Ravi
C++ is the superset of C, i.e. C++ is derrived from C, and have made certain changes
AJAY
C is strictly procedural programming language whereas C++ is both procedural and Object Orientez
Give me some examples
Where we use only c++ not c
Ravi
Give me some examples
Where we use only c++ not c
Implementing any class, just google it, You will find it
Anonymous
In Shell
cat /proc/meminfo | awk NR==2 | awk '{printf $2}'
Output : 48796 (my output)
And how to get this same output in C
You can directly read /proc/meminfo, or use posix call:
#include <unistd.h>
#include <iostream>
using namespace std;
int main() {
const auto pages = sysconf(_SC_AVPHYS_PAGES);
const auto page_size = sysconf(_SC_PAGESIZE);
cout << pages * page_size / 1024 << " kB\n";
}
class Person(Skills): name = str("Ankush Bhagat")
You can directly read /proc/meminfo, or use posix call:
#include <unistd.h>
#include <iostream>
using namespace std;
int main() {
const auto pages = sysconf(_SC_AVPHYS_PAGES);
const auto page_size = sysconf(_SC_PAGESIZE);
cout << pages * page_size / 1024 << " kB\n";
}
Broh I'm talking about c not c++
class Person(Skills): name = str("Ankush Bhagat")
Yes but how did I print a string after whitespace
class Person(Skills): name = str("Ankush Bhagat")
Hello World
.../
World
Shourya
What is the difference between c and c++
Well ..There are many differences in c and c++...c++ is more of a multi paradigm language..As it supports oops so it gives you power full concept of interfaces that can change the order of dependencies..Watch this Uncle bob lecture...From 12 mins onwards...https://www.youtube.com/watch?v=zHiWqnTWsn4 before explaining SOLID Principles he gives an idea of what c++ provides and procedural programing don't...Bit lengthy but trust me totally worth..
RITESH
//Multilevel Inheritance
#include<iostream>
using namespace std;
class student
{
private:
int rl;
char nm[20];
public:
void read();
void display();
};
class marks: public student
{
protected:
int s1;
int s2;
int s3;
public:
void getmarks();
void putmarks();
};
class result: public marks
{
private:
int t;
float p;
char div[10];
public:
void process();
void printresult();
};
void student:read()
{
cout<<"Enter Roll no : ";
cin>>rl;
cout<<"Enter Name : ";
cin>>nm;
}
void student: display()
{
cout <<"\nRoll no : "<<rl<<endl;
cout<<"Name : "<<nm<<endl;
cout<<"\n";
}
void marks:getmarks()
{
cout<<"Enter marks for 3 subjects : "<<endl;
cin>>s1>>s2>>s3;
}
void marks:putmarks()
{
cout<<"Subject 1 :"<<s1<<endl;
cout<<"Subject 2 : "<<s2<<endl;
cout<<"Subject 3 : "<<s3<<endl;
}
void result:process()
{
t= s1+s2+s3;
p = t/3.0;
p>=60strcpy(div,"First"):p>=50strcpy(div,"Second"): strcpy(div,"Third");
}
void result:printresult()
{
cout<<"Total "<<t<<endl;
cout<<"\n";
cout<<"Percentage = "<<p<<endl;
cout<<"Division = "<<div<<endl;
}
int main()
{
result x;
x.read();
x.getmarks();
x.process();
x.display();
x.putmarks();
x.printresult();
return 0;
}
Can anyone tell where the error is coming but please what is the mistake
Anonymous
//Multilevel Inheritance
#include<iostream>
using namespace std;
class student
{
private:
int rl;
char nm[20];
public:
void read();
void display();
};
class marks: public student
{
protected:
int s1;
int s2;
int s3;
public:
void getmarks();
void putmarks();
};
class result: public marks
{
private:
int t;
float p;
char div[10];
public:
void process();
void printresult();
};
void student:read()
{
cout<<"Enter Roll no : ";
cin>>rl;
cout<<"Enter Name : ";
cin>>nm;
}
void student: display()
{
cout <<"\nRoll no : "<<rl<<endl;
cout<<"Name : "<<nm<<endl;
cout<<"\n";
}
void marks:getmarks()
{
cout<<"Enter marks for 3 subjects : "<<endl;
cin>>s1>>s2>>s3;
}
void marks:putmarks()
{
cout<<"Subject 1 :"<<s1<<endl;
cout<<"Subject 2 : "<<s2<<endl;
cout<<"Subject 3 : "<<s3<<endl;
}
void result:process()
{
t= s1+s2+s3;
p = t/3.0;
p>=60strcpy(div,"First"):p>=50strcpy(div,"Second"): strcpy(div,"Third");
}
void result:printresult()
{
cout<<"Total "<<t<<endl;
cout<<"\n";
cout<<"Percentage = "<<p<<endl;
cout<<"Division = "<<div<<endl;
}
int main()
{
result x;
x.read();
x.getmarks();
x.process();
x.display();
x.putmarks();
x.printresult();
return 0;
}
Can anyone tell where the error is coming but please what is the mistake
gcc
a.cpp:37:14: error: found ‘:’ in nested-name-specifier, expected ‘::’
37 | void student : read() {
| ^
| ::
a.cpp:45:14: error: found ‘:’ in nested-name-specifier, expected ‘::’
45 | void student : display() {
| ^
| ::
Anonymous
is this somehow unreadable?
