Ya I got it man thanks buddy 👍

Char array....

int & foo (const int & a , const int & b) { return (a/b); }

I've never been using getch() on linux and it looks like one big problem...

Here's how I solved getch on Linux: https://github.com/Newbytee/text-roguelike/blob/experimental/ASCII%20Roguelike/Utils.cpp

Is it possible to create alias for variadic template parameter pack inside a class? Or somehow else allow it be accessed outside of the class For example to do something like this template<typename... Ts> struct Filter { using Components = Ts...; ... }; template <typename Filter> void test() { using Components = Filter::Components...; ... }

You could use a tuple to allow access the types template<typename... Ts> struct Filter { using Components = std::tuple<Ts...>; }; template <typename Filter> void test() { using Components = typename Filter::Components; }

Is it possible to create alias for variadic template parameter pack inside a class? Or somehow else allow it be accessed outside of the class For example to do something like this template<typename... Ts> struct Filter { using Components = Ts...; ... }; template <typename Filter> void test() { using Components = Filter::Components...; ... }

template<typename... T> struct store{ template <template <typename...> class X> using convert = X<T...> };

hello, friends, The two's complement is calculated by inverting the bits and adding one. e.g., three bits signed integer, -1's two complement: 001( invert)->110(plus one)->111 But how to get -128's two complement?(using 8 bits)

if we have some code like this: char ch＝ -128; I know in memory, ch is 1000 0000, but how computer get this number?

I think two's complement of -128 is 10000001

Actually for negative no. Compiler do 2 times 2's complement ....

According to my knowledge negative number are stored in the form of 2's complement only

I think two's complement of -128 is 10000001

Ok intelligent girl... So tell me what is your results after 2's and before 2's complement.... What is the no. that your bit represent here ?

Listen I am converting -2 firstly to one's complement and then adding 1 to this to get 2's complement

Ok... But have you got the right answer ?

Does anyone have functions and pointers notes of C language??

Does anyone have functions and pointers notes of C language??

using a = store<int, double, char> using b = typename a::template convert<std::tuple>

can someone explain the flow of program

then why they asked this kind of problems in mcq type exams?

what should i do in exam if they asks this kind of questions?

what should i do in exam if they asks this kind of questions?

Yes... You're right... They asked..... But it will give right answer if you write i upto 3 -4 times instead of 7 times........

will do thanks appreciate your help

there is no right answer for undefined behaviour just like there is no right answer for 1 / 0 in the context of the field of the real numbers

As I learned , In print function evaluation is done from right to left and printing of value done from left to right... And it's true

As I learned , In print function evaluation is done from right to left and printing of value done from left to right... And it's true

As I learned , In print function evaluation is done from right to left and printing of value done from left to right... And it's true

Please don't mind chandreep... 👍

I saw that bug on that cpp site... But there is possibility of prediction....

In this call it doesn’t matter whether the arguments are passed from left to right or from right to left. However, in some function call the order of passing arguments becomes an important consideration. For example: int a = 1 ; printf ( "%d %d %d", a, ++a, a++ ) ; It appears that this printf( ) would output 1 2 3. This however is not the case. Surprisingly, it outputs 3 3 1. This is because C’s calling convention is from right to left. That is, firstly 1 is passed through the expression a++ and then a is incremented to 2. Then result of ++a is passed. That is, a is incremented to 3 and then passed. Finally, latest value of a, i.e. 3, is passed. Thus in right to left order 1, 3, 3 get passed. Once printf( ) collects them it prints them in the order in which we have asked it to get them printed (and not the order in which they were passed). Thus 3 3 1 gets printed......

#include<stdio.h> #include<stdint.h> #define CRC16 0x8005 uint16_t gen_crc16(const uint8_t *data, uint16_t size) { uint16_t out = 0; int bits_read = 0, bit_flag; printf("\nCRC %s\n", data); if(data == NULL) return 0; while(size > 0) { bit_flag = out >> 15; out <<= 1; out |= (*data >> bits_read) & 1; bits_read++; if(bits_read > 7) { bits_read = 0; data++; size--; } if(bit_flag) out ^= CRC16; } int i; for (i = 0; i < 16; ++i) { bit_flag = out >> 15; out <<= 1; if(bit_flag) out ^= CRC16; } uint16_t crc = 0; i = 0x8000; int j = 0x0001; for (; i != 0; i >>=1, j <<= 1) { if (i & out) crc |= j; } return crc; } int main() { char buf[]="89654221256565656"; int c , r; printf ("crc check %s", buf); r = gen_crc16(buf,sizeof(buf)-1); printf("%04hx\n", r); return (0); }