yes.for each item how much they have been sold out

You just need to maintain a separate running counter for each individual items which you initialize to 0 and then when an item is ordered you add them to the specific counter of the item. You dont reset it to 0 for the next customer. You go on adding to this counter and display it all together at the end. Ideally instead of maintaining separate counters, you can create classes for each item and let them do the hard work. Would make your code look better and also make it easy to make any changes in future.

classes? can be more detail? not understand little bit..

classes? can be more detail? not understand little bit..

Are you familiar with OOP?

You can just create a tensor directly from this input. You dont even need a file. Look at their examples. They have lots of them covering different scenarios. Not all the inputs are image files.

Could you give me a URL, I just found doc like this https://serizba.github.io/cppflow/examples.html#inference-on-efficientnet Sorry for asking this

Are you familiar with OOP?

nope

nope

Then forget it.

ouhh okay thanks

Could you give me a URL, I just found doc like this https://serizba.github.io/cppflow/examples.html#inference-on-efficientnet Sorry for asking this

https://github.com/serizba/cppflow/blob/cppflow2/examples/multi_input_output/main.cpp Here the input is a tensor that they create using the fill method.

https://github.com/serizba/cppflow/blob/cppflow2/examples/multi_input_output/main.cpp Here the input is a tensor that they create using the fill method.

Let me studing in this. Thx a lot, having a good day!

Let me studing in this. Thx a lot, having a good day!

You need to understand what tensors are. I guess you are already familiar with python and so must have used np.arrays from numpy. Tensors are the C/C++ equivalent of that. There are many ways you can create them. Look at the cppflow wrapper and see what methods are available. If not convenient, you can use the underlying Tensorflow API directly.

What is difference with size of object and size of class

I just submitted the solution and it was accepted. Not sure why yours is getting rejected then. Check out ID = 28128919 in the submitted solutions

Hey, it got submitted, yes, BUT, the output when I run in local/online editor, it shows only 0's just like before :/

Hey, it got submitted, yes, BUT, the output when I run in local/online editor, it shows only 0's just like before :/

I tried some corner cases like only 1 solution and all 100 solutions with same concentration and all. It did work fine. Online submission to SPOJ was also accepted as having passed all test cases. Not sure why it is different for you.

I tried some corner cases like only 1 solution and all 100 solutions with same concentration and all. It did work fine. Online submission to SPOJ was also accepted as having passed all test cases. Not sure why it is different for you.

Nah I am saying, did you run it locally?

Can you show me the output?

I tried the border cases on my local system as well

I tried the border cases on my local system as well

I am not asking about the cases, it shows me 0 for sample case itself

I am not asking about the cases, it shows me 0 for sample case itself

No it worked fine for those as well. Hold on let me show you.

No it worked fine for those as well. Hold on let me show you.

yes pls

yes pls

you want to test any specific inputs

you want to test any specific inputs

2 18 19 3 40 60 20

The samples ones, given in the question itself

Okay so it works :/ Will check it up again Anyway, thanks a lot for entertaining my questions!

Okay so it works :/ Will check it up again Anyway, thanks a lot for entertaining my questions!

I will delete the screenshot as they are frowned upon here.

I will delete the screenshot as they are frowned upon here.

sure, but who are frowned upon and why?

sure, but who are frowned upon and why?

sharing screenshots. People used to post pictures of the screen instead of taking a screenshot. To curb the menace, attaching files is now not allowed for anyone.

sharing screenshots. People used to post pictures of the screen instead of taking a screenshot. To curb the menace, attaching files is now not allowed for anyone.

oh, cool

What is difference with size of object and size of class

sizeof an object will be the same as the sizeof its class.

Why is that so because memory is allocated after object is created so for class there must be no memory. And another question why does static member memory is counted for each object its only one for whole class

sizeof an object will be the same as the sizeof its class.

There must be some difference when dealing with static member . But i cant observe it i get same size .