Anonymous
clang
a.cpp:37:14: error: unexpected ':' in nested name specifier; did you mean '::'?
void student : read() {
^
::
a.cpp:45:14: error: unexpected ':' in nested name specifier; did you mean '::'?
void student : display() {
^
::
Anonymous
//Multilevel Inheritance
#include<iostream>
using namespace std;
class student
{
private:
int rl;
char nm[20];
public:
void read();
void display();
};
class marks: public student
{
protected:
int s1;
int s2;
int s3;
public:
void getmarks();
void putmarks();
};
class result: public marks
{
private:
int t;
float p;
char div[10];
public:
void process();
void printresult();
};
void student:read()
{
cout<<"Enter Roll no : ";
cin>>rl;
cout<<"Enter Name : ";
cin>>nm;
}
void student: display()
{
cout <<"\nRoll no : "<<rl<<endl;
cout<<"Name : "<<nm<<endl;
cout<<"\n";
}
void marks:getmarks()
{
cout<<"Enter marks for 3 subjects : "<<endl;
cin>>s1>>s2>>s3;
}
void marks:putmarks()
{
cout<<"Subject 1 :"<<s1<<endl;
cout<<"Subject 2 : "<<s2<<endl;
cout<<"Subject 3 : "<<s3<<endl;
}
void result:process()
{
t= s1+s2+s3;
p = t/3.0;
p>=60strcpy(div,"First"):p>=50strcpy(div,"Second"): strcpy(div,"Third");
}
void result:printresult()
{
cout<<"Total "<<t<<endl;
cout<<"\n";
cout<<"Percentage = "<<p<<endl;
cout<<"Division = "<<div<<endl;
}
int main()
{
result x;
x.read();
x.getmarks();
x.process();
x.display();
x.putmarks();
x.printresult();
return 0;
}
Can anyone tell where the error is coming but please what is the mistake
I understand this is done as an exercise for teaching inheritance but this is a bad example. Ignoring the compiler errors, marks should not be derived from student. A student class should ideally compose marks and result could either be computed from the individual marks every time it is requested or it can be lazily evaluated and stored the first time it is requested.
Aditi
any one help for vaccine distribution
HaiNahi
5*8-(3*(1+4)+4)/(4*(5+2)) my calculator solved this ^^ tail recursion
Apk
RITESH
I understand this is done as an exercise for teaching inheritance but this is a bad example. Ignoring the compiler errors, marks should not be derived from student. A student class should ideally compose marks and result could either be computed from the individual marks every time it is requested or it can be lazily evaluated and stored the first time it is requested.
