Btw why <=?

Shouldn't it be strictly less?

how to print any word without using semicolon ;

Do you mean the ; at the end of statement?

so is there any way to writ a program of printing hello world without using a single semicolon

so is there any way to writ a program of printing hello world without using a single semicolon

Also why would you want to remove it?

I searched some tricky c programs so from net there I got this program ,so I thought ask from others

Can we use gets instead of scanf

how to read array elements through user input without asking user to enter its size

Hello again, didn't touch C for a month and now came back to the same easy question that I don't understand why it dosn't work...I remember Olli helped me with this but I forgot what was the answer...(Wasnt on telegram alot..) on C, dividing by minus only.. why it dosn't work?

There are a couple things wrong with this implementation, e.g. while (num2 != 0) ^^^^ { num3 = num1 - num2; ^^^^ cnt++; printf ("%d", num3); } You check num2 for being not 0 but never change it, you reassign the same value to num3 over and over again, since neither num1 nor num2 change in your loop body. In general, checking for 0 is not correct because despite not being zero, 2 cannot be divided by 5.

I see.. So how should I write it to count them? I couldn't figure it out until now...

while (num1 >= num2) { num1 -= num2; ++cnt; }

while (num1 >= num2) { num1 -= num2; ++cnt; }

And then num3 =num1? Or just return num1?

you should return 0; from main if your execution was successful. once main returns your logic ends and you return control back to your operating system which might perform different operations based on the value returned from main. You don't need num3 in your application. in case you want it, because you don't want to change num1 you can assign num1 to num3 before the loop, e.g. num3 = num1; while (num3 >= num2) { num3 -= num2; ++cnt; }

Hey , Is there anyone work in plc programming

1+x¹+x²+x³.........x^n How can i solve this using functions in the C program?

1+x¹+x²+x³.........x^n How can i solve this using functions in the C program?

1+x¹+x²+x³.........x^n How can i solve this using functions in the C program?

İ am new to this, O guess i can't do it

You'll need include <math.h> also for this one

İ am new to this, O guess i can't do it

İts forbidden

🤨

We haven't worked yet

You can't do complicated math with out include <math.h> if I'm not wrong..

Calculating 1+x+x^2... is not hard assuming x is given by user. That's like introduction to loops or recursion level and it's solvable without any of those too.

He wants to do powers.. You need math.h for that no?

He wants to do powers.. You need math.h for that no?

using power function for each term of the summation won't be efficient I guess

Power is just x*x*x.... We're taking about natural numbers only. No need for any special function

But he did powers there

That's the same expression. X^n. N is natural number.

It's the simplest geometric series that has a closed form. You just need to calculate power once.

If its that easy, do it bro 😅

Yes I mean using a function there will result in unnecessary calculations.

That's your homework. There is nothing tricky here.

so there is nothing like 2**3 in c/c++ ?

You have https://en.cppreference.com/w/cpp/numeric/math/pow

Closed formula for this series (1-x^n)/(1-x) for finite n.

Okay....I didn't know the formula

https://en.m.wikipedia.org/wiki/Geometric_progression#Geometric_series