/warn *bonk*

for(i=0; i<size; i++) { if(arr[i] == toSearch) { found = 1; break; } }

what break statement doing here i mean its use?

what break statement doing here i mean its use?

it will break the loop immediately

and what about value of i ?

wdym?

if say 3==toSearch true will i update its value to 3 even outside of for loop

if say 3==toSearch true will i update its value to 3 even outside of for loop

i havent experiment with that but if variable i declared outside of the for loop, you could use its latest value

if say 3==toSearch true will i update its value to 3 even outside of for loop

Its value is already became 3, that's why it broke the loop

if i do - printf("%d", i); right after loops end will i =3 ?

if i do - printf("%d", i); right after loops end will i =3 ?

try it man

if i do - printf("%d", i); right after loops end will i =3 ?

Yes

Yes

but when i tried without break i is giving different value why is it so?

Actually no, I didn't noticed it is post increment

It's value has become 4 now

Yes

Sorry my mistake

np thanks for help

👍

but when i tried without break i is giving different value why is it so?

when you remove the break keyword, the for loop keep adding value to variable i

when you remove the break keyword, the for loop keep adding value to variable i

got it thanks

#include<stdio.h> int main(){ int i; int j; for(int i = 0; i < 10; i++){ } printf("j: %d, i: %d \n", j,i); return 0; }

output- j:50 i:0

why j is 50 ? without initialization

is that a garbage value

in my machine: j: 0, i: 32767

in my machine: j: 0, i: 32767

so its undefine behaviour

so its undefine behaviour

im not that advance yet 😂

output- j:50 i:0

J must be garbage value but why I is 0? It should be 11,right?

im not that advance yet 😂

np will learn together

J must be garbage value but why I is 0? It should be 11,right?

how about removing the int i = 0 declaration? Like so: for(i = 0; i < 10; i++){

J must be garbage value but why I is 0? It should be 11,right?

yes that is what i was hoping but i dont know

oops false reply

J must be garbage value but why I is 0? It should be 11,right?

#include<stdio.h> int main(){ int i; // int j=5; for( i = 0; i < 5; i++){ printf("%d", i); } printf("%d", i); return 0; }

now it gives i=5

now it gives i=5

Yeah it is right

gret

#include<stdio.h> int main(){ int i; // int j=5; for( i = 0; i < 5; i++){ printf("%d", i); } printf("%d", i); return 0; }

If you do I<=5 it will give 6

Yeah it is right

so conclustion -if you initiatilize int i in for loop has its own scope you cant access it outside

so conclustion -if you initiatilize int i in for loop has its own scope you cant access it outside

It seems to be wrong statement

It's just the post increment operator

no you can check by urself try to print the same program

no you can check by urself try to print the same program

Ok I'll check

post increment operator - may be

let me check that too

no you can check by urself try to print the same program

You were right bro, all the variable initialised inside for loop have scope in the for loop only not outside it

You were right bro, all the variable initialised inside for loop have scope in the for loop only not outside it

i tried pre and post increment no effect on output so its all about initilization

Yes

Can someone help my c programming exam?

Can someone help my c programming exam?

no

Well it depends

Can someone help my c programming exam?

How much are you willing to pay?

How much are you willing to pay?

30 dollar if u can do over 85 points

Can someone help my c programming exam?

Why not... I'll try in free

How can we help you with an exam? I haven't passed my exam yet. What are you going to do once you pass your exam? Ask someone to do your work for you?

Can someone help my c programming exam?

Wait, it's illegal

How can we help you with an exam? I haven't passed my exam yet. What are you going to do once you pass your exam? Ask someone to do your work for you?

+1

I think helping someone is not illegal

I think helping someone is not illegal

I think you should opt for that exam yourself and ask doubts later

#include<stdio.h> int main(){ int i; // int j=5; for( i = 0; i < 5; i++){ printf("%d", i); } printf("%d", i); return 0; }

It gives 5 because the increment part in for loop execute after completion of each time off all the statements... So when i=4 and it execute all statement in loop then it goes to increment part where it become 5 then then it check condition where it find (i<5) so condition is false therefore it exit. In simple word understand if loop condition is (i<5) then after execution of for loop i will be 5 and If (i<=5) then in last i will be 6

I think you should opt for that exam yourself and ask doubts later

If i can i’ll do

Anyone having simplest approach on finding first non repetitive element in a word/string. Time complexity doesn't matter.

?

It is working using hashmap, but is there any simpler approach?

If i can i’ll do

Good luck!

🚲

🤔since l am asking for help in a game card in C++ here but no one is responding 😐

🤔since l am asking for help in a game card in C++ here but no one is responding 😐

I am not that advanced in c, but you can share your problem with me, hope I can help in anyway

I am not that advanced in c, but you can share your problem with me, hope I can help in anyway

C++ not c

C++ not c

Ok

What is the problem?

What is the problem?

To create repository in a directory

Anyone having simplest approach on finding first non repetitive element in a word/string. Time complexity doesn't matter.

Create an array of size 26 of character counts (assuming english alphabets). Iterate through the string once and set the character counts accordingly. Iterate through the string again and choose the first character in the given string that has a count of 1.

To create repository in a directory

Will try

To create repository in a directory

What do you mean by a repository? A source code repository? If yes, then which version control software are you using? If GIT, then a simple "git init" would do the job.

Create an array of size 26 of character counts (assuming english alphabets). Iterate through the string once and set the character counts accordingly. Iterate through the string again and choose the first character in the given string that has a count of 1.

Will try, thankyou

Hola alguien habla español?

Some programmer to help me

?

Can you help me make a code with an options menu that contains bubble sorting, insertion, binary search, invented search

Can you help me make a code with an options menu that contains bubble sorting, insertion, binary search, invented search

I don't know about invented search, but I will try other ones