Can anyone tell me a good example of multiple inheritance which is easy and we can understand
Sandeep
#include <bits/stdc++.h>
using namespace std;
void swap(int& a, int& b)
{
int temp = a;
a = b;
b = temp;
}
void rotate(int a[], int n, int idx)
{
int i;
for (i = 0; i < idx / 2; i++)
swap(a[i], a[idx - 1 - i]);
for (i = idx; i < (n + idx) / 2; i++)
swap(a[i], a[n - 1 - (i - idx)]);
for (i = 0; i < n / 2; i++)
swap(a[i], a[n - 1 - i]);
}
void sol(int a1[], int a2[], int n, int m)
{
int l = 0, h = n - 1, idx = 0;👈👈👈👈what is idx significance anybody
//---------------------------------------------------------
while (l <= h) {
// select the median of the remaining subarray
int c1 = (l + h) / 2;
// select the first elements from the larger array
// euqal to the size of remaining portion to the
// right of the smaller array
int c2 = n - c1 - 1;
int l1 = a1[c1];
int l2 = a2[c2 - 1];
int r1 = c1 == n - 1 ? INT_MAX : a1[c1 + 1];
int r2 = c2 == m ? INT_MAX : a2[c2];
// compare the border elements and check for the
// target index
if (l1 > r2) {
h = c1 - 1;
if (h == -1)
idx = 0;
}
else if (l2 > r1) {
l = c1 + 1;
if (l == n - 1)
idx = n;
}
else {
idx = c1 + 1;
break;
}
}
for (int i = idx; i < n; i++)
swap(a1[i], a2[i - idx]);
sort(a1, a1 + n);
sort(a2, a2 + m);
}
void merge(int arr1[], int arr2[], int n, int m)
{
// code here
if (n > m) {
sol(arr2, arr1, m, n);
rotate(arr1, n, n - m);
for (int i = 0; i < m; i++)
swap(arr2[i], arr1[i]);
}
else {
sol(arr1, arr2, n, m);
}
}
int main()
{
int ar1[] = { 1, 5, 9, 10, 15, 20 };
int ar2[] = { 2, 3, 8, 13 };
int m = sizeof(ar1) / sizeof(ar1[0]);
int n = sizeof(ar2) / sizeof(ar2[0]);
merge(ar1, ar2, m, n);
cout << "After Merging \nFirst Array: ";
for (int i = 0; i < m; i++)
cout << ar1[i] << " ";
cout << "\nSecond Array: ";
for (int i = 0; i < n; i++)
cout << ar2[i] << " ";
return 0;
}
Anonymous
Can anyone tell me a good example of multiple inheritance which is easy and we can understand
Multiple inheritance is usually used to refer to the cases where a class derives from 2 or more base classes directly. What you have is just plain inheritance down to multiple levels which is not essentially the same. AFAIK in 6 years of professional development I have not seen code where multiple inheritanceis used. Most of the times when duck typing needs to be emulated, C++ programmers usually choose what Java developers do. Inherit interfaces.
Most of the code out there instead uses composition and aggregation to model relationships.
Anonymous
This program is for merging two sorted arrays without extra space
Why dont you try debugging it and see what it does? The code is not very reader friendly. I doubt if anyone will go through that big chunk of mess and figure out what the purpose of a single variable is. Debugger is your best friend here.
Sandeep
Why dont you try debugging it and see what it does? The code is not very reader friendly. I doubt if anyone will go through that big chunk of mess and figure out what the purpose of a single variable is. Debugger is your best friend here.
I did...I can see what is happing but I don t understand why
Anonymous
Table= (int**)calloc(rowNum+1, sizeof(int*));
I am trying to figure out what is diffrence in pointers to int* and int** in above dynamic ragged array code?
Ravi
Table= (int**)calloc(rowNum+1, sizeof(int*));
I am trying to figure out what is diffrence in pointers to int* and int** in above dynamic ragged array code?
int** means it is again pointing to the int array, i.e. int*, you can consider int as cell, int* as a column and int** as a row.
Ravi
Anonymous
Table= (int**)calloc(rowNum+1, sizeof(int*));
I am trying to figure out what is diffrence in pointers to int* and int** in above dynamic ragged array code?
calloc allocates an array of rownum+1 elements each of which is an int* pointer. The name of this array will decay to a pointer to a int pointer as I mentioned earlier which is why you use a int** pointer. Now each of those individual elements is an int* pointer and hence they can themselves point to an array of ints.
Anonymous
int** means it is again pointing to the int array, i.e. int*, you can consider int as cell, int* as a column and int** as a row.
so int* and int** both point to Zeroth row and coloum?
Ravi
so int* and int** both point to Zeroth row and coloum?
