yes, why?

Do you create any app

I mean any app can create you

I mean any app can create you

What kind of AI is creating humans?

😆

I am begginer for C++.i am not idea how can write a program any one help me?

Anyways let’s stop the negativity here, congrats on being a self taught programmer Udoh

You need not congratulate me. You need congratulate all of us. We are all self taught programmers and that is what you need to do too

You need not congratulate me. You need congratulate all of us. We are all self taught programmers and that is what you need to do too

no hard feelings udoh lets just stop this ok? i admit i’m not a self taught programmer, i’m just a computer science student who was stuck on a homework and wanted support here. And yes its great that everyone is working towards being a proficient programmer.

What is good Dev-cpp or visual studio

Vim

Hello eve, I have two files (hpp,cpp) In the hpp files I declared a overloading function and I want to implement them on the cpp file.

When I’m compile I get an error of all my functions : “must be a unary/binary operator”

Anyone know why?

show me your code

#include <stdio.h> #include <sys/socket.h> #include <errno.h> #include <netdb.h> #include <string.h> #include <stdlib.h> int main(int argc, char **argv){ struct hostent *host; int err, i, sock, start, end; char hostname[100]; struct sockaddr_in sa; printf("Enter hostname or IP:"); gets(hostname); printf("\n"); printf("Enter start port number: "); scanf("%d", &start); printf("\n"); printf("Enter end port number: "); scanf("%d", &end); memcpy((char*)&sa, "", sizeof sa); sa.sin_family = AF_INET; if(isdigit(hostname[0])){ sa.sin_addr.s_addr = inet_addr(hostname); } else if ( (host = gethostbyname(hostname)) != 0){ memcpy((char*)&sa.sin_addr, (char*) host->h_addr, sizeof sa.sin_addr); } else { herror(hostname); exit(2); } for(i = start; i <= end; i++){ printf("Scanning port %i\n",i); sa.sin_port = htons(i); sock = socket(AF_INET, SOCK_STREAM, 0); if(socket < 0){ exit(1); } err = connect(sock, (struct sockaddr*)&sa, sizeof sa); if (err < 0){ fflush(stdout); } else { printf("Port %i is open\n", i); } close(sock); } fflush(stdout); return 0; }

how can i make this to work on atmega32

i want to do some tcp/udp port scanning

hi

Hello everyone

I am fresher to c++

Which book is best for c ++

Please suggest

Which book is best for c ++

read rule 5 in pinned message.

I'm very curious why anyone would prefer autotools

I don't have any vendetta against GNU, but I never found autotools to be very pleasant to work with

I think that Autotools is very hard to understand!

You can't go back and blame the old days

I don't have any vendetta against GNU, but I never found autotools to be very pleasant to work with

/get cppbookguide

/get cppbookguide

Why is this in reply to me

sorry, wrong replying[

Which book is best for c ++

/get cppbookguide

i think you messed your things here, they are different things

i think you messed your things here, they are different things

Are you sure?

Yes

cmake is something else than make for example

and cmake cannot compile by itself like make does

cmake is something else than make for example

Yeah, sure, but CMake and Meson are very comparable

And I think Autotools is comparable to them as well

why is make there then

Idk

wow such c++ related

but it’s QT anyways

wow such c++ related

that happens to you when you do C for way too long

Pls can someone help with this: What is the largest numeric value that could be represented with three bytes if each digit were encoded using one ASCII pattern per byte? What if binary notation were used?

#include <stdio.h> const int MAX = 3; int main () { int var[] = {10, 100, 200}; int i, *ptr; /* let us have array address in pointer */ ptr = var; //MY QUESTION IS ABOUT THIS PART, WHY NOT ptr = &var; for ( i = 0; i < MAX; i++) { printf("Address of var[%d] = %x\n", i, ptr ); printf("Value of var[%d] = %d\n", i, *ptr ); /* move to the next location */ ptr++; } return 0; }

why did they skip "&" in ptr=var; ?

#include <stdio.h> const int MAX = 3; int main () { int var[] = {10, 100, 200}; int i, *ptr; /* let us have array address in pointer */ ptr = var; //MY QUESTION IS ABOUT THIS PART, WHY NOT ptr = &var; for ( i = 0; i < MAX; i++) { printf("Address of var[%d] = %x\n", i, ptr ); printf("Value of var[%d] = %d\n", i, *ptr ); /* move to the next location */ ptr++; } return 0; }

var can be seen as an pointer

var actually points to the first element of that array

this var is array in this programm which of int type right

yes that i know

but still as pointer stores the address of var

so we need & to store the address right?

but still as pointer stores the address of var

No, reread the printf part

wait

No, reread the printf part

im dumb still didnt get it please tell me

instead of %u they used %x i guess

in first printf

ptr has type int * var also have type int * var[1] is actually *(var+1) So assign var to ptr is OK. Then by ptr++ and *ptr, the number stored at each place will be passed to printf

Anyone one have any idea where i can learn c++ for free

ptr has type int * var also have type int * var[1] is actually *(var+1) So assign var to ptr is OK. Then by ptr++ and *ptr, the number stored at each place will be passed to printf

ptr has type int* ✅ var also have type int* ✅, var[1] is pointer to the first element ,✅, so assign var to ptr is basically like assinging pointer to poiner right?

Hey could anyone help on how to encrypt file. Just a simple method not that hard

ptr has type int* ✅ var also have type int* ✅, var[1] is pointer to the first element ,✅, so assign var to ptr is basically like assinging pointer to poiner right?

var[1] is the actually value of the second element, the first one being var[0]，the other are correct

var[1] is the actually value of the second element, the first one being var[0]，the other are correct

sure but is it my statement right that assinging var to ptr is like assigning point (ptr in thsi case) to pointer( var[1]) right?

sure but is it my statement right that assinging var to ptr is like assigning point (ptr in thsi case) to pointer( var[1]) right?

var[1] is int, var is pointer, assign is ok

var[1] is int, var is pointer, assign is ok

ok got it thank you so much i appreciate you time

😁

Hey could anyone help on how to encrypt file. Just a simple method not that hard

....

....

Are you banned in Google or what?

Hey could anyone help on how to encrypt file. Just a simple method not that hard

gpg is ok

Are you banned in Google or what?

This is not how you respond

I already searched

I thought you guys could guide me.

I already searched

https://stackoverflow.com/questions/16219239/simple-encryption-algorithm ....

Ok thanks

Hey could anyone help on how to encrypt file. Just a simple method not that hard

https://stackoverflow.com/questions/180870/what-is-the-best-encryption-library-in-c-c

ptr has type int * var also have type int * var[1] is actually *(var+1) So assign var to ptr is OK. Then by ptr++ and *ptr, the number stored at each place will be passed to printf

this is last question- in this expression " *(var+1) " is var a offset? i just came across this term recently and after seeing this expression cant stop thinking about it.

this is last question- in this expression " *(var+1) " is var a offset? i just came across this term recently and after seeing this expression cant stop thinking about it.

So you can see var as an address, then i is kind of an offset.

But var is actually virtual address, the compiler will take care of that.

thank you for clearing that too

Hello