plSrc++; len -= 4; } } char * pcDst = (char *) plDst; char const * pcDst = (char const *) plSrc; while (len–) { *pcDst++ = *pcSrc++; } return (dst); }

they give an example for making the coping word size. and than they do checking to see 4 bits alignment i think they do wrong comparison

Agree

I believe they wanted to avoid modulo operation

(!(src & 0xFFFFFFFC) && !(dst & 0xFFFFFFFC)) so this is a mistake ?

(!(src & 0xFFFFFFFC) && !(dst & 0xFFFFFFFC)) so this is a mistake ?

I think it's correct

If any of the last two bits are on it would give true

Then result is negated

If any of the last two bits are on it would give true

My bad fixed

Or not

but lets take src to be (64 = 1000000 & 01111111100) it will give troe

I think it should be src & 3

how come so advanced articles do such mistakes?

not that i complain, but a beginner like me will waste 4 days rechecking before I will have the courage to doubt professional article

I think it should be src & 3

thank you sir

how come so advanced articles do such mistakes?

Even more so. Such mistakes get into production code :P

Even more so. Such mistakes get into production code :P

Thanks a lot Sir, Whish you best weekend

Hi bro Im Iranian too

/get

Hi

I am new joining

I am new joining

Hiii

Hiii

Hello

Hii plz suggest me a book for cpp

Hii plz suggest me a book for cpp

Link send please

Anyone to help with a School assignment c++ program

What's so wrong with saying hi? Yikes. Don't be like those guys in QebecOS IRC.

#include<iostream.h> #include<conio.h> void main() { int cash=0,deposit,withdraw,choice; char c; do { cout<<"1.withdraw 2.deposit 3.Balance"; cin>>choice; switch(choice ) { case 1: { cout<<"enter withdrawal amout"; cin>>withdraw; if(withdraw%100==0) { if( cash>=withdraw) { cash -= withdraw; cout<<"after withdraw in cash in yr account"<<cash; } else { cout<<" enter amount in 100's"; } // else // { // cout<<"you don't have enough amount" ; // } } } case 2: { cout<<"enter deposit amounts in 100's"; cin>>deposit; if(deposit%100==0) { cash+=cash+deposit; cout<<" balance after depositing"<<cash; } else { cout<<"enter amount is 100's"; } } case 3: { cout<<"yr account balance is"<<cash; break; } default : { cout<<"enter valid choice"; } cout<<" to continue press Y "; cin>>c; } }while(c=='y' || c=='Y'); }

Do while loop is not working ? Y?

What's so wrong with saying hi? Yikes. Don't be like those guys in QebecOS IRC.

That is all she (sorry it) has been saying for last 4 days.

Hi! I'm new joining

I'm Mohammed Sahfan Sri Lanka I have some doubts in c programming. Can anyone solve my doubt?

/get cbook

Ok

Hii plz suggest me a book for cpp

Let us cpp by yashwant kanetkar

How can we remove whitespaces from a string, none of the algorithms on the internet are working

how do i split a vector into sub vectors based on content comparison? as i need to split a list of views into a seperate list of views based on if the location X is inside the view's location

How can we remove whitespaces from a string, none of the algorithms on the internet are working

just rebuild the string with whitespaces ommited

string tmp; for (char x : str) { bool skip = false; for (char w : whitespace_chars) { if (x == w) { skip = true; break; } } if (skip) { continue; } tmp += x; } return tmp;

Hey

Hey

hi

https://github.com/jakowskidev/uMario_Jakowski Some crazy guy rewrote super Mario in c++...

https://github.com/jakowskidev/uMario_Jakowski Some crazy guy rewrote super Mario in c++...

mm, its very accurate.

Hii

Hii

/report BOT!!!

Does codeblocks is better than vs code ?

Does codeblocks is better than vs code ?

Too old for now, but still works

Does codeblocks is better than vs code ?

Yeah, for c/c++

Does codeblocks is better than vs code ?

In my opinion I don't think this comparison is up for debate at this point. Code::Blocks is too old and slow for today's standards, but it was acceptable back in the day.

/get

I've built a user thread library in C++ . Now, using Googletest framework to test the functionality of my library, when I call ASSERT_EXIT to verify the number of exit code, the exit code that is returned is always 1, and 0 is expected. I've debugged it. and I exit the program with std::exit(0), and not with 1. But, for some strange reason, I've checked the assembly of this std::exit(0) and I got: __GI_exit: endbr64 push rax pop rax mov ecx,0x1 mov edx,0x1 lea rsi,[rip+0x1a1b41] ; 0x7f79946c3718 <__exit_funcs> sub rsp,0x8 call 0x7f7994521930 ; <__run_exit_handlers> That is, the assembly of std::exit always returns exit code = 1 !! Why is that? Even if I change it to std::exit(5) it still exits with 1.