Ammm thats difficult to explain here for me.
Anonymous
so int* and int** both point to Zeroth row and coloum?
Int** points to an array of int* pointers. It doesnt point to the element in the zeroth row and zeroth column. The first int* pointer after it is made to point to allocated memory will point to the first element in the array that it is pointing to. And in your Original post you mentioned it is a jagged array. So there is no concept of rows and columns. If all the int* pointers point to arrays of the same size, then the first int* pointer will point to the element in 0th row and zeroth column.
Anonymous
i* = 1d array i** = 2d array i*** = 3d array
Not necessarily.
int arr[3][3];
int** ptr = arr; //this wont work
Anonymous
please use malloc
Sandeep
Why dont you try debugging it and see what it does? The code is not very reader friendly. I doubt if anyone will go through that big chunk of mess and figure out what the purpose of a single variable is. Debugger is your best friend here.
So I debugged ..and I found out that idx is returns the median of both the arrays combined...but ..after that ..he is swapping...the remaining elements with the elements from the second array...like what if ...already are like...1 2 3 4 and 5 6 7 8...in this case we don't have to swap no?
Anonymous
So I debugged ..and I found out that idx is returns the median of both the arrays combined...but ..after that ..he is swapping...the remaining elements with the elements from the second array...like what if ...already are like...1 2 3 4 and 5 6 7 8...in this case we don't have to swap no?
I have no idea. I didnt read that code at all. Like I said debug it for the case you mentioned and find out what happens. This is a good exercise for you.
Sandeep
/warn @MissRose_bot wtf
klimi
Picky
Is there anyone who can give me any online works? Actually I have to bear my University cost so i have to work plz
Ram saran
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Anonymous
Is there anyone who can give me any online works? Actually I have to bear my University cost so i have to work plz
Try some freelancing work. There are sites like TopTal.com which could be of help
PREM SAGAR
Mr.007, [28.06.21 23:33]
Mr.007, [28.06.21 22:47]
#include<iostream.h>
#include<conio.h>
#include<dos.h>
#include<stdlib.h>
#include<graphics.h>
#define LEFT 75
#define RIGHT 77
#define UP 72
#define DOWN 80
#define ENTER 13
class CAR
{
public:
int cp, init, op1, op2, op3; //initializing car,and obstacles
CAR::CAR() //creating constructor for the class car
{
cp = 300; //putting car value at 300
init = 0;
op1 = 0; //1st obstacle starts from 0
op2 = -20; //2nd obstacle starts 20 behind the 1st obstacle
op3 = -40; //3rd one starts 40 behind the 1st one
}
}
car; //object
int randx( void ) //creating function for random obstacle appearance
{
int x = random( 55*8 );//using random function to choose a random valuefor random obstacle
if ( x < 25*8 )//if the x axis distance is less then 25 the obstacle lies outside the lane
{
x = x + ( 25 *8 );//so we add 25 to keep the values in the lane
}
return ( x );
}
void right() //this is called to perform right dirn movement
{
if ( car.cp < 420 ) //here the class object is compared
{
car.cp += 10;//to move the car from 10 dirn
}
return ;
}
void left() //this is for left dirn
{
if ( car.cp > 180 ) //for left movement