Why is that so because memory is allocated after object is created so for class there must be no memory. And another question why does static member memory is counted for each object its only one for whole class

sizeof when used with a class tells you how much memory will be taken up by the objects of the class which will be the same as sizeof an object of the class. Static members dont affect sizeof. Did you check with an example code?

sizeof when used with a class tells you how much memory will be taken up by the objects of the class which will be the same as sizeof an object of the class. Static members dont affect sizeof. Did you check with an example code?

I checked with example code . You are correct static members have nothing to with size while dealing with object . So that means we cant define size of class?

I checked with example code . You are correct static members have nothing to with size while dealing with object . So that means we cant define size of class?

Sizeof class like I said, gives you the size that an object of this class will take up in memory (this doesnt include heap memory allocations btw).Static members are not part of an object. Hence sizeof class or sizeof object will not be affected by them.

Is their any case when size of class and size object wont be same . And i find a website saying classes dont have any size.

Is their any case when size of class and size object wont be same . And i find a website saying classes dont have any size.

Sizeof(A) will always be same as sizeof(obj) where obj is an instance of A.

A simple class for eg. Class test {int a;}; containing various member variables.

No a class definition defined using class keyword.

Sizeof(A) will always be same as sizeof(obj) where obj is an instance of A.

Gotit. Thanks

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) and (MathMark >= 65) and (ChemMark >= 50){ if (Total_3 >= 190 ) or (Total_2 >= 137){ printf("This candidate is eligible for admission") ; } else{ printf("This candidate is not eligible for admission"); } } } }

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) and (MathMark >= 65) and (ChemMark >= 50){ if (Total_3 >= 190 ) or (Total_2 >= 137){ printf("This candidate is eligible for admission") ; } else{ printf("This candidate is not eligible for admission"); } } } }

What's wrong with me?

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) and (MathMark >= 65) and (ChemMark >= 50){ if (Total_3 >= 190 ) or (Total_2 >= 137){ printf("This candidate is eligible for admission") ; } else{ printf("This candidate is not eligible for admission"); } } } }

instead of and in if condition use operator && and do the same in or use ||

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) and (MathMark >= 65) and (ChemMark >= 50){ if (Total_3 >= 190 ) or (Total_2 >= 137){ printf("This candidate is eligible for admission") ; } else{ printf("This candidate is not eligible for admission"); } } } }

also befor ending } use return 0

instead of and in if condition use operator && and do the same in or use ||

still error

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) && (MathMark >= 65) && (ChemMark >= 50) { if (Total_3 >= 190 ) || (Total_2 >= 137) { printf("This candidate is eligible for admission") ; } else { printf("This candidate is not eligible for admission"); } } return 0; }

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) && (MathMark >= 65) && (ChemMark >= 50) { if (Total_3 >= 190 ) || (Total_2 >= 137) { printf("This candidate is eligible for admission") ; } else { printf("This candidate is not eligible for admission"); } } return 0; }

You should add an extra parentheses to group all the relationship operations in the if statement like if((Total_3>=190)||(Total_2>=137)) Likewise for the first if as well.

You should add an extra parentheses to group all the relationship operations in the if statement like if((Total_3>=190)||(Total_2>=137)) Likewise for the first if as well.

i got it. thanks

You should add an extra parentheses to group all the relationship operations in the if statement like if((Total_3>=190)||(Total_2>=137)) Likewise for the first if as well.

Constraints: 1 <= T <= 200 1 <= N <= 107 1 <= D <= N 0 <= arr[i] <= 105 by looking constrains how can i get to know what should be the time complexity for my code

Constraints: 1 <= T <= 200 1 <= N <= 107 1 <= D <= N 0 <= arr[i] <= 105 by looking constrains how can i get to know what should be the time complexity for my code

Time complexity depends on your algorithm. The constraints can then be used to determine how much time will be taken up by your algorithm from the time complexity to a constant factor. Without looking at the problem, you cant do anything with the constraints alone.

Time complexity depends on your algorithm. The constraints can then be used to determine how much time will be taken up by your algorithm from the time complexity to a constant factor. Without looking at the problem, you cant do anything with the constraints alone.

i mean by seeing constrains how can i get an idea that code should have time complexity of ....

whats wrong?

