Drop a malicious library somewhere in ~ and throw LD_PRELOAD into .bashrc

You can write to .bashrc from within a flatpak sandbox running as non root

The only way to do that is some extrnal source, obviously. And it can be done without sudo , I agree. But I really don't think that you can inject anything into .bashrc without root permissions.

Windows checks if the malicious process actually has write access to the file and rejects any attempt to make links if the process doesn't have access

It checks the permission that's true, however is not so difficult to trick the system and gain write access to a file by links https://github.com/padovah4ck/CVE-2020-0683 https://offsec.almond.consulting/intro-to-file-operation-abuse-on-Windows.html https://nixhacker.com/understanding-and-exploiting-symbolic-link-in-windows/

I want to learn C/C++ can anyone help me please

Why do you need an old compiler version? You can use a newer version and targeting a previous version of the programming language.

/get

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hi guys I'm working on a project for my university its need register account. i design a table for that.but my teacher told me its should be standard.what table and field need for standard registration?

That doesn't look like C++. You're asking in a wrong group. Why can't you ask your teacher to explain it better?

C++ or batter say c+class And class can be set as a table

C++ or batter say c+class And class can be set as a table

Hey, c begginer, Can someone explain me why the function calling dosnt work? What do I need to do to call the function right? https://onlinegdb.com/BkwjeuHtP

This one does not make sense. int arr[SIZE]; ... ... for (int i = 0; i < arr; i++) This part i < arr, you compare an integer with memory address of the array.

Not possible

This one does not make sense. int arr[SIZE]; ... ... for (int i = 0; i < arr; i++) This part i < arr, you compare an integer with memory address of the array.

Calling a function in C is just like this. function_name(arg1, arg2, arg3); It is the same as you call scanf, printf, and something like that. They are all functions too. Simple example: int add(int a, int b) { return a + b; } int at the beginning of the function definition is the return type. add is the function name. int a is the first argument. int b is the second argument. Call function example: int x = 10; int y = 30; int result = add(x, y); printf("%d", result); // output 40

Yes, it is the group for the discussion. It is necessary to discuss it here because it is connected to the people here. Devs should be aware of operating systems clearly and myths need to be busted, imo. Nobody should have myths in mind regarding os, imo

there are only 6 lines in the .txt file, but without closing fptr in the child process, it could fork up to thousands of child process

c #include <stdlib.h> #include <stdio.h> #include <string.h> #include <sys/types.h> #include <unistd.h> int main (){ pid_t procid; int cnt = 0, // fork counter n_read; FILE *fptr = NULL; fptr = fopen("tmpfile.txt", "r"); char line_buffer[100]; while( (n_read = fscanf( fptr, "%s", line_buffer)) != EOF){ procid = fork(); if(procid == 0){ fclose( fptr ); // undefined behavior after removing this line exit(0); } cnt ++; } printf("%d forked\n", cnt); return 0; }

if i were to use repl.it, shall i invite or post? havent used it before

You ran the same executable both times

gcc (Ubuntu 7.5.0-3ubuntu1~18.04) 7.5.0 this is what i use

to my knowledge, it should be independent after fork, FILE* or fd, but it seems that it behaves as expected on your machine

to my knowledge, it should be independent after fork, FILE* or fd, but it seems that it behaves as expected on your machine

this is mentioned in APUE and UNP, after forking, there is a reference counter to the file, closing it will cause the counter to -1 and the file truely closes once it goes down to 0

yes, true; but on my machine, calling _Exit will result in expected output and _Exit does not do the cleaning process 😅😅