{
car.cp -= 10;
}
return ;
}
void bgmove() //car body and its movement
{
if ( car.init > 5 )
{
car.init = 1;//init set to one
}
setcolor( RED ); //car body
setfillstyle( SOLID_FILL,WHITE );//fills the block into colour assigned
sector( car.cp + 20, 330, 0, 180, 20, 30 );//formation of ellipse head of car
setfillstyle( SOLID_FILL,RED );
bar3d( car.cp, 333, car.cp + 37, 360, 4, 4 );//function to create a block i.e. looks as a cube
for ( int i = car.init;i < 70;i += 5 )//for the design of lane
{
setcolor(BLUE );
setfillstyle( 1, BLUE );
bar( 16 * 8, i * 8, 20 * 8, ( i + 2 ) * 8 );//creating walls forming at side of road
bar( 60 * 8, i * 8, 64 * 8, ( i + 2 ) * 8 );
}
return ;
}
void opp1( int x1 )//obstacle 1
{
if ( car.op1 < 600 )
{
car.op1 += 10;
setfillstyle( 1, RED );
bar3d( x1, car.op1, x1 + 30, car.op1 + 30, 2, 3 );
}
else
{
car.op1 = 0;
}
return ;
}
void opp2( int x2 )//obstacle 2
{
if ( car.op2 < 600 )
{
car.op2 += 10;
setfillstyle( 1, YELLOW );
bar3d( x2, car.op2, x2 + 30, car.op2 + 30, 2, 3 );
}
else
{
car.op2 = 0;
}
return ;
}
void opp3( int x3 ) //obstacle 3
{
if ( car.op3 < 600 )
{
car.op3 += 10;
setfillstyle( 1, BLUE );
bar3d( x3, car.op3, x3 + 30, car.op3 + 30, 2, 3 );
}
else
{
car.op3 = 0;
}
return ;
}
int check( int x, int op, int cp ) //collision part
{
int a[ 31 ], b[ 31 ], c[ 40 ], d[ 50 ];//let the sizes randomly or just let according to loop
for ( int i = 0;i < 30;i++ )
{
a[ i ] = x + i; //random value suppled + i using loop
}
for ( i = 0;i < 30;i++ )
{
b[ i ] = op + i;//returned obstacle value
}
for ( i = 0;i < 40;i++ )
{
c[ i ] = cp + i; //returned car value
}
PREM SAGAR
Mr.007, [28.06.21 23:33]
Mr.007, [28.06.21 22:47]
for ( i = 0;i < 50;i++ )
{
d[ i ] = 300 + i; //
}
for ( i = 0;i < 40;i++ )
{
for ( int j = 0;j < 50;j++ )
{
for ( int k = 0;k < 30;k++ )
{
if ( a[ k ] == c[ i ] && b[ k ] == d[ j ] )
return 1;
}
}
}
return 0;
}
PREM SAGAR
void logo ()
{
for ( int i = 1;i < 250;i++ ) //for the introduction part
{
int p;
setcolor( YELLOW );
setfillstyle( SOLID_FILL, LIGHTBLUE );
settextstyle( 7, HORIZ_DIR, 5 );
outtextxy( 65, 100,"HCOE GRAPHICS PROJECT" );
outtextxy(150,150 ," RACING GAME " );
outtextxy(150,200," 070 BCT B ");
setcolor( WHITE );
settextstyle( 2, HORIZ_DIR, 5 );
outtextxy(150,250, "PRESENTED TO : DEPARTMENT OF ELECTRONICS AND COMPUTER " );
outtextxy(150,300, "PRESENTED BY : ROLL NOS (48,50,52,57,64)");
}
delay( 2000 );
cleardevice();
return ;
}
void over( void )//after collision this is to show the game over
{
for ( int i = 1;i < 35;i++ )
{
cleardevice();
delay( 20 );
settextstyle( 1, 0, 6 );
setcolor( RED );
outtextxy( 150, 100, "!!!GAME OVER!!!" );
delay( 20 );
}
delay( 2000 );
cleardevice();
getch();
return ;
}
void about() //menu part and control the menu
{
while ( !kbhit() )
{
for ( int i = 300;kbhit() == 0;i++ )
{
cleardevice();
setcolor( 6 );
settextstyle( 2, 0, 6 );
outtextxy( 600 - i, 600 - i, "season maharjan(48)" );
outtextxy( i - 150, 215, "yaju shrestha(64)" );
outtextxy( i - 30, i - 130, "smriti mool(52)" );
outtextxy( 600 - i, i - 150, "shiwangi shrestha(50)" );
outtextxy( 600 -i, i -300 , "sushmita chaurasia(57)" );
setfillstyle( 1, 4 );
setcolor( 1 );
settextstyle( 2, 0, 10 );
outtextxy( 280, 380, "HCOE" );
outtextxy( 215, 420, "O70 BATCH" );
delay( 60 );
}
}
getch();
return ;
}
\
PREM SAGAR
int play( void )//if the play is entered by user
