Might be. Do you have any suggestion to fix it?

hello everyone i need to write a c program like : For integers X and Y received from the user (assuming X < Y), write the program that adds all Germain prime numbers in the range of X to Y to an array and prints the elements in this array on the screen. Germain prime numbers are primes such that the number 2p + 1 is also prime. An additional string will not be used in this question. Otherwise, it will be evaluated as 0. also usage of user defined functions, continue and break is illegal. I've been this for 2 days but still i couldn't reach the right output. Here is my code, can someone check it and tell me where my mistake is https://codeshare.io/5v38mn

#include <stdio.h> void my_function1 (int a) { int b; for (b=0; b<a; b++) printf ("Hello world! \n"); printf ("I accept something\n"); printf (" but return nothing\n"); } void main (void) { int a; printf ("Type a number : "); scanf ("%d", &a); my_function1 (a); } Can you guys explain the output error?

#include <stdio.h> void my_function1 (int a) { int b; for (b=0; b<a; b++) printf ("Hello world! \n"); printf ("I accept something\n"); printf (" but return nothing\n"); } void main (void) { int a; printf ("Type a number : "); scanf ("%d", &a); my_function1 (a); } Can you guys explain the output error?

#include <stdio.h> void my_function1 (int a) { int b; for (b=0; b<a; b++) printf ("Hello world! \n"); printf ("I accept something\n"); printf (" but return nothing\n"); } void main (void) { int a; printf ("Type a number : "); scanf ("%d", &a); my_function1 (a); } Can you guys explain the output error?

Change void main to int main

Please find the test case - Pastebin.com https://pastebin.com/M9EYMTtr

What about characters like underscore

What about characters like underscore

May I?

printf("Enter the 5 digit number"); int num; scanf("%d", num); int n1=num%10; int n2=num-n1; int n3=n2%10; int n4=n2-n3; int n5=n4%10; int n6=n4-n5; int n7=n6%10; int n8=n6-n7; int n9=n8%10; int sum=n1+n3+n5+n7+n9; printf(" The sum of the digits is %d", sum);

If you are printing sum of digits of the input, that is probably not the right way

why not ? the question specifically stated to do so using modulo operator

Modulo is fine....but after that you won't do the subtraction

Yeah you do divide the number by 10 since you already included the last digit

Modulo is fine....but after that you won't do the subtraction

why so? logically its correct I think

Try it on 12

I have written that program specefically for 5 digit numbers only ..why is it not running for 5 dig nos?

The problem is same....when you subtract the first time, you are making the number a multiple of 10 so after that the modulus will always give 0

The problem is same....when you subtract the first time, you are making the number a multiple of 10 so after that the modulus will always give 0

Hello, I'm just starting with the C language. Can you suggest a simple to use IDE in C language?

@unterumarmung is that your argument why Eclipse is bad? Removing comments? 😂 So mature.

Eclipse good, but only 1% of users knows that it can-be expanded by plugins

sublime text better

Would you please see my code 😅😅

@Roshan_Pradhan1098 unfortunately I don't code in C++ I code in C and python a little bit

i need your help

can you help me program in c++

can you help me program in c++

What's the problem that you need help?

Do you code in C++ ?

printf("Enter the 5 digit number"); int num; scanf("%d", num); int n1=num%10; int n2=num-n1; int n3=n2%10; int n4=n2-n3; int n5=n4%10; int n6=n4-n5; int n7=n6%10; int n8=n6-n7; int n9=n8%10; int sum=n1+n3+n5+n7+n9; printf(" The sum of the digits is %d", sum);

I have, yes

please pm me so that we can talk

please pm me so that we can talk

printf("Enter the 5 digit number"); int num; scanf("%d", num); int n1=num%10; int n2=num-n1; int n3=n2%10; int n4=n2-n3; int n5=n4%10; int n6=n4-n5; int n7=n6%10; int n8=n6-n7; int n9=n8%10; int sum=n1+n3+n5+n7+n9; printf(" The sum of the digits is %d", sum);

I dont pm random people

Then you will pm me

1. Using these values: m = 12, n = 24, p = 6, q = 3, r = 2, s = 4, and t = 1,, show whether the following Boolean expressions evaluate to ‘true’ or ‘false’ : (i) if (m > p) and (q > s) and (r > t) then print true else print false (ii) if (m > n*p) or (q*r < p) or (p > s+t) then print true else print false (iii) if (m/p = r) and (p-q = r) or (p+q = 2*s) then print true else print false

1. Using these values: m = 12, n = 24, p = 6, q = 3, r = 2, s = 4, and t = 1,, show whether the following Boolean expressions evaluate to ‘true’ or ‘false’ : (i) if (m > p) and (q > s) and (r > t) then print true else print false (ii) if (m > n*p) or (q*r < p) or (p > s+t) then print true else print false (iii) if (m/p = r) and (p-q = r) or (p+q = 2*s) then print true else print false

i don't know how to work on it

i hust pmed you let's talk

Just do it here

Question 1 #include <iostream> using namespace std; int main() { char m=12; char n=24; char p=6; char q=3; char r=2; char s=4; char t=1; int d=12/6; //division int e=6-3; //subtract int a=6+3; //addition string tr= "true"; string fa= "false"; if ((m > p)&&(q > s)&&(r > t)) cout <<" The boolean expressions is: "<< tr; else cout <<" The boolean expressions is: "<< fa; cout << "\n"; cout << "\n"; if ((m > n*p) || (q*r < p) || (p > s+t)) cout <<" The boolean expressions is: "<<tr; else cout <<" The boolean expressions is: " <<fa; cout << "\n"; cout << "\n"; if ((d = r) && (e = r) || (a = 2*s)) cout <<" The boolean expressions is: "<< tr; else cout <<" The boolean expressions is: "<< fa; cout << "\n"; cout << "\n"; return 0; }

Question 1 #include <iostream> using namespace std; int main() { char m=12; char n=24; char p=6; char q=3; char r=2; char s=4; char t=1; int d=12/6; //division int e=6-3; //subtract int a=6+3; //addition string tr= "true"; string fa= "false"; if ((m > p)&&(q > s)&&(r > t)) cout <<" The boolean expressions is: "<< tr; else cout <<" The boolean expressions is: "<< fa; cout << "\n"; cout << "\n"; if ((m > n*p) || (q*r < p) || (p > s+t)) cout <<" The boolean expressions is: "<<tr; else cout <<" The boolean expressions is: " <<fa; cout << "\n"; cout << "\n"; if ((d = r) && (e = r) || (a = 2*s)) cout <<" The boolean expressions is: "<< tr; else cout <<" The boolean expressions is: "<< fa; cout << "\n"; cout << "\n"; return 0; }

And I assume you've not used = in condition instead of ==

i don't know how to do it you give me teps