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Not all students wished to enter a university on their own😂

Not all students wished to enter a university on their own😂

fair enough, but once you're applying for a job and are in an interview you wish you would have paid attention. So try to do your assignments and learn, your future self will appreciate it.

can anyone let me know what's wrong with that? I am not getting expected answer

you missed acually reading integer numbers

you missed acually reading integer numbers

Write a program using while loop that ask the user about how many number he/she wants to enter. Your task is to take input those many number and calculate their sum. » #include <stdio.h> int main () { int n,i,sum = 0; scanf("%d",&n); i=1; while (i<=n) { sum +=i*10; ++i; } printf("%d\n",sum); return 0; }

you need to take all the numbers as input and then calculate their sum

#include <stdio.h> int main() { int n, i, sum = 0; printf("Enter a positive integer: "); scanf("%d", &n); i = 1; while (i <= n) { sum += i; ++i; } printf("Sum = %d", sum); return 0; }

I have tried that at the very begining. But it's not giving actual result

#include <stdio.h> int main() { int n, i, sum = 0; printf("Enter a positive integer: "); scanf("%d", &n); i = 1; while (i <= n) { sum += i; ++i; } printf("Sum = %d", sum); return 0; }

could you suggest c++ code analyzer for linux?

what is the usual approach?

ubuntu. should I add cppcheck to CMakefile?

apt install cppcheck

Then man cppcheck

why many people write code like this: while((*s++ = *t++) != '\0') ; isnt better to write this version? while((*s++ = *t++) != '\0');

That the semicolon is a line down?

That the semicolon is a line down?

yes

why many people write code like this: while((*s++ = *t++) != '\0') ; isnt better to write this version? while((*s++ = *t++) != '\0');

Hi, how do I list all files of an entire drive in a text file? I have been able to list files of only one directory at a time with WinAPIs. Can anyone suggest me something?

you have function for one directory to list all files. lets call it get_files(const string &path) this func should call get_files(dir_path) for all directories are found in the dir

could you suggest c++ code analyzer for linux?

#include <stdio.h> #include <string.h> #include <math.h> #include <float.h> int main() { char machine_a[4]; char machine_b[4]; char machine_c[4]; char extra_var; printf("enter the name for first machine.\n"); fgets(machine_a , 4, stdin); extra_var = getchar(); printf("enter the name for second machine\n"); fgets(machine_b , 4, stdin); extra_var = getchar(); printf("enter the name for third machine.\n"); fgets(machine_c , 4, stdin); extra_var = getchar(); float a = 0.0, b = 0.0, c = 0.0; float x; float total_production; float max_production = -1; float min_production=flt_max; char max_machine[4]; char min_machine[4]; printf("enter the 2 productions of machine %s:\n", machine_a); scanf("%f", &x); a = a + x; scanf("%f", &x); a = a + x; if(a > max_production) { max_production = a; strcpy(max_machine,machine_a); } if(a < min_production) { min_production = a; strcpy(min_machine , machine_a); } printf("enter the 2 productions of machine %s:\n", machine_b); scanf("%f", &x); b = b + x; scanf("%f", &x); b = b + x; if(b > max_production) { max_production = b; strcpy(max_machine , machine_b); } if(b < min_production) { min_production = b; strcpy(min_machine , machine_b); } printf("enter the 2 productions of machine %s:\n", machine_c); scanf("%f", &x); c = c + x; scanf("%f", &x); c = c + x; if(c > max_production) { max_production = c; strcpy(max_machine , machine_c); } if(c < min_production) { min_production = c; strcpy(min_machine , machine_c); } total_production = a + b + c; float avg_production = total_production / 3; printf("total production: %0.1f\n", total_production); printf("average production: %0.1f\n", avg_production); printf("machine with maximum production: %s\n", max_machine); printf("machine with minimum production: %s\n", min_machine); return 0; }

BRUH

Help me with c

that was incredibly specific.

Help me with c

Can we use void functions as int functions by just getting them to return a garbage value ? Will it effect the output ?

So if I do int display( int num ) { cout<< num ; return 0; } It won't compile ?

So if I do int display( int num ) { cout<< num ; return 0; } It won't compile ?

It will only return 0... where is the "void"?

there's always a first time

So if I do int display( int num ) { cout<< num ; return 0; } It won't compile ?

This would be preferred void display( int num ) { cout<< num ; return ; }