{
int life = 1, m, x1, x2, x3, s;//assigning values for life, m for selection
//x1,x2,x3 for random values from the randx function
re:
while ( life ) //check the life value to enter the while loop
{
cleardevice();
if ( car.op1 == 0 ) //
{
x1 = randx();//getting the random values
car.op1++;//calling the obstacle in class and incrementing
}
else
{
opp1( x1 );//if not equal to zero print the obstacle
}
if ( car.op2 == 0 )//for obstacle 2
{
x2 = randx();
car.op2++;
}
else if ( car.op2 < 1 ) //for obstacle valueless than 1
{
car.op2++;
}
else
{
opp2( x2 );
}
if ( car.op3 == 0 ) //for obstacle no 3
{
x3 = randx();
car.op3++;
}
else if ( car.op3 < 1 )
{car.op3++;}
else
{
opp3( x3 );
}
setcolor( 10 );
bgmove(); //calling move function for car to appearin sceen
if ( check( x2, car.op2, car.cp ) || check( x1, car.op1, car.cp ) || check( x3, car.op3, car.cp ) )
{ //checking the collision condition from the check function
life--;
if ( life == 0 )
{
over();//calling the over fuction for finishing the game
}
car.op1 = 1; //initializing the obstacle
car.op2 = -16;
car.op3 = -32;
goto re;//using goto to repeat the processes always
}
if ( kbhit() )//check the key stroke
{
m = getch();
switch ( m ) //key stroke decision using switch case
{
case LEFT: left();//for left arrow
break;
case RIGHT: right(); //for right arrow key
break;
case 'q': exit( 0 ); //to exit the game when ever the user want to
}
}
else
{
delay( 100 );
}
}
getch();
return ( 0 );
}
void menu()//for the menu appearance
{
int s = 1, t = 0, a, p = 140;//here s is for keystroke selection in switch case
do//to contiue the program after finish
{ //here a is for the rectangle to move up and down
do //p for rectangle use in menu
{
cleardevice();
setcolor( YELLOW );
settextstyle( 1, 0, 4 );
outtextxy( 230, 30, "MENU" );Mr.007, [28.06.21 23:33]
Mr.007, [28.06.21 22:47]
PREM SAGAR
for ( i = 0;i < 50;i++ )
{
d[ i ] = 300 + i; //
}
for ( i = 0;i < 40;i++ )
{
for ( int j = 0;j < 50;j++ )
{
for ( int k = 0;k < 30;k++ )
{
if ( a[ k ] == c[ i ] && b[ k ] == d[ j ] )
return 1;
}
}
}
return 0;
}
PREM SAGAR
void logo ()
{
for ( int i = 1;i < 250;i++ ) //for the introduction part
{
int p;
setcolor( YELLOW );
setfillstyle( SOLID_FILL, LIGHTBLUE );
settextstyle( 7, HORIZ_DIR, 5 );
outtextxy( 65, 100,"HCOE GRAPHICS PROJECT" );
outtextxy(150,150 ," RACING GAME " );
outtextxy(150,200," 070 BCT B ");
setcolor( WHITE );
settextstyle( 2, HORIZ_DIR, 5 );
outtextxy(150,250, "PRESENTED TO : DEPARTMENT OF ELECTRONICS AND COMPUTER " );
outtextxy(150,300, "PRESENTED BY : ROLL NOS (48,50,52,57,64)");
}
delay( 2000 );
cleardevice();
return ;
}
void over( void )//after collision this is to show the game over
{
for ( int i = 1;i < 35;i++ )
{
cleardevice();
delay( 20 );
settextstyle( 1, 0, 6 );
setcolor( RED );
outtextxy( 150, 100, "!!!GAME OVER!!!" );
delay( 20 );
}
delay( 2000 );
cleardevice();
getch();
return ;
}
void about() //menu part and control the menu
{
while ( !kbhit() )
{
for ( int i = 300;kbhit() == 0;i++ )
{
cleardevice();
setcolor( 6 );
settextstyle( 2, 0, 6 );
outtextxy( 600 - i, 600 - i, "season maharjan(48)" );
outtextxy( i - 150, 215, "yaju shrestha(64)" );
outtextxy( i - 30, i - 130, "smriti mool(52)" );
outtextxy( 600 - i, i - 150, "shiwangi shrestha(50)" );
outtextxy( 600 -i, i -300 , "sushmita chaurasia(57)" );
setfillstyle( 1, 4 );
setcolor( 1 );