#include <stdio.h> int main(){ int PhyMark = 65,MathMark = 72,ChemMark = 51; int Total_3 = PhyMark + MathMark + ChemMark; int Total_2 = PhyMark + MathMark; if (PhyMark >= 51) { if (MathMark >= 65) { if (ChemMark >= 50) { if (Total_3 >= 190 ) { printf("This candidate is eligible for admission"); else if (Total_2 >= 137) { printf("This candidate is eligible for admission"); } } } } } else { printf("This candidate is not eligible for admission"); } return 0; }

i mean by seeing constrains how can i get an idea that code should have time complexity of ....

If suppose say you have a linear complexity algorithm, and the size of inputs is 0 to 10000, then you know your algorithm will take 10 micro seconds approx on a computer that can execute 10^9 instructions per second. If the input size is 10^9, then for the same algorithm your time limit will be 1s or more which would give you a TLE error on most competitive programming sites(I guess you are a competitive programmer). Then you know that there must be a sub linear possibly logarithmic complexity algorithm and so on.

const int a = 3; const int *ptr_to_a = &a; int *ptr; ptr = (int*)ptr_to_a; cout<<(*ptr_to_a)<<" "<<ptr_to_a<<endl;; cout<<(a)<<" "<<&a<<endl;; cout<<*ptr<<" "<<ptr<<endl; // changing here. (*ptr) = 5; cout<<(*ptr_to_a)<<" "<<ptr_to_a<<endl;; cout<<(a)<<" "<<&a<<endl;; cout<<*ptr<<" "<<ptr<<endl; Output is 3 0x7ffe87e48554 3 0x7ffe87e48554 3 0x7ffe87e48554 5 0x7ffe87e48554 3 0x7ffe87e48554 5 0x7ffe87e48554 Can anyone explain why its giving output 3 while at same location im getting value 5.

const int a = 3; const int *ptr_to_a = &a; int *ptr; ptr = (int*)ptr_to_a; cout<<(*ptr_to_a)<<" "<<ptr_to_a<<endl;; cout<<(a)<<" "<<&a<<endl;; cout<<*ptr<<" "<<ptr<<endl; // changing here. (*ptr) = 5; cout<<(*ptr_to_a)<<" "<<ptr_to_a<<endl;; cout<<(a)<<" "<<&a<<endl;; cout<<*ptr<<" "<<ptr<<endl; Output is 3 0x7ffe87e48554 3 0x7ffe87e48554 3 0x7ffe87e48554 5 0x7ffe87e48554 3 0x7ffe87e48554 5 0x7ffe87e48554 Can anyone explain why its giving output 3 while at same location im getting value 5.

Because it is Undefined Behavior. The compiler when it sees that something is a constant, will make optimizations by replacing the variable and maybe even the dereferencing of the const pointer to that const variable with the actual value. This is called const propagation. So if the value gets changed underneath, the compiler's optimizations will be rendered invalid which is what leads to Undefined Behavior.

Because it is Undefined Behavior. The compiler when it sees that something is a constant, will make optimizations by replacing the variable and maybe even the dereferencing of the const pointer to that const variable with the actual value. This is called const propagation. So if the value gets changed underneath, the compiler's optimizations will be rendered invalid which is what leads to Undefined Behavior.

Okay.👍

Hello,im new and i need a recommendation where to start learning C language Any recommendation like books,website or video?

Hello,im new and i need a recommendation where to start learning C language Any recommendation like books,website or video?

