@programminginc - страница 3052

fluffy

Hi

Ayaan

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

Apk

Hi guys I need a suggestion Recently i got a paid internship from verzeo via Quiz on google forms I am not sure abt that whthwr it was worth Can anybody guide me so that i can dm them

It's most probably not

Ayaan

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

Help 🥺

Alfredo

Help 🥺

Read the pinned message.

@𝑺𝒐𝒃𝒌𝒂

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

Try it first.

Anshul

Try it first.

In your profile pic, which language it is 😅

Dumb

In your profile pic, which language it is 😅

Maybe it's phyton

Ayaan

Try it first.

Did not happen

@𝑺𝒐𝒃𝒌𝒂

In your profile pic, which language it is 😅

Lol. It is a pseudo-code.

Ayaan

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

It's not just coming that way

Ayaan

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

??

Apk

It's not just coming that way

show what you tried then only someone would be able to help

Ayaan

show what you tried then only someone would be able to help

{ int n = 5; for(int i = 1; i <= n; i++) { for(int j = n - i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; return 0;

Ayaan

show what you tried then only someone would be able to help

?

Ayaan

Write a program to print the following pattern using nested loop. 1 2 3 4 5 2 3 4 5 3 4 5 4 5 5

Anshul

{ int n = 5; for(int i = 1; i <= n; i++) { for(int j = n - i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; return 0;

n-i will be 4 instead of 5

Anshul

And also you want to print from 1 to 5 not 5 to 1

Anshul

Waah kya naam h 😂👍

klimi

Waah kya naam h 😂👍

Lol yes

Oumer

{ int n = 5; for(int i = 1; i <= n; i++) { for(int j = n - i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; return 0;

change for(int j = n - i; j >= 0; j--) in to for(in for(int j = i; j >= 0; j--)

Oumer

{ int n = 5; for(int i = 1; i <= n; i++) { for(int j = n - i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; return 0;

did it work

Ayaan

did it work

Wait bro i gonna check

Ayaan

did it work

Not work

Ayaan

did it work

#include<iostream> using namespace std; int main() { int n = 5; for(int i = 1; i <= n; i++) { for(int j = i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; }}

Ayaan

#include<iostream> using namespace std; int main() { int n = 5; for(int i = 1; i <= n; i++) { for(int j = i; j >= 0; j--) { cout<<j<<" "; } cout<<endl; }}

Still not working

@𝑺𝒐𝒃𝒌𝒂

Still not working

#include <iostream> using namespace std; int main() { for(int i = 1; i <= 5; i++) { for(int j = i; j <= 5; j++) { cout<<j<<" "; } cout<<endl; } return 0; }

@𝑺𝒐𝒃𝒌𝒂

#include <iostream> using namespace std; int main() { for(int i = 1; i <= 5; i++) { for(int j = i; j <= 5; j++) { cout<<j<<" "; } cout<<endl; } return 0; }

One of the possibilities 👆

Ayaan

#include <iostream> using namespace std; int main() { for(int i = 1; i <= 5; i++) { for(int j = i; j <= 5; j++) { cout<<j<<" "; } cout<<endl; } return 0; }

😊 thanks bro

Ayaan

#include <iostream> using namespace std; int main() { for(int i = 1; i <= 5; i++) { for(int j = i; j <= 5; j++) { cout<<j<<" "; } cout<<endl; } return 0; }

Thanks u so much.....

Ayaan

One of the possibilities 👆

Ya its working

@𝑺𝒐𝒃𝒌𝒂

Ya its working

,, 👍

Mar!o

https://github.com/MarioSieg/ExtendedVariant If anyone is interested, I'm currently writing a tiny single header library - an easy to use and clean alternative to std::variant and I'm looking for contributors. It makes using variants much cleaner and nicer and it allows for more customization if needed. No more std::holds_alternative or std::visit with functor structs or verbose lambdas! It still supports the STL interface like std::variant so it works as a drop in replacement too.

.

Why am I getting an error?