settextstyle( 2, 0, 10 );
outtextxy( 280, 380, "HCOE" );
outtextxy( 215, 420, "O70 BATCH" );
delay( 60 );
}
}
getch();
return ;
}
int play( void )//if the play is entered by user
{
int life = 1, m, x1, x2, x3, s;//assigning values for life, m for selection
//x1,x2,x3 for random values from the randx function
re:
while ( life ) //check the life value to enter the while loop
{
cleardevice();
if ( car.op1 == 0 ) //
{
x1 = randx();//getting the random values
car.op1++;//calling the obstacle in class and incrementing
}
else
{
opp1( x1 );//if not equal to zero print the obstacle
}
if ( car.op2 == 0 )//for obstacle 2
{
x2 = randx();
car.op2++;
}
else if ( car.op2 < 1 ) //for obstacle valueless than 1
{
car.op2++;
}
else
{
opp2( x2 );
}
if ( car.op3 == 0 ) //for obstacle no 3
{
x3 = randx();
car.op3++;
}
else if ( car.op3 < 1 )
{car.op3++;}
else
{
opp3( x3 );
}
setcolor( 10 );
bgmove(); //calling move function for car to appearin sceen
if ( check( x2, car.op2, car.cp ) || check( x1, car.op1, car.cp ) || check( x3, car.op3, car.cp ) )
{ //checking the collision condition from the check function
life--;
if ( life == 0 )
{
over();//calling the over fuction for finishing the game
}
car.op1 = 1; //initializing the obstacle
car.op2 = -16;
car.op3 = -32;
goto re;//using goto to repeat the processes always
}
if ( kbhit() )//check the key stroke
{
m = getch();
switch ( m ) //key stroke decision using switch case
{
case LEFT: left();//for left arrow
break;
case RIGHT: right(); //for right arrow key
break;
case 'q': exit( 0 ); //to exit the game when ever the user want to
}
}
else
{
delay( 100 );
}
}
getch();
return ( 0 );
}
PREM SAGAR
void menu()//for the menu appearance
{
int s = 1, t = 0, a, p = 140;//here s is for keystroke selection in switch case
do//to contiue the program after finish
{ //here a is for the rectangle to move up and down
do //p for rectangle use in menu
{
cleardevice();
setcolor( YELLOW );
settextstyle( 1, 0, 4 );
outtextxy( 230, 30, "MENU" )
artemetra 🇺🇦
Dima
What the heck
PREM SAGAR
please
PREM SAGAR
now brother
Golden Age Of
PREM SAGAR
tq brother
ram
Thank You @ravi
ram
https://codeforces.com/contest/1535/problem/B
ram
#include<bits/stdc++.h>
using namespace std;
int gcd(int a, int b)
{
if (b == 0)
return a;
return gcd(b, a % b);
}
int main()
{
int t,n,ev=0,num,ans=0;
vector <int> vec;
cin >>t ;
while(t--)
{
cin >> n;
for(int no=0;no<n;no++)
{
cin >> num;
if(num%2==0)
{
ans=ans+n-1-ev;
ev++;
}
else
vec.push_back(num);
}
for(int no=0;no<vec.size()-1;no++)
{
for(int no1=no+1;no1<vec.size();no1++)
if(gcd(vec[no],vec[no1])>1)
ans++;
}
cout << ans<<"\n";
ans=0;
ev=0;
vec.clear();
}
}
ram
I am getting time limit exceeded
Hermann
what is the difference between A a (p); and A {p};?. p is a struct
Igor🇺🇦
what is the difference between A a (p); and A {p};?. p is a struct
You don't create any variable in the second case.
Anonymous
what is the difference between A a (p); and A {p};?. p is a struct
A{p} can match a initializer_list constructor. A a(p) cannot.
struct P {
int p = 0;
};
struct A {
int a = 0;
A(P p) { cout << "1"; }
A(initializer_list<P> l) { cout << "2"; }
};
int main() {
P p;
A a(p);
A{p};
}
For example, this code will output "12".
Anonymous
I am getting time limit exceeded
Use GDB, you will find why you got TLE.
for(int no=0;no<vec.size()-1;no++) // vec.size() - 1 underflow if vec is empty