Hello, geeksforgeeks i recommend

Hello, geeksforgeeks i recommend

Thank you

Thank you

You are welcome

#include <stdio.h> #include <string.h> #define SIZE 5 #define SIZE2 20 struct customer{ int account; char name[SIZE2]; char type; float amount; }customer[SIZE]; int main ( void ) { int indexNo , test1 = 0 , test2 = 0; float deposit = 0 , withdrawl = 0 , max , min; char maxName[SIZE2] , minName[SIZE2]; // max = -1; // min = 100000000; for( indexNo = 0; indexNo < SIZE; indexNo++ ) { printf ( "Enter your account number : " ); scanf ( "%d" , &customer[indexNo].account ); printf ( "Enter your name : " ); scanf ( "%s" , customer[indexNo].name ); printf ( "Enter your account type : " ); scanf ( "%*c%c" , &customer[indexNo].type ); printf ( "Enter your amount : " ); scanf ( "%f" , &customer[indexNo].amount ); if ( ( customer[indexNo].type == 'D' ) || ( customer[indexNo].type == 'd' )) { if ( test1 = 0 ) { max = customer[indexNo].amount; } deposit += customer[indexNo].amount; if ( max <= customer[indexNo].amount ) { max = customer[indexNo].amount; strcpy ( maxName , customer[indexNo].name ); } test1 = 2; } else if ( ( customer[indexNo].type == 'W' ) || ( customer[indexNo].type == 'w' )) { if ( test2 = 0 ) { min = customer[indexNo].amount; } withdrawl += customer[indexNo].amount; if ( min >= customer[indexNo].amount ) { min = customer[indexNo].amount; strcpy ( minName , customer[indexNo].name ); } test2 = 2; } printf ( "\n" ); } printf ( "Total deposit amount : %.2f\n" , deposit ); printf ( "Total withdrawl amount : %.2f\n" , withdrawl ); printf ( "Name of the customer with the maximum deposit amount : %s\n" , maxName ); printf ( "Name of the customer with the minimum withdrawl amount : %s\n" , minName ); return 0; }

theres error on withdrawl minimum amount can anyone check it?

guys help me

i dont know what do

Hello, i need help, why does my program isn't working I show you my source code

#include <cstdio> int main() { int search (int left, int right) { int mid = left; int res = 0; while (mid <= right) { if (mid % 11 == 0) { res++; mid++; } else if (mid % 12 == 0) { mid++; else { if (mid % 4 == 0) { res++; } mid++; } } return res; } }

With input (1, 100) Please help me 🥲

#include <cstdio> int main() { int search (int left, int right) { int mid = left; int res = 0; while (mid <= right) { if (mid % 11 == 0) { res++; mid++; } else if (mid % 12 == 0) { mid++; else { if (mid % 4 == 0) { res++; } mid++; } } return res; } }

Your search function is defined inside another function (main function). I think you should define it outside... And then call it inside a main function

Your search function is defined inside another function (main function). I think you should define it outside... And then call it inside a main function

Thank you i'll show you later

I am learning pointers and pointer variable can access data and manipulate data through deference operator * , if that is the case how secure is data in pointer environment! Any one can access data with no security!

I am learning pointers and pointer variable can access data and manipulate data through deference operator * , if that is the case how secure is data in pointer environment! Any one can access data with no security!

How will you obtain the pointer to the data in the first place without being provided access to the data (or maybe by a stupid programmer mistake where he returns a pointer or reference to data that is supposed to be encapsulated away)

How will you obtain the pointer to the data in the first place without being provided access to the data (or maybe by a stupid programmer mistake where he returns a pointer or reference to data that is supposed to be encapsulated away)

Oh true!

Oh true!

you will learn oop there is a concept called encapsulation there you will get to know in detail.

Explain with an example the passing of a structure to a function by reference.

Explain with an example the passing of a structure to a function by reference.

?

you will learn oop there is a concept called encapsulation there you will get to know in detail.

Oh great

Explain with an example the passing of a structure to a function by reference.

google it.

Explain with an example the passing of a structure to a function by reference.

I think u can create ur own structure and pass name of structure as parameter in function call. But dont forget to put arguments in function pointing to a variable! I think it works

I think u can create ur own structure and pass name of structure as parameter in function call. But dont forget to put arguments in function pointing to a variable! I think it works

* put arguments in function defnition pointing to variable

In cpp... The length function on a string is not the same as strlen on a char pointer...somebody explain this

In cpp... The length function on a string is not the same as strlen on a char pointer...somebody explain this

I observed that if I replace ith index with null character ...the length function still shows the same length