.

int main() { int primos por mostrar, n, d; int es primo; printf("Cuantos primos desea mostrar: "); scanf("%d", &primos por mostrar); n = 2; while (primos por mostrar > 0) { /* determinar si n es primo */ es_primo = 1; for (d = 2; d < n; ++d) { if (n % d == 0) { es_primo = 0; break; } } /* mostrar el numero * y actualizar el contador */ if (es primo) { printf("%d ", n); primos por mostrar--; } n++; } printf("\n"); return 0;

.

In the int

@𝑺𝒐𝒃𝒌𝒂

Why am I getting an error?

The name of some variable doesn't match with the rule. No whitespace is allowed. Instead of primos por mostrar, es primo, you should write primos_por_mostrar/primosPorMostrar, es_primo/esPrimo.

Diego

int main() { int primos por mostrar, n, d; int es primo; printf("Cuantos primos desea mostrar: "); scanf("%d", &primos por mostrar); n = 2; while (primos por mostrar > 0) { /* determinar si n es primo */ es_primo = 1; for (d = 2; d < n; ++d) { if (n % d == 0) { es_primo = 0; break; } } /* mostrar el numero * y actualizar el contador */ if (es primo) { printf("%d ", n); primos por mostrar--; } n++; } printf("\n"); return 0;

You can't have spaces in your variables

Anonymous

thanks

Anonymous

You forgot "return" before check(arr,n-1) in the else part.

B121065_Swoyam Siddharth Nayak

ohkay

B121065_Swoyam Siddharth Nayak

the problem is solved, thank you

Anonymous

ohkay

If you delete your message after asking a question, it will just make my answer meaningless

B121065_Swoyam Siddharth Nayak

If you delete your message after asking a question, it will just make my answer meaningless

sorry brother, but your solution worked

B121065_Swoyam Siddharth Nayak

sorry

Hanz

bruh

Hanz

that is unfortunate, but the keyword "answer is wrong" mean something for me 🤔

TechGuy

hi

Anonymous

how can i call the constructor of a base class without having to declare it explicitly in its derived class?

Diego

You can't

Anshul

You have to make a new constrictor in derived class. Because then only you can initialise the derived class members

Anshul

Else compiler will make default constructor and the base class constructor will be called by this default constructor itself

Anonymous

eg class A { public: A(int unused); } A::A(int unused) {}; class DERIV: public A {}; // candidate constructor (the implicit default constructor) not viable: requires 0 arguments, but 1 was provided DERIV x = DERIV(5);

Anshul

eg class A { public: A(int unused); } A::A(int unused) {}; class DERIV: public A {}; // candidate constructor (the implicit default constructor) not viable: requires 0 arguments, but 1 was provided DERIV x = DERIV(5);

It won't work I think

Anshul

Because derived class default constructor can call only default constructor of base class

Anonymous

🙁

Anshul

eg class A { public: A(int unused); } A::A(int unused) {}; class DERIV: public A {}; // candidate constructor (the implicit default constructor) not viable: requires 0 arguments, but 1 was provided DERIV x = DERIV(5);

To make it correct make this in your derived class DERIV(int x):A(x) { }

Anonymous

welp i came up with this #ifdef CORRADE_TARGET_ANDROID #define CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_CPP(class_, className) #define CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_HPP(class_) #else #define CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_CPP(class_, className) class_::className(const Magnum::Platform::Sdl2Application::Arguments &arguments) : Crafter::Package{arguments} {} #define CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_HPP(class_) explicit class_(const Magnum::Platform::Sdl2Application::Arguments &arguments) #endif class Draw_Color : public Crafter::Package { public: CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_HPP(Draw_Color); void drawEvent() override; }; CRAFTER_PACKAGE_CONSTRUCTOR_WRAPPERS_CPP(Crafter::Packages::Draw_Color, Draw_Color) void Crafter::Packages::Draw_Color::drawEvent() { swapBuffers(); GL::defaultFramebuffer.clear(GL::FramebufferClear::Color); }

Anonymous

so i do not have to copy ifdefs to all my classes and cpp files

Top most

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